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Determine the following indefinite integrals. Check your work by differentiation. $$\int\left(4 z^{1 / 3}-z^{-1 / 3}\right) d z$$

Short Answer

Expert verified
Question: Find the indefinite integral of the given function and verify the solution by differentiation: $$\int\left(4 z^{1 / 3}-z^{-1 / 3}\right) d z$$ Answer: The indefinite integral of the given function is $$3z^{4/3} -\frac{3}{2}z^{2/3} + C$$

Step by step solution

01

Separate the Function into Two Integrals

We have: $$\int\left(4 z^{1 / 3}-z^{-1 / 3}\right) d z = \int 4z^{1/3}dz - \int z^{-1/3} dz$$
02

Integrate Each Function

Integrate each side separately: $$\int 4z^{1/3}dz = 4\int z^{1/3}dz = \frac{4}{4/3} z^{(1/3)+1} + C_1 = 3z^{4/3} + C_1$$ $$\int z^{-1/3} dz = \frac{1}{(-1/3)+1} z^{(-1/3)+1} + C_2 = -\frac{3}{2} z^{2/3} + C_2$$ Now, we combine the two integrals: $$\int\left(4 z^{1/3}-z^{-1/3}\right) d z = 3z^{4/3} - \frac{3}{2} z^{2/3} + C = G(z)$$ Where C is the constant of integration (C = C_1 - C_2).
03

Check by Differentiation

Take the derivative of the integrated function: $$\frac{d}{dz} G(z) = \frac{d}{dz} \left( 3z^{4/3} - \frac{3}{2} z^{2/3} + C \right)$$ Use the power rule for differentiation to find: $$\frac{d}{dz} G(z) = \left(4z^{(4/3)-1}\right) - \left(\frac{3}{2}(2/3)z^{(2/3)-1}\right) = 4z^{1/3} - z^{-1/3}$$ This is the original function, so our integration and solution are correct. The final answer is: $$\int\left(4 z^{1 / 3}-z^{-1 / 3}\right) d z = 3z^{4/3} - \frac{3}{2} z^{2/3} + C$$

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