/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 Use limit methods to determine w... [FREE SOLUTION] | 91Ó°ÊÓ

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Use limit methods to determine which of the two given functions grows faster, or state that they have comparable growth rates. $$e^{x^{2}} ; e^{10 x}$$

Short Answer

Expert verified
Answer: The function \(e^{x^2}\) grows faster than the function \(e^{10x}\).

Step by step solution

01

- Define the Ratio of Functions

To compare the growth rates of the given functions \(f(x) = e^{x^2}\) and \(g(x) = e^{10x}\), let us first create a ratio function, \(h(x) = \frac{f(x)}{g(x)}\). \(h(x) = \frac{e^{x^2}}{e^{10x}}\)
02

- Simplify h(x)

Now let's simplify the ratio function \(h(x)\) using properties of exponents. \(h(x) = \frac{e^{x^2}}{e^{10x}} = e^{x^2 - 10x}\)
03

- Find the Limit of h(x)

Now, let us find the limit of the function \(h(x) = e^{x^2 - 10x}\) as \(x \to \infty\). \(\lim_{x \to \infty} h(x) = \lim_{x \to \infty} e^{x^2 - 10x}\) For this, we will use the fact that exponential functions grow much faster than polynomial functions.
04

- Analyze the Limit of h(x)

As x approaches infinity, the exponent \(x^2 - 10x\) will become dominated by the \(x^2\) term due to the fundamental rate of growth of functions. Therefore, the \(10x\) term will become relatively insignificant in comparison. So, we can say: \(\lim_{x \to \infty} h(x) = \lim_{x \to \infty} e^{x^2}\) Since the exponential function \(e^{x^2}\) grows without bound as \(x \to \infty\), the limit is: \(\lim_{x \to \infty} h(x) = \infty\)
05

- Determine the Growth Rate Comparison

The limit of the ratio \(\lim_{x \to \infty} h(x) = \infty\) shows that the function \(f(x) = e^{x^2}\) grows faster than the function \(g(x) = e^{10x}\) as \(x\) approaches infinity. In conclusion, the function \(e^{x^2}\) grows faster than the function \(e^{10x}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits
Limits are a fundamental concept in calculus that help us understand the behavior of functions as the input, often denoted as \(x\), approaches a certain value—in this case, infinity. When we talk about limits at infinity, we're interested in understanding how the function behaves as \(x\) grows larger and larger.

To analyze the growth of functions \(e^{x^2}\) and \(e^{10x}\), we calculate the limit of their ratio as \(x\to\infty\). This helps us see which function grows faster. A key insight here is using limits to provide clarity on the relative pace of growth between competing functions.
  • If the limit of the ratio is \infty, the numerator (top part of the fraction) grows faster than the denominator (bottom part).
  • If the limit is 0, the denominator grows faster than the numerator.
  • If the limit is a finite positive number, both functions grow at a comparable rate.
Understanding limits allows us to rigorously determine which function outpaces the other as \(x\to\infty\). In our specific case, the function \(e^{x^2}\)'s domination in the growth was confirmed by observing the limit \(\lim_{x \to \infty} h(x) = \infty\). This means \(e^{x^2}\) grows faster than \(e^{10x}\).
Exponential Functions
Exponential functions have the form \(e^{f(x)}\), where \(e\) is a constant approximately equal to 2.71828 and \(f(x)\) is an expression involving \(x\). They are fascinating due to their unique growth properties: they grow at rates proportional to their current value, leading to extremely rapid increases.

In our comparison of \(e^{x^2}\) and \(e^{10x}\), the exponent determines how quickly each function grows. For \(e^{x^2}\), the square in the exponent results in a more aggressive growth because \(x^2\) increases much faster than \(10x\) as \(x\) becomes large.
  • Exponential growth is not linear; it accelerates as the variable \(x\) becomes larger.
  • The function \(e^{x^2}\) indicates that the output increases not only due to \(x\) but the exponential effect of squaring \(x\).
  • For \(e^{10x}\), though the growth is accelerated by 10, it is still slower than the squared variant over the longer term.
Thus, understanding exponential functions is critical as they can model phenomena in the real world like population growth and radioactive decay. In mathematics, they are essential in evaluating growth trends as seen in our analysis.
Rate of Growth
Rate of growth is a concept in understanding how quickly a function's output increases as its input changes. It is especially critical when comparing functions for which the growth isn't straightforward.

When comparing \(e^{x^2}\) and \(e^{10x}\), we considered the rate of growth by looking at the behavior of the ratio \(h(x) = \frac{e^{x^2}}{e^{10x}}\), simplifying it to \(e^{x^2 - 10x}\). This expression allowed us to see exactly how the terms \(x^2\) and \(-10x\) influence the rate at which each function grows over the input range.
  • The term \(x^2\) in the growth rates leads to a dominating effect, which means \(e^{x^2}\) grows exceptionally faster than \(e^{10x}\).
  • Rate of growth is visually and analytically apparent when a function with a higher exponent (like \(x^2\)) shows faster progression over linear terms like \(10x\).
  • Analyzing these rates helps not just for theoretical comparison but also to gather insights into applications where such functions are practicable.
Understanding and comparing the rate of growth is crucial for many real-world contexts, including finance, biology, and engineering, where determining which processes scale faster can lead to better decision-making.

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