/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 Use the reduction formulas in a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the reduction formulas in a table of integrals to evaluate the following integrals. $$\int \sec ^{4} 4 x d x$$

Short Answer

Expert verified
Question: Evaluate the integral $$\int \sec^4(4x) dx$$. Answer: The integral of the given function is $$\int \sec^4(4x) dx = \frac{\sec^2(4x) \tan(4x)}{3} + \frac{1}{2}\tan(4x) + C$$, where C is the constant of integration.

Step by step solution

01

Identify the reduction formula for even powers of secant function

The reduction formula for even powers of secant function is given by the formula: $$\int \sec^n(x) dx = \frac{1}{n-1} \sec^{n-2}(x) \tan(x) + \frac{n-2}{n-1}\int \sec^{n-2}(x) dx$$ Where n is an even integer.
02

Apply the reduction formula to the given integral

We are given the integral: $$\int \sec^4(4x) dx$$ Here, we have \(n=4\), and the function inside the secant is \(4x\). Applying the reduction formula, we get: $$\int \sec^4(4x) dx = \frac{1}{4-1} \sec^2(4x) \tan(4x) + \frac{4-2}{4-1}\int \sec^2(4x) dx$$ Simplify the expression: $$\int \sec^4(4x) dx = \frac{\sec^2(4x) \tan(4x)}{3} + \frac{2}{3}\int \sec^2(4x) dx$$
03

Evaluate the remaining integral

Now, we need to evaluate the integral of \(\sec^2(4x)\). This integral is a standard one and can be easily recognized as the derivative of the tangent function. Thus, we have: $$\int \sec^2(4x) dx = \tan(4x) + C$$ However, since we have a chain rule in action (\(u=4x\)), we need to apply the substitution rule and divide by the derivative of \(u\), which is \(4\): $$\int \sec^2(4x) dx = \frac{1}{4}(\tan(4x) + C)$$
04

Substitute the result back into the original expression

Now, substitute the result of the remaining integral back into the expression obtained in Step 2: $$\int \sec^4(4x) dx = \frac{\sec^2(4x) \tan(4x)}{3} + \frac{2}{3}\left(\frac{1}{4}(\tan(4x) + C)\right)$$ Simplify the expression: $$\int \sec^4(4x) dx = \frac{\sec^2(4x) \tan(4x)}{3} + \frac{1}{2}\tan(4x) + \frac{2}{12}C$$
05

Write down the final answer

The integral of the given function is: $$\int \sec^4(4x) dx = \frac{\sec^2(4x) \tan(4x)}{3} + \frac{1}{2}\tan(4x) + C$$ Where C is the constant of integration.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration
Integration is a fundamental concept in calculus used to find areas under curves and sums of continuous functions over intervals. It is essentially the reverse process of differentiation.
The integral of a function gives us the accumulation of quantities and can be deemed as a measure of total change.
Integrals can be classified mainly into two types:
  • Definite integrals – Used when computing areas under the curve from one point to another.
  • Indefinite integrals – Express the general form of the antiderivative, without specific bounds.
In our exercise, we are focused on indefinite integrals related to trigonometric functions.
By using specific techniques like reduction formulas, we can handle complex integrals involving powers of trigonometric functions like the secant function.
Trigonometric Integrals
Trigonometric integrals involve functions of angles or ratios of lengths in right-angled triangles. These integrals often include sine, cosine, tangent, and secant functions.
Trigonometric integrals are crucial in various fields such as physics and engineering. Reduction formulas help simplify trigonometric integrals, especially when dealing with powers of these functions.
This can reduce the complexity significantly when integrating powers higher than two.
In the given problem, we work with \(\sec^4(4x)\).
Utilizing the reduction formula, we transform this into a sum of simpler integrals that are easier to solve. This method saves time and simplifies complex expressions in calculus.
Secant Function
The secant function, denoted as sec(x), is one of the primary trigonometric functions. It is the reciprocal of the cosine function and has significant roles when dealing with integrals of trigonometric expressions.
The properties of the secant function often allow it to appear in problems involving integration because of its distinct behavior.Key properties include:
  • Secant function is defined as \( \sec(x) = \frac{1}{\cos(x)} \).
  • Its graph has vertical asymptotes at points where cosine is zero.
  • It has a period of \(2\pi\).
When using the reduction formula for integrals, the secant function's powers can be reduced systematically, making integration more approachable.
Chain Rule
The chain rule is a fundamental differentiation rule used to compute the derivative of functions composed of other functions. When an integral involves a composite function, the chain rule helps express it in a solvable form.For example, in the given integral \( \int \sec^2(4x) dx \), the chain rule applies because the function inside the trigonometric expression is \(4x\).
When differentiating or integrating a composite function f(g(x)), the derivative is found by multiplying the derivative of f with respect to g by the derivative of g with respect to x.Steps involved include:
  • Identify the inner function, in this case, \(u = 4x\).
  • Integrate using known identities, then adjust for the derivative of the inner function, \(\frac{1}{4}\), which corrects for the change of variable technique.
Using the chain rule correctly simplifies the integration process and ensures accurate results, as seen in how we adjusted the integral of \[ \int \sec^2(4x) dx \] in the problem.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Many methods needed Show that \(\int_{0}^{\infty} \frac{\sqrt{x} \ln x}{(1+x)^{2}} d x=\pi\) in the following steps. a. Integrate by parts with \(u=\sqrt{x} \ln x.\) b. Change variables by letting \(y=1 / x.\) c. Show that \(\int_{0}^{1} \frac{\ln x}{\sqrt{x}(1+x)} d x=-\int_{1}^{\infty} \frac{\ln x}{\sqrt{x}(1+x)} d x\) and conclude that \(\int_{0}^{\infty} \frac{\ln x}{\sqrt{x}(1+x)} d x=0.\) d. Evaluate the remaining integral using the change of variables \(z=\sqrt{x}\) (Source: Mathematics Magazine 59, No. 1 (February 1986): 49).

The cycloid is the curve traced by a point on the rim of a rolling wheel. Imagine a wire shaped like an inverted cycloid (see figure). A bead sliding down this wire without friction has some remarkable properties. Among all wire shapes, the cycloid is the shape that produces the fastest descent time. It can be shown that the descent time between any two points \(0 \leq a \leq b \leq \pi\) on the curve is $$\text { descent time }=\int_{a}^{b} \sqrt{\frac{1-\cos t}{g(\cos a-\cos t)}} d t$$ where \(g\) is the acceleration due to gravity, \(t=0\) corresponds to the top of the wire, and \(t=\pi\) corresponds to the lowest point on the wire. a. Find the descent time on the interval \([a, b]\) by making the substitution \(u=\cos t\) b. Show that when \(b=\pi\), the descent time is the same for all values of \(a ;\) that is, the descent time to the bottom of the wire is the same for all starting points.

Evaluate the following integrals or state that they diverge. $$\int_{0}^{\pi / 2} \sec \theta d \theta$$

\(A\) powerful tool in solving problems in engineering and physics is the Laplace transform. Given a function \(f(t),\) the Laplace transform is a new function \(F(s)\) defined by $$ F(s)=\int_{0}^{\infty} e^{-s t} f(t) d t $$ where we assume that s is a positive real number. For example, to find the Laplace transform of \(f(t)=e^{-t},\) the following improper integral is evaluated: $$ F(s)=\int_{0}^{\infty} e^{-s t} e^{-t} d t=\int_{0}^{\infty} e^{-(s+1) t} d t=\frac{1}{s+1} $$ Verify the following Laplace transforms, where a is a real number. $$f(t)=t \longrightarrow F(s)=\frac{1}{s^{2}}$$

The nucleus of an atom is positively charged because it consists of positively charged protons and uncharged neutrons. To bring a free proton toward a nucleus, a repulsive force \(F(r)=k q Q / r^{2}\) must be overcome, where \(q=1.6 \times 10^{-19} \mathrm{C}\) is the charge on the proton, \(k=9 \times 10^{9} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}^{2}, Q\) is the charge on the nucleus, and \(r\) is the distance between the center of the nucleus and the proton. Find the work required to bring a free proton (assumed to be a point mass) from a large distance \((r \rightarrow \infty)\) to the edge of a nucleus that has a charge \(Q=50 q\) and a radius of \(6 \times 10^{-11} \mathrm{m}.\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.