/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 A standard pendulum of length \(... [FREE SOLUTION] | 91Ó°ÊÓ

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A standard pendulum of length \(L\) swinging under only the influence of gravity (no resistance) has a period of $$T=\frac{4}{\omega} \int_{0}^{\pi / 2} \frac{d \varphi}{\sqrt{1-k^{2} \sin ^{2} \varphi}}$$ where \(\omega^{2}=g / L, k^{2}=\sin ^{2}\left(\theta_{0} / 2\right), g \approx 9.8 \mathrm{m} / \mathrm{s}^{2}\) is the acceleration due to gravity, and \(\theta_{0}\) is the initial angle from which the pendulum is released (in radians). Use numerical integration to approximate the period of a pendulum with \(L=1 \mathrm{m}\) that is released from an angle of \(\theta_{0}=\pi / 4\) rad.

Short Answer

Expert verified
Question: Approximate the period of a pendulum with a length of 1 meter released from an angle of π/4 radians using numerical integration. Answer: The period of the pendulum is approximately T = (4/3.13)I, where I is the result of the numerical integration of the integral $$\int_{0}^{\pi / 2}\frac{d \varphi}{\sqrt{1-0.146 \sin ^{2} \varphi}}$$ using a method like Simpson's rule.

Step by step solution

01

Identify the integral and variables

We are given the integral $$\int_{0}^{\pi / 2}\frac{d \varphi}{\sqrt{1-k^{2} \sin ^{2} \varphi}}$$ and the value of the variables \(L=1 \mathrm{m}\), \(\theta_{0}=\pi / 4\), and \(g \approx 9.8 \mathrm{m} / \mathrm{s}^{2}\).
02

Compute the values of \(\omega\) and \(k^{2}\)

Using the given formulas, we can compute the values of \(\omega\) and \(k^{2}\). 1. \(\omega^{2}=\frac{g}{L}\Rightarrow \omega=\sqrt{\frac{9.8}{1}}=3.13\) (approximately) 2. \(k^{2}=\sin^{2}\left(\frac{\theta_{0}}{2}\right)\Rightarrow k^{2}=\sin^{2}\left(\frac{\pi}{8}\right) =0.146\) (approximately)
03

Use numerical integration to evaluate the integral

We will use a numerical integration method (e.g., trapezoidal rule, Simpson's rule) to evaluate the following integral:$$\int_{0}^{\pi / 2}{\frac{d \varphi}{\sqrt{1-0.146 \sin ^{2} \varphi}}}$$ Let's use Simpson's rule with \(n=1000\) subdivisions of the interval \([0, \pi/2]\). Divide the interval into equally spaced subintervals, compute the Simpson's rule approximation, and let the result be denoted by \(I\).
04

Compute the period using the integral result

Now that we have the result for \(I\), we can use the formula for the period of the pendulum:$$T=\frac{4}{\omega}I$$ Substitute the values for \(\omega\) and \(I\) to get:$$T=\frac{4}{3.13}I$$ Then, calculate the numerical value of \(T\) to obtain the period of the pendulum. The final result approximates the period of a pendulum with \(L=1\,\text{m}\) released from an angle of \(\theta_{0}=\frac{\pi}{4}\) radians using numerical integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pendulum Period
A pendulum is a weight suspended from a pivot so that it can swing freely. The time taken for one complete cycle of a swing is known as the period of the pendulum. The period of a standard pendulum depends on the length of the pendulum and the initial angle from which it is released. In this exercise, the length of the pendulum is 1 meter. To determine the period, we use a formula that involves an integral:\[T=\frac{4}{\omega} \int_{0}^{\pi / 2} \frac{d \varphi}{\sqrt{1-k^{2} \sin^{2} \varphi}}\]
Here, \(\omega^{2}=\frac{g}{L}\) with \(g\) being the gravitational acceleration, approximately 9.8 m/s². Meanwhile, \(k^{2}=\sin^{2}(\theta_{0}/2)\) where \(\theta_{0}\) is the initial release angle. In this specific case, the pendulum is released from \(\theta_{0} = \pi/4\) radians. After computing the necessary values for \(\omega\) and \(k^2\), the next step is evaluating the integral using numerical integration methods to approximate the pendulum's period.
Simpson's Rule
Simpson's Rule is a frequently used method for numerical integration, which is particularly effective when dealing with integrals of functions that are smooth over the interval of interest. This rule provides an approximation to the integral by using parabolic segments to approximate the curve. The method is expressed as:\[\int_{a}^{b} f(x) \, dx \approx \frac{\Delta x}{3} \left( f(x_0) + 4f(x_1) + 2f(x_2) + \cdots + 4f(x_{n-1}) + f(x_n) \right)\]
Where \(n\) must be an even number. For maximum accuracy, it is essential to divide the interval into a large number of subintervals. In our pendulum problem, this rule is applied with 1000 subdivisions for the interval \([0, \pi/2]\). This ensures a precise approximated value \(I\) for the integral \(\int_{0}^{\pi / 2} \frac{d \varphi}{\sqrt{1-0.146 \sin^2 \varphi}}\). This approximation is pivotal in determining the pendulum period after multiplying by \(\frac{4}{\omega}\).
Trapezoidal Rule
The Trapezoidal Rule is another method of numerical integration used to approximate the integral of a function. This method works by dividing the area under the curve into trapezoids rather than rectangles, hence its name. The formula for the Trapezoidal Rule is:\[\int_{a}^{b} f(x) \, dx \approx \frac{\Delta x}{2} \left( f(x_0) + 2f(x_1) + 2f(x_2) + \cdots + 2f(x_{n-1}) + f(x_n) \right)\]
Where \( \Delta x = \frac{b-a}{n}\) is the width of each segment. Though not as precise as Simpson's Rule for the same number of subdivisions, the Trapezoidal Rule is simpler and can still provide acceptable approximations. In applications like estimating the period of a pendulum, it offers a straightforward alternative to evaluate integrals should computational resources or simplicity be a priority. Utilizing the Trapezoidal Rule requires thoughtful application to balance error margins and computational efficiency effectively.

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Most popular questions from this chapter

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