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Implicit differentiation Carry out the following steps. a. Use implicit differentiation to find \(\frac{d y}{d x}\). b. Find the slope of the curve at the given point. $$x=e^{y} ;(2, \ln 2)$$

Short Answer

Expert verified
Question: Find the derivative of the function \(x = e^y\) implicitly and determine the slope of the curve at the point (2, ln2). Solution: 1. The derivative with respect to x, \(\frac{dy}{dx}=\frac{1}{e^y}\) 2. The slope of the curve at the given point (2, ln2) is \(\frac{1}{2}\).

Step by step solution

01

Rewrite the equation in terms of y

Rewrite the given function: $$x=e^y$$
02

Implicit differentiation

Apply implicit differentiation with respect to x on both sides of the equation: $$\frac{d}{dx} x = \frac{d}{dx} e^y$$ Recall that \(\frac{d}{dx}x = 1\). Also, finding the derivative of \(e^y\) with respect to x, we get: $$\frac{d}{dx} e^y = e^y\frac{dy}{dx}$$ Now the equation becomes: $$1=e^y\frac{dy}{dx}$$
03

Solve for \(\frac{d y}{d x}\)

Rearrange the equation to get \(\frac{d y}{d x}\) on one side: $$\frac{dy}{dx}=\frac{1}{e^y}$$
04

Plug in the given point (2, ln2)

Put \(x=2\) and \(y= \ln 2\) into the equation to find the slope of the curve at the given point: $$\frac{dy}{dx} \Big|_{(2, \ln 2)} = \frac{1}{e^{\ln 2}}$$
05

Simplify

As \(e^{\ln a} = a\), when \(a>0\) we can simplify the expression as: $$\frac{dy}{dx}\Big|_{(2, \ln 2)} = \frac{1}{2}$$ Answer: a. The derivative with respect to x, \(\frac{dy}{dx}=\frac{1}{e^y}\) b. The slope of the curve at the given point \((2, \ln2)\) is \(\frac{1}{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative of Exponential Functions
Understanding how to differentiate exponential functions is crucial in calculus. Exponential functions are of the form \( e^y \), where \( e \) is Euler's number, approximately equal to 2.71828. When differentiating \( e^y \) with respect to \( x \), we utilize implicit differentiation. This involves applying the chain rule, as \( y \) is a function of \( x \).
To perform implicit differentiation, take the derivative of \( e^y \). The derivative of \( e^y \) is \( e^y \) multiplied by the derivative of \( y \) with respect to \( x \), symbolized by \( \frac{dy}{dx} \). Therefore, the expression becomes \( \frac{d}{dx}e^y = e^y \cdot \frac{dy}{dx} \).
This approach helps differentiate functions where variables are intertwined, making it a robust method for many types of equations.
Slope of a Curve
The slope of a curve at any given point is essentially the derivative at that point. It represents the rate of change or the steepness of the curve. For implicit functions like \( x = e^y \), the slope is found after differentiating and solving for \( \frac{dy}{dx} \).
Sometimes, we need to evaluate this derivative at a particular point. For instance, in the original exercise, at the point \((2, \ln 2)\), the expression \( \frac{dy}{dx} = \frac{1}{e^y} \) is evaluated by substituting \( y = \ln 2 \).
  • Substitute \( y = \ln 2 \) into the derivative expression \( \frac{dy}{dx} \).
  • Recognize that \( e^{\ln 2} = 2 \).
  • This simplifies to \( \frac{1}{2} \), which is the slope at the given point.
Understanding the slope provides insights into how the function behaves at any small interval around this point.
Rewriting Equations in Terms of y
Rewriting equations involves expressing one variable explicitly in terms of another. This is especially helpful when dealing with implicit functions where variables are mixed. Take for instance the equation \( x = e^y \). Here, \( x \) is expressed in terms of \( y \).
To make the differentiation process easier, rewrite such that you understand the dependent relationship. You know that \( e^y \) must somehow represent a transformation of \( x \).
  • Isolate \( y \) if needed by using logarithms, as with \( y = \ln x \) from \( x = e^y \).
  • Manipulating equations this way helps prepare for differentiation.
  • Clear expressions simplify finding derivatives and understanding the slope as it links back to a known function.
Rewriting equations is a fundamental skill that makes it easier to navigate challenges in calculus and find solutions efficiently.

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