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Symmetry in integrals Use symmetry to evaluate the following integrals. $$\int_{-200}^{200} 2 x^{5} d x$$

Short Answer

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Question: Use symmetry to evaluate the integral $$\int_{-200}^{200} 2x^5 dx$$. Answer: The integral evaluates to 0.

Step by step solution

01

Determine if the function is odd or even

To determine if a function is odd or even, we need to check the following conditions: - A function \(f(x)\) is even if \(f(-x) = f(x)\) - A function \(f(x)\) is odd if \(f(-x) = -f(x)\) Let's evaluate \(f(-x)\): $$f(-x) = 2(-x)^5 = -2x^5 = -f(x)$$ Since \(f(-x) = -f(x)\), the function \(f(x)\) is an odd function.
02

Utilize symmetry for odd functions

For odd functions, the following property is true: $$\int_{-a}^{a} f(x) dx = 0$$ Since \(f(x)\) is an odd function, we can apply this property and evaluate the integral accordingly.
03

Evaluate the integral

Using the property stated above, the given integral is: $$\int_{-200}^{200} 2x^5 dx = 0$$ Hence, the evaluated integral is equal to 0.

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