/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Find the limit of the following ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the limit of the following sequences or determine that the limit does not exist. $$\left\\{\left(\frac{1}{n}\right)^{1 / n}\right\\}$$

Short Answer

Expert verified
Answer: The limit of the sequence is $$\frac{1}{e}$$ as n approaches infinity.

Step by step solution

01

Recognize the sequence and its general term

In this case, the sequence is $$\left\\{\left(\frac{1}{n}\right)^{1 / n}\right\\}$$, and the general term (nth term) of the sequence can be written as: $$a_n=\left(\frac{1}{n}\right)^{1 / n}$$
02

Analyze the behavior of the sequence as n approaches infinity

To find the limit of the given sequence, we need to find the value of the general term as n approaches infinity, or formally: $$\lim_{n\to\infty}\left(\frac{1}{n}\right)^{1/n}$$
03

Apply a known limit

To solve this limit, we can apply a known limit called the "Exponential Limit": $$\lim_{n\to\infty}\left(1+\frac{a}{n}\right)^n=e^a$$, where a is a constant. We can rewrite our original limit to resemble this known limit by making the following substitutions: let $$a=-n$$ and $$b=\frac{1}{n}$$. Therefore, our new limit becomes $$\lim_{n\to\infty}\left(1-\frac{1}{n}\right)^{-n}$$ Now, we can directly apply the Exponential Limit, which gives us: $$\lim_{n\to\infty}\left(1-\frac{1}{n}\right)^{-n}=e^{-1}=\frac{1}{e}$$
04

State the result

As a result, the limit of the given sequence is the value of the general term as n approaches infinity: $$\lim_{n\to\infty}\left(\frac{1}{n}\right)^{1/n}=\frac{1}{e}$$

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Most popular questions from this chapter

Consider the following sequences defined by a recurrence relation. Use a calculator, analytical methods, and/or graphing to make a conjecture about the value of the limit or determine that the limit does not exist. $$a_{n+1}=\frac{1}{2} a_{n}+2 ; a_{0}=5, n=0,1,2, \dots$$

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