/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Evaluate the following integrals... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following integrals. $$\int \frac{e^{x}}{e^{x}+1} d x$$

Short Answer

Expert verified
Question: Evaluate the integral \(\int \frac{e^x}{e^x + 1} dx\). Answer: \(\int \frac{e^x}{e^x + 1} dx = \ln |e^x + 1| + C\)

Step by step solution

01

Identify the main function and its derivative

In the given integrand, \(\frac{e^x}{e^x + 1}\), the main function is \(u = e^x + 1\). Its derivative is \(du = e^x dx\).
02

Perform the substitution

Substitute \(u = e^x + 1\) and \(du = e^x dx\) in the integral: $$\int \frac{e^x}{e^x + 1} dx = \int \frac{1}{u} du$$
03

Integrate with respect to u

Now, we need to integrate the simplified integrand with respect to \(u\): $$\int \frac{1}{u} du = \ln |u| + C$$
04

Replace u with the original function

Finally, we will replace \(u\) with the original function (\(u = e^x + 1\)) to get the antiderivative in terms of \(x\): $$\ln|u| + C = \ln |e^x + 1| + C$$ Thus, the result of the integration is: $$\int \frac{e^x}{e^x + 1} dx = \ln |e^x + 1| + C$$

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