/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Find the intervals on which \(f\... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the intervals on which \(f\) is increasing and decreasing. $$f(x)=\tan ^{-1} x$$

Short Answer

Expert verified
Answer: The function f(x) = \(\tan^{-1}x\) is increasing on the interval (-\(\infty\), \(\infty\)) and has no decreasing intervals.

Step by step solution

01

Find the derivative of f(x)

To find the derivative of f(x) with respect to x, we can use the formula for the derivative of the inverse tangent function, which is given by: $$\frac{d}{dx}(\tan^{-1}x) = \frac{1}{1+x^2}$$
02

Determine the sign of the derivative

Now that we have the derivative of f(x), we need to determine the intervals of x where it is positive or negative. Notice that the derivative function \(\frac{1}{1+x^2}\) is always positive for any value of x, since both the numerator and the denominator are always positive.
03

Analyze the increasing and decreasing intervals

Since the derivative is always positive for any value of x, we can conclude that the function f(x) is increasing for the entire domain of x, which is (-\(\infty\), \(\infty\)).
04

Final conclusion

The function f(x) = \(\tan^{-1}x\) is increasing on the interval (-\(\infty\), \(\infty\)) and has no decreasing intervals.

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