/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Evaluate the following integrals... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following integrals. $$\int \frac{d x}{\left(16-x^{2}\right)^{1 / 2}}$$

Short Answer

Expert verified
Solution: The integral is equal to \(\arcsin\left(\frac{x}{4}\right) + C\).

Step by step solution

01

Identify the constant a

In the given integral, we can identify that the constant \(a^2 = 16\). Taking the square root, we get \(a = 4\).
02

Apply the arcsin identity

Using the identity mentioned in the analysis section, we have: $$\int \frac{1}{\sqrt{16 - x^2}} dx = \int \frac{1}{\sqrt{4^2 - x^2}} dx = \arcsin\left(\frac{x}{4}\right) + C$$
03

Write the final answer

The final answer is: $$\int \frac{1}{\sqrt{16 - x^2}} dx = \arcsin\left(\frac{x}{4}\right) + C$$

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