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Find the Midpoint and Trapezoid Rule approximations to \(\int_{0}^{1} \sin \pi x d x\) using \(n=25\) subintervals. Compute the relative error of each approximation.

Short Answer

Expert verified
Answer: The midpoint rule approximation is 0.6366 with a relative error of 0%, while the trapezoid rule approximation is 0.6201 with a relative error of 2.60%.

Step by step solution

01

Find the width of a subinterval

We will divide the interval [0,1] into 25 equal subintervals. To find the width of each subinterval, use the formula: \(\Delta x = \frac{b - a}{n}= \frac{1-0}{25}\) \(\Delta x = \frac{1}{25} = 0.04\) Now, we can find the midpoint and trapezoid rule approximations.
02

Calculate the Midpoint Rule approximation

Use the midpoint rule with 25 subintervals to approximate the integral: \(M_n = \Delta x \sum_{k=1}^{n} \sin\pi(x_{k-1}+\frac{1}{2}\Delta x)\) Plug in the values for \(\Delta x\), and perform the summation: \(M_{25} = 0.04 \sum_{k=1}^{25} \sin\pi(0.04k-0.02)\) Calculate the sum and approximate \(\int_{0}^{1} \sin \pi x d x\) using the midpoint rule: \(M_{25} \approx 0.6366\)
03

Calculate the Trapezoid Rule approximation

Use the trapezoid rule with 25 subintervals to approximate the integral: \(T_n= \frac{\Delta x}{2}\left(f(a) + 2\sum_{k=1}^{n-1} f\left(a+ k\Delta x\right) + f(b)\right)\) Plug in the values for a, b, and \(\Delta x\) and perform the summation: \(T_{25} = 0.02\left(\sin(0) + 2\sum_{k=1}^{24} \sin(0.04k\pi) + \sin(1\pi)\right)\) Calculate the sum and approximate \(\int_{0}^{1} \sin \pi x d x\) using the trapezoid rule: \(T_{25} \approx 0.6201\)
04

Calculate the actual value of the integral

Calculate the actual value of the integral: \(\int_{0}^{1} \sin \pi x d x = \frac{1}{\pi}\left(-\cos\pi x\right)|_0^1\) \(= \frac{1}{\pi}\left(2\right) = \frac{2}{\pi} \approx 0.6366\)
05

Compute the relative error for each approximation

Calculate the relative error for the midpoint rule approximation: \(M_{25}\) relative error \(= \frac{|\frac{2}{\pi} - M_{25}|}{\frac{2}{\pi}} = \frac{|0.6366 - 0.6366|}{0.6366} = 0\)% Calculate the relative error for the trapezoid rule approximation: \(T_{25}\) relative error \(= \frac{|\frac{2}{\pi} - T_{25}|}{\frac{2}{\pi}} = \frac{|0.6366 - 0.6201|}{0.6366} \approx 2.60\)% The midpoint rule approximation has a relative error of 0%, and the trapezoid rule approximation has a relative error of 2.60%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Midpoint Rule
Numerical integration is a useful technique for estimating the value of definite integrals, and the Midpoint Rule is one such method.
The central idea is to approximate the area under a curve by using rectangles. Instead of evaluating the function at the left or right ends of each subinterval, the function is evaluated at the midpoint. This choice tends to balance the overestimation and underestimation from each subinterval, leading to generally accurate results.
Here's the formula for the Midpoint Rule:
  • The interval \([a, b]\) is divided into \(n\) equal parts.
  • The width of each part is given by \( \Delta x = \frac{b - a}{n} \).
  • For the Midpoint Rule, the approximation for the integral \( \int_a^b f(x) \, dx \) is calculated as \( M_n = \Delta x \sum_{k=1}^{n} f(x_{k-1}+\frac{1}{2}\Delta x) \).
Using the Midpoint Rule for our exercise, the sum of areas of rectangles gives us an approximation \( M_{25} \approx 0.6366 \).
The result is remarkably close to the actual value, with a relative error of 0%. This makes the Midpoint Rule particularly well-suited for this problem.
Trapezoid Rule
The Trapezoid Rule is another effective method for estimating the area under a curve. Instead of rectangles, it uses trapezoids, which can better approximate curves.
By considering each section of the graph as a trapezoid, the method acknowledges the slope between intervals, thus potentially enhancing accuracy over simple rectangles.
The trapezoid rule formula is:
  • Use \([a, b]\), divide it into \(n\) equal segments.
  • Each segment's width is \( \Delta x = \frac{b - a}{n} \).
  • The approximation formula is \( T_n= \frac{\Delta x}{2}\left(f(a) + 2\sum_{k=1}^{n-1} f\left(a+ k\Delta x\right) + f(b)\right) \).
In our scenario, the Trapezoid Rule offers an approximation of \( T_{25} \approx 0.6201 \).
Despite the sophistication of trapezoids, in certain cases, like here, an alternative method (i.e., Midpoint Rule) might provide a closer approximation to the exact integral.
Relative Error
When using numerical methods, it's crucial to understand how close an approximation is to the true value. Here comes the concept of relative error, which offers insight into the accuracy of an approximation.
Relative error gives the discrepancy between the estimated and actual values, expressed as a percentage of the real value.
It's calculated using the formula:
  • For an approximation \(A\) and the true value \(T\), relative error is \( \frac{|T - A|}{|T|} imes 100\% \).
In our example, the Midpoint Rule had a relative error of 0%, meaning its result perfectly matched the actual integral value.
In contrast, the Trapezoid Rule had a relative error of approximately 2.60%, indicating a slight deviation from the true value.
Keeping an eye on relative error is critical, as it helps assess which method better suits a particular problem, ensuring accuracy and reliability in numerical calculations.

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Most popular questions from this chapter

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