/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Evaluate the geometric series or... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the geometric series or state that it diverges. $$\sum_{m=2}^{\infty} \frac{5}{2^{m}}$$

Short Answer

Expert verified
Answer: The sum of the infinite geometric series is $\frac{5}{2}$.

Step by step solution

01

Identify the common ratio

The common ratio for the given series can be identified as the quotient of two consecutive terms. In this case, the series is given by $$\frac{5}{2^2}, \frac{5}{2^3}, \frac{5}{2^4}, \ldots$$ So the common ratio (r) is: $$\frac{\frac{5}{2^3}}{\frac{5}{2^2}} = \frac{2^2}{2^3} = \frac{1}{2}$$
02

Check for convergence

A geometric series converges if its common ratio is less than 1 in absolute value: \(|r|<1\). In this case, the common ratio is $$|r| = \left|\frac{1}{2}\right| = \frac{1}{2}$$ Since the common ratio is less than 1 in absolute value, the series converges.
03

Use the formula for the sum of a geometric series

Since we have established that the given series converges, we can use the formula for the sum of an infinite geometric series: $$S = \frac{a}{1 - r}$$ where 'S' represents the sum of the series, 'a' is the first term, and 'r' is the common ratio.
04

Calculate the sum

Plug in the values of 'a' and 'r' into the formula. Here, the first term 'a' is the term with m = 2: $$\frac{5}{2^2} = \frac{5}{4}$$ And we found the common ratio 'r' to be \(\frac{1}{2}\). Now, we can find the sum 'S': $$S = \frac{\frac{5}{4}}{1 - \frac{1}{2}} = \frac{\frac{5}{4}}{\frac{1}{2}}$$ To simplify the expression, multiply the numerator and the denominator by 4 $$S = \frac{5}{2}$$ So the sum of the given geometric series is: $$\sum_{m=2}^{\infty} \frac{5}{2^{m}} = \frac{5}{2}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence
In the context of a geometric series, convergence refers to the behavior of the series as the number of terms grows indefinitely. For a geometric series to converge, the absolute value of the common ratio \(r\) must be less than 1, written as \(|r|<1\). This condition ensures that as we add more and more terms to the series, the series approaches a definite value rather than fluctuating towards infinity or diverging.

Understanding why convergence happens can be intuitive if you think of each term in a series becoming increasingly smaller. As terms diminish toward zero, the series stabilizes around a specific sum. In the provided exercise, the common ratio \(r\) was found to be \(\frac{1}{2}\), which is clearly less than 1, indicating that the series converges.
Common Ratio
The common ratio is a crucial element in geometric series. It's the factor by which we multiply any term of the series to get the next term. Determining the common ratio is the first step in analyzing a geometric series. In the given exercise, the series starts with terms like \(\frac{5}{2^2}, \frac{5}{2^3}, \frac{5}{2^4}, \ldots\) and the common ratio \(r\) is calculated as:
  • The ratio of the second term to the first: \(\frac{\frac{5}{2^3}}{\frac{5}{2^2}} = \frac{2^2}{2^3} = \frac{1}{2}\)
This constant multiplication factor \(\frac{1}{2}\) is what transforms each term into the next, creating a predictable series pattern.

Recognizing the common ratio helps establish whether a series converges or diverges, and is essential for calculating the sum of an infinite series.
Sum of Series
Once we know whether a geometric series converges, we can calculate its sum if it does. The sum of an infinite geometric series is given by the formula:
  • \(S = \frac{a}{1 - r}\)
Here, \(S\) represents the sum of the series, \(a\) is the first term, and \(r\) is the common ratio. This formula simplifies the complex task of summing infinite terms to a simple arithmetic expression.

In the original exercise, the first term \(a\) was \(\frac{5}{4}\) (or when \(m = 2\)), and the common ratio \(r\) was determined to be \(\frac{1}{2}\). Plugging these into the formula, the series sum is:
  • \(S = \frac{\frac{5}{4}}{1 - \frac{1}{2}} = \frac{\frac{5}{4}}{\frac{1}{2}} = \frac{5}{2}\)
Understanding the sum of series concept allows one to capture the overall value that an infinite series approaches, providing insight into the series' behavior.

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Most popular questions from this chapter

Determine whether the following series converge absolutely or conditionally, or diverge. $$\sum_{k=1}^{\infty} \frac{\cos k}{k^{3}}$$

Consider the following situations that generate a sequence. a. Write out the first five terms of the sequence. b. Find an explicit formula for the terms of the sequence. c. Find a recurrence relation that generates the sequence. d. Using a calculator or a graphing utility, estimate the limit of the sequence or state that it does not exist. When a biologist begins a study, a colony of prairie dogs has a population of \(250 .\) Regular measurements reveal that each month the prairie dog population increases by \(3 \%\) Let \(p_{n}\) be the population (rounded to whole numbers) at the end of the \(n\) th month, where the initial population is \(p_{0}=250\).

Consider the following situations that generate a sequence. a. Write out the first five terms of the sequence. b. Find an explicit formula for the terms of the sequence. c. Find a recurrence relation that generates the sequence. d. Using a calculator or a graphing utility, estimate the limit of the sequence or state that it does not exist. Jack took a \(200-\mathrm{mg}\) dose of a strong painkiller at midnight. Every hour, \(5 \%\) of the drug is washed out of his bloodstream. Let \(d_{n}\) be the amount of drug in Jack's blood \(n\) hours after the drug was taken, where \(d_{0}=200 \mathrm{mg}.\)

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A fishery manager knows that her fish population naturally increases at a rate of \(1.5 \%\) per month, while 80 fish are harvested each month. Let \(F_{n}\) be the fish population after the \(n\) th month, where \(F_{0}=4000\) fish. a. Write out the first five terms of the sequence \(\left\\{F_{n}\right\\}\). b. Find a recurrence relation that generates the sequence \(\left\\{F_{n}\right\\}\). c. Does the fish population decrease or increase in the long run? d. Determine whether the fish population decreases or increases in the long run if the initial population is 5500 fish. e. Determine the initial fish population \(F_{0}\) below which the population decreases.

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