/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Evaluate the series or state tha... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the series or state that it diverges. $$\sum_{k=1}^{\infty} \frac{(-2)^{k}}{3^{k+1}}$$

Short Answer

Expert verified
Answer: The sum of the given series is $-\frac{2}{15}$.

Step by step solution

01

Identify the first term and common ratio

To begin, we should identify the first term (a) and the common ratio (r) of the geometric series. In this case, the first term is when k=1, which is: $$ a = \frac{(-2)^{1}}{3^{1+1}} = \frac{-2}{9} $$ The common ratio (r) can be identified by dividing a consecutive term by its previous one, which is given by the expression: $$ r = \frac{(-2)^{k}}{3^{k+1}} \cdot \frac{3^{k}}{(-2)^{k-1}} = -\frac{2}{3} $$ #Step 2: Check if the series converges or diverges#
02

Check if the series converges or diverges

In order for a geometric series to converge, the common ratio r must be between -1 and 1. In this case, our common ratio is -2/3, which is indeed between -1 and 1. Thus, the series converges. #Step 3: Find the sum of the series#
03

Find the sum of the series

Since the series converges, we can use the formula for the sum of an infinite geometric series: $$ S = \frac{a}{1-r} $$ Plugging in our values for a and r, we find that: $$ S = \frac{-2/9}{1-(-\frac{2}{3})} = \frac{-2/9}{\frac{5}{3}} = \frac{-2}{9} \cdot \frac{3}{5} = -\frac{2}{15} $$ The sum of the given series is $$-\frac{2}{15}$$.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence of a Geometric Series
Understanding the convergence of a geometric series is crucial when analyzing whether a series will sum to a finite value. A geometric series is defined by each term being a constant multiple, known as the common ratio, of the previous term.

For such a series to converge—that is, to approach a specific value as we consider more and more terms—the absolute value of the common ratio, denoted as \(r\), must be less than 1. If \(|r| < 1\), the terms get smaller and smaller, allowing the series to settle to a particular sum.
  • Example: For \(r = -\frac{2}{3}\), since its absolute value \(|-\frac{2}{3}| = \frac{2}{3}\) is less than 1, the series converges.
  • This criterion means that as more terms are added, the overall series approaches an actual distinct value.
Thus, checking the common ratio is a vital step in determining the behavior of a series. If \(|r| \geq 1\), the series diverges, implying no finite sum exists.
Infinite Series
An infinite series is the sum of the terms of an infinite sequence of numbers. In mathematics, particularly in calculus, series that never end are depicted as follows: \(\sum_{k=1}^{\infty} a_k\), indicating we are summing terms starting from \(k=1\) to infinity.

Infinite series can be daunting, but understanding whether they converge (sum to a finite number) or diverge (grow without bound) is essential. Convergent infinite series might have sums that can be found using specific formulas, like for geometric series where \(|r| < 1\).
  • Geometric series: Often represented as \(a + ar + ar^2 + \ldots\)
  • If convergent, can be summed using: \(S = \frac{a}{1-r}\)
This formula efficiently provides a finite sum if the series converges. Understanding this concept helps demystify what happens when we add up an infinite number of terms.
Common Ratio in Geometric Series
In the realm of geometric series, the common ratio is a fundamental building block that determines the series' behavior. The common ratio, denoted as \(r\), is defined as the factor that each term is multiplied by to produce the subsequent term of the series.

Identifying the common ratio involves dividing any term by the preceding term. For example, given terms in a geometric series like \(a, ar, ar^2, \ldots\), the common ratio is calculated as \(r = \frac{ar}{a} = r\). With a known common ratio, we can predict how the series behaves as more terms are added.
  • If \(|r| < 1\), the series converges, approaching a specific sum.
  • If \(|r| \geq 1\), the series diverges, with terms failing to settle to a finite amount.
Understanding the role of the common ratio not only helps in determining convergence but also assists in calculating the sum of convergent geometric series.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The famous Fibonacci sequence was proposed by Leonardo Pisano, also known as Fibonacci, in about A.D. 1200 as a model for the growth of rabbit populations. It is given by the recurrence relation \(f_{n+1}=f_{n}+f_{n-1}\), for \(n=1,2,3, \ldots,\) where \(f_{0}=0, f_{1}=1 .\) Each term of the sequence is the sum of its two predecessors. a. Write out the first ten terms of the sequence. b. Is the sequence bounded? c. Estimate or determine \(\varphi=\lim _{n \rightarrow \infty} \frac{f_{n+1}}{f_{n}},\) the ratio of the successive terms of the sequence. Provide evidence that \(\varphi=(1+\sqrt{5}) / 2,\) a number known as the golden mean. d. Verify the remarkable result that $$f_{n}=\frac{1}{\sqrt{5}}\left(\varphi^{n}-(-1)^{n} \varphi^{-n}\right)$$

Determine how many terms of the following convergent series must be summed to be sure that the remainder is less than \(10^{-4} .\) Although you do not need it, the exact value of the series is given in each case. $$\sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{(2 k+1) !}$$

Given any infinite series \(\Sigma a_{k},\) let \(N(r)\) be the number of terms of the series that must be summed to guarantee that the remainder is less than \(10^{-r}\), where \(r\) is a positive integer. a. Graph the function \(N(r)\) for the three alternating \(p\) -series \(\sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{k^{p}},\) for \(p=1,2,\) and \(3 .\) Compare the three graphs and discuss what they mean about the rates of convergence of the three series. b. Carry out the procedure of part (a) for the series \(\sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{k !}\) and compare the rates of convergence of all four series.

It can be proved that if a series converges absolutely, then its terms may be summed in any order without changing the value of the series. However, if a series converges conditionally, then the value of the series depends on the order of summation. For example, the (conditionally convergent) alternating harmonic series has the value $$1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\dots=\ln 2.$$ Show that by rearranging the terms (so the sign pattern is \(++-\) ), $$1+\frac{1}{3}-\frac{1}{2}+\frac{1}{5}+\frac{1}{7}-\frac{1}{4}+\cdots=\frac{3}{2} \ln 2.$$

a. Consider the number 0.555555...., which can be viewed as the series \(5 \sum_{k=1}^{\infty} 10^{-k} .\) Evaluate the geometric series to obtain a rational value of \(0.555555 \ldots\) b. Consider the number \(0.54545454 \ldots,\) which can be represented by the series \(54 \sum_{k=1}^{\infty} 10^{-2 k} .\) Evaluate the geometric series to obtain a rational value of the number. c. Now generalize parts (a) and (b). Suppose you are given a number with a decimal expansion that repeats in cycles of length \(p,\) say, \(n_{1}, n_{2} \ldots \ldots, n_{p},\) where \(n_{1}, \ldots, n_{p}\) are integers between 0 and \(9 .\) Explain how to use geometric series to obtain a rational form of the number. d. Try the method of part (c) on the number \(0.123456789123456789 \ldots\) e. Prove that \(0 . \overline{9}=1\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.