Chapter 9: Problem 85
A glimpse ahead to power series Use the Ratio Test to determine the values of \(x \geq 0\) for which each series converges. $$\sum_{k=1}^{\infty} \frac{x^{k}}{k^{2}}$$
Short Answer
Expert verified
The given series converges for values of x in the interval [0, 1).
Step by step solution
01
Identify the series and Ratio Test formula.
The given series is:
$$\sum_{k=1}^{\infty} \frac{x^{k}}{k^{2}}$$
We need to find the values of \(x \geq 0\) for which the series converges using the Ratio Test. The formula for the Ratio Test is:
$$\lim_{k \to \infty} \left |\frac{a_{k+1}}{a_k} \right |$$
02
Apply the Ratio Test formula on the given series.
We need to find the ratio of consecutive terms (\(\frac{a_{k+1}}{a_k}\)) in the series:
$$\frac{a_{k+1}}{a_k} = \frac{\frac{x^{k+1}}{(k+1)^2}}{\frac{x^k}{k^2}}$$
Simplify the expression:
$$\frac{a_{k+1}}{a_k} = \frac{x^{k+1}k^2}{x^{k}(k+1)^2}$$
03
Find the limit of the absolute value of the ratio.
Now, we need to find the limit of the absolute value of the ratio as \(k \to \infty\):
$$\lim_{k \to \infty} \left |\frac{x^{k+1}k^2}{x^{k}(k+1)^2} \right |$$
Simplify the expression:
$$\lim_{k \to \infty} \left |\frac{x k^2}{(k+1)^2} \right |$$
04
Evaluate the limit to determine convergence conditions.
Since \(x\) is independent of \(k\), we can take it out of the limit:
$$x \lim_{k \to \infty} \left |\frac{k^2}{(k+1)^2} \right |$$
As \(k \to \infty\), the limit converges to 1:
$$x \cdot 1 = x$$
For the series to converge, the limit has to be less than 1:
$$x < 1$$
Since we are given \(x \geq 0\), the interval of convergence is:
$$0 \leq x < 1$$
05
Conclusion
The series converges for \(0 \leq x < 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Series
A power series is an infinite series in the form of \( \sum_{k=0}^{\infty} a_k(x - c)^k \), where \( a_k \) are coefficients and \( x \) is a variable. The power series is centered around \( c \), which means if \( c = 0 \), the series is centered at zero.
In the given problem, we observe that the power series is \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \). This series doesn't follow the exact form of a traditional power series since the denominator includes \( k^2 \). However, it still demonstrates the structure because \( x^k \) indicates varying powers of \( x \).
In the given problem, we observe that the power series is \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \). This series doesn't follow the exact form of a traditional power series since the denominator includes \( k^2 \). However, it still demonstrates the structure because \( x^k \) indicates varying powers of \( x \).
- The role of \( x \) here is crucial as it dictates the series' behavior and convergence.
- These types of series frequently appear in calculus when representing functions as series, especially through Taylor and Maclaurin series.
Convergence
Convergence of a series indicates that as you add more terms in the sequence, the sum approaches a definite value. For series like the one we're examining, convergence is dependent on the value of \( x \).
- The Ratio Test is one of the standard methods used to determine convergence, specifically for series with non-negative terms.
- If the limit of the ratio of successive terms \( \left |\frac{a_{k+1}}{a_k} \right | \) is less than 1 as \( k \to \infty \), the series converges.
Limit Evaluation
Limit evaluation is crucial for using the Ratio Test in determining the convergence of a series. It involves simplifying and calculating the limit of the terms' ratio as \( k \to \infty \).
Applying the Ratio Test to the series \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \) required finding the limit of \( \frac{a_{k+1}}{a_k} \). Here's what that process looked like:
Applying the Ratio Test to the series \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \) required finding the limit of \( \frac{a_{k+1}}{a_k} \). Here's what that process looked like:
- First, find the expression for consecutive terms, which simplifies the ratio.
- Next, isolate terms involving \( x \) since they don't depend on \( k \), making computation of the limit with respect to \( k \) simpler.
- Finally, calculate the limit, where in our case, the expression simplified such that the limit was found to be \( x \).