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Write the terms \(a_{1}, a_{2}, a_{3},\) and \(a_{4}\) of the following sequences. If the sequence appears to converge, make a conjecture about its limit. If the sequence diverges, explain why. $$a_{n}=\frac{(-1)^{n}}{n} ; n=1,2,3, \dots$$

Short Answer

Expert verified
Answer: The sequence converges, as the terms get closer and closer to zero as n approaches infinity. We can make a conjecture that the limit of the sequence as \(n\) approaches infinity is equal to zero: \(\lim_{n\rightarrow \infty} \frac{(-1)^n}{n}=0\).

Step by step solution

01

Calculate \(a_1, a_2, a_3,\) and \(a_4\).

To find these terms, plug the values of n = 1, 2, 3, and 4 into the formula \(a_n = \frac{(-1)^n}{n}\): 1. When n = 1: \(a_1 = \frac{(-1)^1}{1} = -1\) 2. When n = 2: \(a_2 = \frac{(-1)^2}{2} =\frac{1}{2}\) 3. When n = 3: \(a_3 = \frac{(-1)^3}{3} = -\frac{1}{3}\) 4. When n = 4: \(a_4 = \frac{(-1)^4}{4} = \frac{1}{4}\) Thus, we get the terms \(a_1 = -1\), \(a_2 = \frac{1}{2}\), \(a_3 = -\frac{1}{3}\), and \(a_4 = \frac{1}{4}\).
02

Determine if the sequence converges or diverges.

Observe the terms of the sequence as n increases. It seems the sequence alternates in sign and gets closer to zero. The terms are getting smaller and approach zero: $$a_1 = -1$$ $$a_2 = \frac{1}{2}$$ $$a_3 = -\frac{1}{3}$$ $$a_4 = \frac{1}{4}$$ $$\vdots$$ $$a_n = \frac{(-1)^n}{n}$$ As n approaches infinity, the alternating sign given by \((-1)^n\) will continue, but the value \(\frac{1}{n}\) is decreasing and approaching zero.
03

Conjecture about the limit.

Since the terms in this sequence are getting closer and closer to zero as n increases, we can make a conjecture that the limit of the sequence as \(n\) approaches infinity is equal to zero: $$\lim_{n\rightarrow \infty} \frac{(-1)^n}{n}=0$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequence Divergence
In mathematics, when we talk about sequence divergence, we're referring to sequences that do not approach a specific value as the number of terms goes to infinity. Instead, divergent sequences can grow without bound, oscillate indefinitely, or follow no discernible pattern. In the context of the given problem, sequence divergence was considered to assess whether the sequence approaches a particular value, such as zero, or if it diverges away from this value.

To determine if a sequence diverges, you need to observe the behavior of its terms as you move further and further along the sequence. If the terms do not settle to a single number or stable pattern, you can conclude that the sequence diverges. However, the sequence here \(a_n = \frac{(-1)^n}{n}\) does not actually diverge. Instead, this sequence converges, as its terms become smaller in magnitude and approach zero. Nevertheless, when studying sequences, carefully examine the pattern of terms to decide if they genuinely converge to a limit or diverge.
Alternating Sequences
Alternating sequences are a fascinating type of sequence where the terms switch back and forth in sign or direction. The sequence from the exercise \(a_n = \frac{(-1)^n}{n}\) is a classic example of an alternating sequence because the sign of each term changes with each step – from positive to negative to positive, and so on.

The nature of alternating sequences means their visual representation typically zig-zags as it progresses. This style of sequence is instrumental when diving into complex patterns and behaviors of sequences and series in calculus and analysis. For this sequence, it is the \((-1)^n\) component that alternates signs, causing terms to switch between being positive and negative as \(n\) increases.
  • Positive if \(n\) is even
  • Negative if \(n\) is odd
Despite the alternating signs, if the terms themselves get smaller, as they do here, the sequence can still converge to a limit – in this case, zero.
Limit of a Sequence
The limit of a sequence is a fundamental concept in mathematics, particularly in calculus. It defines the value that the terms of a sequence approach as the number of terms goes to infinity. Identifying the limit involves understanding the behavior of a sequence over time or as the index number becomes very large.

For the sequence given by \(a_n = \frac{(-1)^n}{n}\), we observe that while the term signs change, the numerical component \(\frac{1}{n}\) gets closer to zero as \(n\) becomes very large. Thus, we conjecture that the limit of this alternating sequence is zero.
  • The terms \(a_1 = -1\), \(a_2 = \frac{1}{2}\), \(a_3 = -\frac{1}{3}\), \(a_4 = \frac{1}{4}\), ...
  • These terms keep getting closer to zero in magnitude as the index gets larger.
Ultimately, despite the flipping signs, the decreasing magnitude means the sequence converges to a single value: \(\lim_{n\rightarrow \infty} \frac{(-1)^n}{n}=0\). Understanding this concept helps in evaluating series, solving complex problems, and predicting behaviors in mathematical models.

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Most popular questions from this chapter

Determine whether the following series converge absolutely or conditionally, or diverge. $$\sum_{k=1}^{\infty}(-1)^{k} e^{-k}$$

Consider the following situations that generate a sequence. a. Write out the first five terms of the sequence. b. Find an explicit formula for the terms of the sequence. c. Find a recurrence relation that generates the sequence. d. Using a calculator or a graphing utility, estimate the limit of the sequence or state that it does not exist. The Consumer Price Index (the CPI is a measure of the U.S. cost of living) is given a base value of 100 in the year \(1984 .\) Assume the CPI has increased by an average of \(3 \%\) per year since \(1984 .\) Let \(c_{n}\) be the CPI \(n\) years after \(1984,\) where \(c_{0}=100.\)

Determine whether the following series converge absolutely or conditionally, or diverge. $$\sum_{k=1}^{\infty} \frac{\cos k}{k^{3}}$$

Given any infinite series \(\Sigma a_{k},\) let \(N(r)\) be the number of terms of the series that must be summed to guarantee that the remainder is less than \(10^{-r}\), where \(r\) is a positive integer. a. Graph the function \(N(r)\) for the three alternating \(p\) -series \(\sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{k^{p}},\) for \(p=1,2,\) and \(3 .\) Compare the three graphs and discuss what they mean about the rates of convergence of the three series. b. Carry out the procedure of part (a) for the series \(\sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{k !}\) and compare the rates of convergence of all four series.

Consider the geometric series $$S=\sum_{k=0}^{\infty} r^{k}$$ which has the value \(1 /(1-r)\) provided \(|r|<1 .\) Let \(S_{n}=\sum_{k=0}^{n-1} r^{k}=\frac{1-r^{n}}{1-r}\) be the sum of the first \(n\) terms. The remainder \(R_{n}\) is the error in approximating \(S\) by \(S_{n} .\) Show that $$R_{n}=\left|S-S_{n}\right|=\left|\frac{r^{n}}{1-r}\right|$$

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