/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Evaluate the following integrals... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following integrals or state that they diverge. $$\int_{1}^{2} \frac{1}{\sqrt{x-1}} d x$$

Short Answer

Expert verified
Answer: The integral converges and its value is 1.

Step by step solution

01

Identify the substitution

Let’s use the substitution \(u = \sqrt{x-1}\). This will simplify the integration process for the given function.
02

Find dx in terms of du

Differentiate both sides of the substitution equation with respect to \(x\) to find the relationship between \(dx\) and \(du\). $$\frac{d u}{d x} = \frac{1}{2}(x-1)^{-1/2}$$ Now, solve for \(dx\) in terms of \(du\): $$dx = 2(u)^2 \ du$$
03

Change the limits of integration

Replace the bounds of integration in terms of \(u\). When \(x=1\), \(u = \sqrt{1-1} = 0\) When \(x=2\), \(u = \sqrt{2-1} = 1\) So, the new limits of integration are from \(u=0\) to \(u=1\).
04

Substitute and evaluate the integral

Substitute the expression for \(u\) and \(dx\) into the original integral and evaluate: $$\int_{1}^{2} \frac{1}{\sqrt{x-1}} d x = \int_{0}^{1} \frac{1}{u} \cdot 2(u)^2 \ du$$ Simplify the integrand and calculate the integral: $$\int_{0}^{1} 2u \ du = u^2 \Big\rvert_{0}^{1} = (1)^2 - (0)^2 = 1$$ Thus, the integral converges, and its value is: $$\int_{1}^{2} \frac{1}{\sqrt{x-1}} d x = 1$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integrals
Definite integrals are a fundamental concept in integral calculus that calculate the net area under a curve between two specified points. This calculation not only provides the numerical result but also helps us understand the behavior of the function over an interval. In our exercise, we encounter the definite integral \[\int_{1}^{2} \frac{1}{\sqrt{x-1}} \, dx\]Here, the limits of integration are 1 and 2. By resolving this integral, we establish the finite area under the curve of the function \(\frac{1}{\sqrt{x-1}}\) between these two points. Definite integrals are typically solved by applying integration techniques, of which substitution is commonly used, as seen in this exercise.By changing variables or transforming the integrand, we can simplify the integration process, making it manageable and arriving at a meaningful result. It's important to note that definite integrals can also indicate whether a solution converges, signifying a finite result, or diverges, which means no finite solution exists.
Integration by Substitution
Integration by substitution is a powerful technique to simplify complex integrals by changing variables. This method is somewhat analogous to the chain rule in differentiation.

Choosing the Right Substitution

The key to a successful substitution lies in choosing an expression that simplifies the integrand. In our exercise, the substitution \(u = \sqrt{x-1}\) was carefully selected because it directly addresses the complexity of \(\sqrt{x-1}\), transforming it into a more straightforward linear term \(u\).

Steps to Implement Substitution

  • Selecting the substitution: Start by identifying a part of the integrand that can be replaced with a simpler variable, typically based on its derivative being present elsewhere in the integrand.
  • Expressing new variables: Differentiate the substitution equation to express the original variables in terms of the new ones.
  • Adjusting limits of integration: So important! Ensure new limits match your substitution by converting original bounds into terms of the new variable.
  • Solve the simplified integral: Evaluate the new integrand, now easier to integrate.
Through these steps, substitution effortlessly untangles complex integrals into simpler tasks.
Convergence of Integrals
Understanding the convergence of integrals is crucial in identifying whether a given integral has a finite solution. This is particularly pertinent when dealing with definite integrals involving improper limits or discontinuities in the integrand.
In our exercise, we needed to determine if the integral would converge to a definite value. Convergence occurs if the integration results in a bounded area under the curve, providing a finite number as the solution.

Testing for Convergence

To test convergence, we must consider:
  • Bounded limits of integration: Ensure the integral spans a finite range.
  • Behavior at bounds: Particularly near any points of discontinuity, assess if the result stays finite.
For our specific problem,\(\int_{1}^{2} \frac{1}{\sqrt{x-1}} \, dx\),having evaluated the integral and arriving at the answer 1, confirms that the integral converges, since this denotes a bounded and finite area under the curve within the specified limits.
Integration Techniques
When tackling integrals, especially more complex ones involving roots or variables raised to powers, various integration techniques come into play. Mastery of these techniques provides tools for addressing nearly any integral challenge posed.

Key Techniques Explored

  • Substitution: As we've experienced, changing the variable to simplify the problem is often the first step. Specifically useful when facing nested functions.
  • Partial Fraction Decomposition: This is useful when integrating rational functions, breaking them into simpler fractions.
  • Integration by Parts: Often used when products of different functions are involved, akin to the product rule in differentiation.
Each of these methods can be strategically applied based on the given function's structure, simplifying the integration process significantly.
In our exercise, substitution was successfully employed, turning a potentially difficult problem into a straightforward calculation. Exploring these techniques, digging deeper into their applications, reinforces the capacity to solve integrals with confidence and competence.

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Most popular questions from this chapter

Let \(a>0\) and let \(R\) be the region bounded by the graph of \(y=e^{-a x}\) and the \(x\) -axis on the interval \([b, \infty).\) a. Find \(A(a, b),\) the area of \(R\) as a function of \(a\) and \(b\) b. Find the relationship \(b=g(a)\) such that \(A(a, b)=2\) c. What is the minimum value of \(b\) (call it \(b^{*}\) ) such that when \(b>b^{*}, A(a, b)=2\) for some value of \(a>0 ?\)

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