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Find \(\frac{d^{2} y}{d x^{2}}\) for the following functions. $$y=\sqrt{x^{2}+2}$$

Short Answer

Expert verified
Question: Find the second derivative of the function y = √(x^2+2). Answer: The second derivative of the function is given by: $$ \frac{d^{2}y}{dx^{2}} = \frac{2}{(x^2+2)\sqrt{x^2+2}} $$

Step by step solution

01

Find the first derivative dy/dx

Differentiate the given function y with respect to x using the chain rule: $$ \frac{dy}{dx}=\frac{1}{2\sqrt{x^{2}+2}}\cdot\frac{d\left(x^{2}+2\right)}{dx} $$ Now, differentiate the inner function with respect to x: $$ \frac{d\left(x^{2}+2\right)}{dx}=2x $$ So, the first derivative becomes: $$ \frac{dy}{dx}=\frac{1}{2\sqrt{x^{2}+2}}\cdot\left(2x\right) $$
02

Simplify the first derivative

Simplify the expression for the first derivative: $$ \frac{dy}{dx}=\frac{x}{\sqrt{x^{2}+2}} $$
03

Compute the second derivative d²y/dx²

Differentiate the first derivative with respect to x using the quotient rule: $$ \frac{d^{2}y}{dx^{2}}=\frac{\left(\frac{d}{dx}x\right)\left(\sqrt{x^{2}+2}\right)-\left(\frac{d}{dx}\sqrt{x^{2}+2}\right)(x)}{\left(x^2+2\right)} $$
04

Compute the derivatives in the numerator

Differentiate x and sqrt(x^2+2) with respect to x: $$ \frac{d}{dx}x=1 $$ and $$ \frac{d}{dx}\sqrt{x^{2}+2}=\frac{x}{\sqrt{x^{2}+2}} $$ Substitute the derivatives into the expression for the second derivative: $$ \frac{d^{2}y}{dx^{2}}=\frac{\left(\sqrt{x^{2}+2}\right)-\left(\frac{x}{\sqrt{x^{2}+2}}\right)(x)}{(x^2+2)} $$
05

Simplify the second derivative

Simplify the expression for the second derivative: $$ \frac{d^{2}y}{dx^{2}}=\frac{x^2+2-x^2}{(x^2+2)\sqrt{x^2+2}} $$ Thus, the second derivative of the given function is: $$ \frac{d^{2} y}{d x^{2}}=\frac{2}{(x^2+2)\sqrt{x^2+2}} $$

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