Chapter 7: Problem 8
$$\text { How would you evaluate } \int \sec ^{12} x \tan x d x ?$$
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 7: Problem 8
$$\text { How would you evaluate } \int \sec ^{12} x \tan x d x ?$$
These are the key concepts you need to understand to accurately answer the question.
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The following integrals require a preliminary step such as long division or a change of variables before using partial fractions. Evaluate these integrals. $$\int \frac{\sec \theta}{1+\sin \theta} d \theta$$
Find the area of the following regions. In each case, graph the relevant curves and show the region in question. The region bounded entirely by the curve \(y=\frac{x^{2}-4 x-4}{x^{2}-4 x-5}\) and the \(x\) -axis.
The Mercator map projection was proposed by the Flemish geographer Gerardus Mercator \((1512-1594) .\) The stretching of the Mercator map as a function of the latitude \(\theta\) is given by the function $$ G(\theta)=\int_{0}^{\theta} \sec x d x $$ Graph \(G,\) for \(0 \leq \theta<\pi / 2\)
The nucleus of an atom is positively charged because it consists of positively charged protons and uncharged neutrons. To bring a free proton toward a nucleus, a repulsive force \(F(r)=k q Q / r^{2}\) must be overcome, where \(q=1.6 \times 10^{-19} \mathrm{C}\) is the charge on the proton, \(k=9 \times 10^{9} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}^{2}, Q\) is the charge on the nucleus, and \(r\) is the distance between the center of the nucleus and the proton. Find the work required to bring a free proton (assumed to be a point mass) from a large distance \((r \rightarrow \infty)\) to the edge of a nucleus that has a charge \(Q=50 q\) and a radius of \(6 \times 10^{-11} \mathrm{m}.\)
\(A\) powerful tool in solving problems in engineering and physics is the Laplace transform. Given a function \(f(t),\) the Laplace transform is a new function \(F(s)\) defined by $$ F(s)=\int_{0}^{\infty} e^{-s t} f(t) d t $$ where we assume that s is a positive real number. For example, to find the Laplace transform of \(f(t)=e^{-t},\) the following improper integral is evaluated: $$ F(s)=\int_{0}^{\infty} e^{-s t} e^{-t} d t=\int_{0}^{\infty} e^{-(s+1) t} d t=\frac{1}{s+1} $$ Verify the following Laplace transforms, where a is a real number. $$f(t)=1 \longrightarrow F(s)=\frac{1}{s}$$
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