/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Determine the following indefini... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine the following indefinite integrals. Check your work by differentiation. $$\int \frac{1}{2 y} d y$$

Short Answer

Expert verified
Question: Find the antiderivative of the function \(\frac{1}{2y}\) with respect to \(y\), and verify your solution. Answer: The antiderivative of the function \(\frac{1}{2y}\) with respect to \(y\) is \(\frac{1}{2}\ln|y| + C\), where \(C\) is the constant of integration. Verification is obtained by differentiating the antiderivative to obtain the original function \(\frac{1}{2y}\).

Step by step solution

01

Find the antiderivative

To find the antiderivative of the function \(\frac{1}{2y}\) with respect to \(y\), we integrate it: $$\int \frac{1}{2y} dy$$ The integral of the given function can be written as: $$\frac{1}{2} \int \frac{1}{y} dy$$ Now, we know that the antiderivative of \(\frac{1}{y}\) with respect to \(y\) is \(\ln|y|\), so we can now write the result as: $$\frac{1}{2}\ln|y| + C$$ where \(C\) is the constant of integration.
02

Differentiate the antiderivative

To check our work, we will now differentiate the antiderivative function that we found: $$\frac{d}{dy}(\frac{1}{2}\ln|y| + C)$$ Applying the chain rule, we have: $$\frac{1}{2} \cdot \frac{1}{y} \cdot 1 + 0$$ Which simplifies to: $$\frac{1}{2y}$$ Since the derivative of our antiderivative function matches the original function, we have successfully verified our work. The correct antiderivative is: $$\frac{1}{2}\ln|y| + C$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The graph of \(f^{\prime}\) on the interval [-3,2] is shown in the figure. a. On what interval(s) is \(f\) increasing? Decreasing? b. Find the critical points of \(f .\) Which critical points correspond to local maxima? Local minima? Neither? c. At what point(s) does \(f\) have an inflection point? d. On what interval(s) is \(f\) concave up? Concave down? e. Sketch the graph of \(f^{\prime \prime}\) f. Sketch one possible graph of \(f\)

Show that \(f(x)=\log _{a} x\) and \(g(x)=\) \(\log _{b} x,\) where \(a>1\) and \(b>1,\) grow at a comparable rate as \(x \rightarrow \infty\).

Suppose that object A is located at \(s=0\) at time \(t=0\) and starts moving along the \(s\) -axis with a velocity given by \(v(t)=2 a t,\) where \(a > 0 .\) Object \(B\) is located at \(s=c>0\) at \(t=0\) and starts moving along the \(s\) -axis with a constant velocity given by \(V(t)=b>0 .\) Show that \(\mathrm{A}\) always overtakes \(\mathrm{B}\) at time $$t=\frac{b+\sqrt{b^{2}+4 a c}}{2 a}$$.

Find the function \(F\) that satisfies the following differential equations and initial conditions. $$F^{\prime \prime \prime}(x)=672 x^{5}+24 x, F^{\prime \prime}(0)=0, F^{\prime}(0)=2, F(0)=1$$

Suppose you make a deposit of \(\$ P\) into a savings account that earns interest at a rate of \(100 \mathrm{r} \%\) per year. a. Show that if interest is compounded once per year, then the balance after \(t\) years is \(B(t)=P(1+r)^{t}\). b. If interest is compounded \(m\) times per year, then the balance after \(t\) years is \(B(t)=P(1+r / m)^{m t} .\) For example, \(m=12\) corresponds to monthly compounding, and the interest rate for each month is \(r / 12 .\) In the limit \(m \rightarrow \infty,\) the compounding is said to be continuous. Show that with continuous compounding, the balance after \(t\) years is \(B(t)=\overline{P e^{r t}}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.