Chapter 5: Problem 70
Additional integrals Use a change of variables to evaluate the following integrals. $$\int_{1}^{e^{2}} \frac{\ln x}{x} d x$$
Short Answer
Expert verified
Question: Evaluate the integral $$\int_{1}^{e^{2}} \frac{\ln x}{x} d x$$.
Answer: $$\int_{1}^{e^{2}} \frac{\ln x}{x} d x = 2$$.
Step by step solution
01
Choose a substitution
Let's substitute $$u = \ln x$$, which means that $$x = e^u$$.
02
Find the derivative of the substitution
Now, let's find the derivative with respect to $$x$$ to change the differential term $$dx$$ in terms of $$du$$. We have $$\frac{d u}{d x} = \frac{1}{x}$$. So, $$d u = \frac{d x}{x}$$. Thus, the differential term will be $$d x = x d u$$.
03
Change the limits of integration
Next, let's change our limits of integration using our substitution $$u = \ln x$$. When $$x = 1$$, $$u = \ln(1) = 0$$ and when $$x = e^{2}$$, $$u = \ln(e^{2}) = 2$$. So, our limits of integration will now be from $$u = 0$$ to $$u = 2$$.
04
Rewrite the integral
Now, let's rewrite the integral by substituting the expressions we found in steps 1-3:
$$\int_{1}^{e^{2}} \frac{\ln x}{x} d x = \int_{0}^{2} \frac{u}{e^{u}} e^{u} d u$$
Notice that $$\frac{u}{e^u}$$ and $$e^u$$ cancel each other out, and we are left with the following integral:
$$\int_{0}^{2} u d u$$
05
Evaluate the integral
We can now evaluate the integral using the power rule:
$$\int_{0}^{2} u d u = \left[\frac{1}{2}u^2\right]_{0}^{2} = \frac{1}{2}(2)^2 - \frac{1}{2}(0)^2 = 2$$
Therefore, $$\int_{1}^{e^{2}} \frac{\ln x}{x} d x = 2$$.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Change of Variables
The change of variables, also known as substitution, is a powerful technique that simplifies complex integrals by transforming them into easier forms. This technique involves replacing a variable with another variable, often making the integral more approachable.
In our given problem, we were working with the integral \( \int_{1}^{e^{2}} \frac{\ln x}{x} d x \). The natural logarithm function \( \ln x \) can be tricky to integrate directly, so we used substitution to make the process easier.
**How Substitution Works**
1. **Choose a new variable**: Select a substitution that simplifies the integral. In this case, setting \( u = \ln x \) was effective because it reduced the compound structure of the integrand.
2. **Convert the differential**: Calculate \( du \) in terms of \( dx \). This ensures that the entire integral is expressed in terms of \( u \). Here, \( du = \frac{1}{x} dx \).
3. **Adjust the limits of integration**: Since we changed variables, the limits of integration must be updated to reflect the new bounds. When \( x = 1 \), \( u = 0 \), and when \( x = e^{2} \), \( u = 2 \).
This transformed our integral into a simpler form, \( \int_{0}^{2} u du \), where straightforward integration rules apply.
In our given problem, we were working with the integral \( \int_{1}^{e^{2}} \frac{\ln x}{x} d x \). The natural logarithm function \( \ln x \) can be tricky to integrate directly, so we used substitution to make the process easier.
**How Substitution Works**
1. **Choose a new variable**: Select a substitution that simplifies the integral. In this case, setting \( u = \ln x \) was effective because it reduced the compound structure of the integrand.
2. **Convert the differential**: Calculate \( du \) in terms of \( dx \). This ensures that the entire integral is expressed in terms of \( u \). Here, \( du = \frac{1}{x} dx \).
3. **Adjust the limits of integration**: Since we changed variables, the limits of integration must be updated to reflect the new bounds. When \( x = 1 \), \( u = 0 \), and when \( x = e^{2} \), \( u = 2 \).
This transformed our integral into a simpler form, \( \int_{0}^{2} u du \), where straightforward integration rules apply.
Definite Integrals
Definite integrals calculate the area under a curve within specified limits. It is crucial to respect the boundaries given in the problem as they dictate the precise region of integration.
For the integral \( \int_{1}^{e^{2}} \frac{\ln x}{x} dx \), the definite integral helps us find the exact numeric value for the area between \( x = 1 \) and \( x = e^2 \) for the function \( \frac{\ln x}{x} \). Here are the key aspects:
- **Limits of Integration**: These are \( 1 \) and \( e^2 \) in the original integral, but when using substitution, they transformed to \( 0 \) and \( 2 \), respectively, for the variable \( u \).
- **Evaluating Integrals**: Once simplified using substitution, we evaluated the definite integral \( \int_{0}^{2} u du \) by applying the power rule.
- **Outcome**: This leads us to a concrete numerical answer \( 2 \), representing the precise area between the given boundaries.
For the integral \( \int_{1}^{e^{2}} \frac{\ln x}{x} dx \), the definite integral helps us find the exact numeric value for the area between \( x = 1 \) and \( x = e^2 \) for the function \( \frac{\ln x}{x} \). Here are the key aspects:
- **Limits of Integration**: These are \( 1 \) and \( e^2 \) in the original integral, but when using substitution, they transformed to \( 0 \) and \( 2 \), respectively, for the variable \( u \).
- **Evaluating Integrals**: Once simplified using substitution, we evaluated the definite integral \( \int_{0}^{2} u du \) by applying the power rule.
- **Outcome**: This leads us to a concrete numerical answer \( 2 \), representing the precise area between the given boundaries.
Logarithmic Integration
Logarithmic integration involves integrating functions that contain logarithms, such as \( \ln x \). Direct integration can be complicated, which is why substitution often simplifies the process.
In this exercise, \( \int \frac{\ln x}{x} dx \) was made manageable by recognizing that:\[ \text{If } u = \ln x, \text{ then } \frac{\ln x}{x} dx \text{ transforms to } u du. \]
**Steps in Logarithmic Integration**
- **Substitution Choice**: By choosing \( u = \ln x \), we turned a difficult integral into one that uses the power rule easily. This highlights the effectiveness of substitution when dealing with \( \ln x \).
- **Resulting Integral**: The transformation yielded \( \int u du \), allowing us to solve it using the fundamental integration techniques, thereby avoiding the complexities of logarithms.
Overall, logarithmic integration coupled with substitution is a strategic approach that demystifies and resolves otherwise challenging integrals.
In this exercise, \( \int \frac{\ln x}{x} dx \) was made manageable by recognizing that:\[ \text{If } u = \ln x, \text{ then } \frac{\ln x}{x} dx \text{ transforms to } u du. \]
**Steps in Logarithmic Integration**
- **Substitution Choice**: By choosing \( u = \ln x \), we turned a difficult integral into one that uses the power rule easily. This highlights the effectiveness of substitution when dealing with \( \ln x \).
- **Resulting Integral**: The transformation yielded \( \int u du \), allowing us to solve it using the fundamental integration techniques, thereby avoiding the complexities of logarithms.
Overall, logarithmic integration coupled with substitution is a strategic approach that demystifies and resolves otherwise challenging integrals.