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Find the following higher-order derivatives. $$\left.\frac{d^{3}}{d x^{3}}\left(x^{4.2}\right)\right|_{x=1}$$

Short Answer

Expert verified
Answer: The third derivative of the function evaluated at x = 1 is $$29.568$$.

Step by step solution

01

Find the first derivative of the function

To find the first derivative of the function, we can make use of the power rule which states that: $$\frac{d(f(x))}{dx} = nx^{n-1}$$ Applying the power rule, the first derivative, f'(x), will be: $$f'(x) = 4.2x^{4.2-1}$$ Simplify: $$f'(x) = 4.2x^{3.2}$$
02

Find the second derivative of the function

Now that we have the first derivative, we can use the same power rule to find the second derivative, f''(x): $$f''(x) = 3.2\cdot 4.2x^{3.2-1}$$ Simplify: $$f''(x) = 13.44x^{2.2}$$
03

Find the third derivative of the function

To find the third derivative, f'''(x), we apply the power rule one more time: $$f'''(x) = 2.2\cdot 13.44x^{2.2-1}$$ Simplify: $$f'''(x) = 29.568x^{1.2}$$
04

Evaluate the third derivative at x = 1

Now that we have the third derivative, we will evaluate it at x = 1: $$\left.\frac{d^{3}}{d x^{3}}\left(x^{4.2}\right)\right|_{x=1} = 29.568(1)^{1.2}$$ Since 1 raised to any power remains 1, we have: $$\left.\frac{d^{3}}{d x^{3}}\left(x^{4.2}\right)\right|_{x=1} = 29.568$$ Thus, the solution for the problem is $$29.568$$.

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