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Evaluate the geometric series or state that it diverges. $$\sum_{k=0}^{\infty} \frac{2^{k}}{7^{k}}$$

Short Answer

Expert verified
Answer: The sum of the given infinite geometric series is \(\frac{7}{5}\).

Step by step solution

01

Identify the general term of the series

The given series is: $$\sum_{k=0}^{\infty} \frac{2^{k}}{7^{k}}$$ This is a geometric series with a general term of the form \(ar^k\), where k is the term index, a is the first term, and r is the common ratio. In this case, we have: $$a = \frac{2^0}{7^0} = 1$$ $$r = \frac{2}{7}$$ And the general term is: $$ar^k = (\frac{2}{7})^k$$
02

Determine if the series converges or diverges

For a geometric series to converge, the absolute value of the common ratio must be less than 1: $$|r| < 1$$ In our case, we have \(r = \frac{2}{7}\), and since \(|\frac{2}{7}| < 1\), the series converges.
03

Calculate the sum of the convergent geometric series

The formula for the sum (S) of an infinite convergent geometric series is: $$S = \frac{a}{1 - r}$$ Plugging in the values for a and r, we get: $$S = \frac{1}{1 - \frac{2}{7}}$$ Calculating the sum gives: $$S = \frac{1}{\frac{5}{7}} = \frac{7}{5}$$ The sum of the infinite geometric series is \(\frac{7}{5}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence of Series
In mathematics, understanding whether a series converges or diverges is crucial for determining if the sum of the series can be calculated. For geometric series, convergence depends largely on the common ratio, denoted as \( r \). Geometric series have terms that follow the form \( ar^k \), where \( k \) is a non-negative integer starting from 0.
To establish convergence, we check the absolute value of the common ratio:
  • If \( |r| < 1 \), the series converges. This means the infinite series approaches a fixed sum as the number of terms tends to infinity.
  • If \( |r| \geq 1 \), the series diverges, and no finite sum exists.
In our example, the common ratio \( r = \frac{2}{7} \) displays that \( |r| < 1 \), confirming convergence. Therefore, this geometric series will reach a specific sum despite having an infinite number of terms.
Common Ratio
The common ratio \( r \) in a geometric series is the factor by which each term progresses from the previous one. To find the common ratio, take the ratio of any term to its predecessor.
Mathematically, for a sequence \( a, ar, ar^2, ar^3, \ldots \), \( r \) is constant such that:
  • \( r = \frac{successive\ term}{previous\ term} \)
In the given problem, the sequence is \( 1, \frac{2}{7}, \left( \frac{2}{7} \right)^2, \left( \frac{2}{7} \right)^3, \ldots \)
Here, \( r = \frac{2}{7} \), a number significantly less than 1, ensuring each term is smaller than the last one. Recognizing and correctly determining the common ratio is essential for evaluating both convergence and the sum of the series.
Sum of an Infinite Series
Once a geometric series is confirmed to converge, the sum of all its infinite terms can be calculated using a formula. This is especially practical in series with a diminishing pattern where each subsequent term decreases significantly due to the nature of \( |r| < 1 \).
The formula for the sum \( S \) of an infinite geometric series is:
  • \( S = \frac{a}{1 - r} \)
where \( a \) is the first term and \( r \) is the common ratio.
In our exercise, with \( a = 1 \) and \( r = \frac{2}{7} \), the sum is computed as:
  • \( S = \frac{1}{1 - \frac{2}{7}} = \frac{1}{\frac{5}{7}} = \frac{7}{5} \)
Thus, the result \( \frac{7}{5} \) signifies the total sum to which the series converges. The formula helps quantify the infinite series into a single finite sum, illustrating the concept of convergence in practical terms.

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Most popular questions from this chapter

Consider the expression \(\sqrt{1+\sqrt{1+\sqrt{1+\sqrt{1+\cdots}}}},\) where the process continues indefinitely. a. Show that this expression can be built in steps using. the recurrence relation \(a_{0}=1, a_{n+1}=\sqrt{1+a_{n}},\) for \(n=0,1,2,3, \ldots .\) Explain why the value of the expression can be interpreted as \(\lim _{n \rightarrow \infty} a_{n}\). b. Evaluate the first five terms of the sequence \(\left\\{a_{n}\right\\}\). c. Estimate the limit of the sequence. Compare your estimate with \((1+\sqrt{5}) / 2,\) a number known as the golden mean. d. Assuming the limit exists, use the method of Example 5 to determine the limit exactly. e. Repeat the preceding analysis for the expression \(\sqrt{p+\sqrt{p+\sqrt{p+\sqrt{p+\cdots}}}}\) where \(p > 0 .\) Make a table showing the approximate value of this expression for various values of \(p .\) Does the expression seem to have a limit for all positive values of \(p ?\)

Pick two positive numbers \(a_{0}\) and \(b_{0}\) with \(a_{0}>b_{0}\) and write out the first few terms of the two sequences \(\left\\{a_{n}\right\\}\) and \(\left\\{b_{n}\right\\}:\) $$a_{n+1}=\frac{a_{n}+b_{n}}{2}, \quad b_{n+1}=\sqrt{a_{n} b_{n}}, \quad \text { for } n=0,1,2 \dots$$ (Recall that the arithmetic mean \(A=(p+q) / 2\) and the geometric mean \(G=\sqrt{p q}\) of two positive numbers \(p\) and \(q\) satisfy \(A \geq G\). a. Show that \(a_{n}>b_{n}\) for all \(n\). b. Show that \(\left\\{a_{n}\right\\}\) is a decreasing sequence and \(\left\\{b_{n}\right\\}\) is an increasing sequence. c. Conclude that \(\left\\{a_{n}\right\\}\) and \(\left\\{b_{n}\right\\}\) converge. d. Show that \(a_{n+1}-b_{n+1}<\left(a_{n}-b_{n}\right) / 2\) and conclude that \(\lim _{n \rightarrow \infty} a_{n}=\lim _{n \rightarrow \infty} b_{n} .\) The common value of these limits is called the arithmetic-geometric mean of \(a_{0}\) and \(b_{0},\) denoted \(\mathrm{AGM}\left(a_{0}, b_{0}\right)\). e. Estimate AGM(12,20). Estimate Gauss' constant \(1 / \mathrm{AGM}(1, \sqrt{2})\).

Convergence parameter Find the values of the parameter \(p>0\) for which the following series converge. $$\sum_{k=2}^{\infty} \frac{\ln k}{k^{p}}$$

Convergence parameter Find the values of the parameter \(p>0\) for which the following series converge. $$\sum_{k=1}^{\infty} \frac{1 \cdot 3 \cdot 5 \cdots(2 k-1)}{p^{k} k !}$$

Determine whether the following series converge absolutely or conditionally, or diverge. $$\sum_{k=1}^{\infty} \frac{(-1)^{k} k^{2}}{\sqrt{k^{6}+1}}$$

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