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Use the Chain Rule combined with other differentiation rules to find the derivative of the following functions. $$y=\tan \left(x e^{x}\right)$$

Short Answer

Expert verified
Answer: The derivative of the function \(y = \tan(xe^x)\) with respect to x is \(\frac{dy}{dx} = \sec^2(xe^x) \cdot e^x(1 + x)\).

Step by step solution

01

Differentiate the outer function using the trigonometric differentiation rule

Let \(u=xe^x\). The given function can be rewritten as \(y=\tan(u)\). Now, we differentiate the function \(y\) with respect to \(u\), bearing in mind that the derivative of the tangent function is \(\sec^2(u)\): $$\frac{dy}{du} = \sec^2(u) = \sec^2(xe^x)$$
02

Differentiate the inner function using the Product Rule

We have \(u=xe^x\). To find the derivative of this function with respect to x, we will employ the Product Rule, which is given by: $$\frac{d(uv)}{dx} = u'\cdot v + u\cdot v' $$ In our case, \(u = x\), \(v = e^x\). Therefore, we have \(u' = 1\) and \(v' = e^x\): $$\frac{du}{dx} = x'(e^x) + x(e^x)' = 1\cdot e^x + x\cdot e^x = e^x(1 + x)$$
03

Apply the Chain Rule

We will now use the Chain Rule, which states that: $$\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}$$ Substituting the values we have found in Steps 1 and 2: $$\frac{dy}{dx} = \sec^2(xe^x) \cdot e^x(1 + x)$$
04

Simplify the result (if possible)

In this case, there isn't much simplification needed. The final derivative of the given function is: $$\frac{dy}{dx} = \sec^2(xe^x) \cdot e^x(1 + x)$$ The derivative of the function \(y = \tan(xe^x)\) with respect to x is \(\frac{dy}{dx} = \sec^2(xe^x) \cdot e^x(1 + x)\).

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