/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Evaluate the following integrals... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following integrals. $$\int e^{x} \cos x d x$$

Short Answer

Expert verified
Question: Evaluate the integral \(\int e^x \cos x dx\). Answer: \(\int e^x \cos x dx = \frac{1}{2}e^x(\sin x + \cos x) + C\)

Step by step solution

01

Differentiate u to find du

We have \(u = e^x\). Differentiating with respect to x, we get: $$du = e^x dx$$
02

Integrate dv to find v

We have \(dv =\cos x dx\). Integrating with respect to x, we get: $$v = \int \cos x dx = \sin x$$
03

Apply the integration by parts formula

Using the integration by parts formula \(\int u dv = uv - \int v du\), we get: $$\int e^x \cos x dx = e^x \sin x - \int e^x \sin x dx$$ Now, we still have another integral \(\int e^x \sin x dx\) to evaluate. Let's use integration by parts again. This time, let's choose: $$u = e^x$$ $$dv = \sin x dx$$
04

Differentiate u to find du

We have \(u = e^x\). Differentiating with respect to x, we get: $$du = e^x dx$$
05

Integrate dv to find v

We have \(dv = \sin x dx\). Integrating with respect to x, we get: $$v = \int \sin x dx = -\cos x$$
06

Apply the integration by parts formula again

Using the integration by parts formula \(\int u dv = uv - \int v du\), we get: $$\int e^x \sin x dx = -e^x \cos x - \int -e^x \cos x dx$$ Now rewriting our original expression with this new result: $$\int e^x \cos x dx = e^x \sin x - (-e^x \cos x + \int e^x \cos x dx)$$ We still have an integral of \(\int e^x \cos x dx\) in our expression. To solve for it, let's move it to the other side and simplify: $$2\int e^x \cos x dx = e^x \sin x + e^x \cos x$$ Now divide both sides by 2: $$\int e^x \cos x dx = \frac{1}{2}e^x(\sin x + \cos x) + C$$ Finally, we have found the integral: $$\int e^x \cos x dx = \frac{1}{2}e^x(\sin x + \cos x) + C$$

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