Chapter 6: Problem 13
Find the area of the surface generated when the given curve is revolved about the \(x\) -axis. $$y=\frac{x^{3}}{3}+\frac{1}{4 x} \text { on }\left[\frac{1}{2}, 2\right]$$
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Chapter 6: Problem 13
Find the area of the surface generated when the given curve is revolved about the \(x\) -axis. $$y=\frac{x^{3}}{3}+\frac{1}{4 x} \text { on }\left[\frac{1}{2}, 2\right]$$
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A diving pool that is 4 m deep and full of water has a viewing window on one of its vertical walls. Find the force on the following windows. The window is a circle, with a radius of \(0.5 \mathrm{m}\), tangent to the bottom of the pool.
When the catenary \(y=a \cosh (x / a)\) is rotated around the \(x\) -axis, it sweeps out a surface of revolution called a catenoid. Find the area of the surface generated when \(y=\cosh x\) on \([-\ln 2, \ln 2]\) is rotated around the \(x\) -axis.
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Evaluate the following integrals. $$\int 7^{2 x} d x$$
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