/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 Calculating derivatives Find \(d... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Calculating derivatives Find \(d y / d x\) for the following functions .$$y=\frac{\sin x}{1+\cos x}$$

Short Answer

Expert verified
Question: Find the derivative of the function \(y = \frac{\sin x}{1+\cos x}\). Answer: The derivative of the function \(y = \frac{\sin x}{1+\cos x}\) is \(y' = \frac{1 + \cos x}{(1+\cos x)^2}\).

Step by step solution

01

Identify the quotient rule for differentiation

The quotient rule states that for a function \(f(x) = \frac{g(x)}{h(x)}\), the derivative of \(f(x)\) with respect to x, \(f'(x)\), can be found using the following formula: .$$f'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{[h(x)]^2}$$ In our case, the function is \(y = \frac{\sin x}{1+\cos x}\). Let \(g(x) = \sin x\) and \(h(x) = 1+\cos x\). We will begin by finding the derivatives of \(g(x)\) and \(h(x)\).
02

Find the derivatives of \(g(x)\) and \(h(x)\)

Using basic differentiation rules, we have: .$$g'(x) = \frac{d(\sin x)}{dx} = \cos x$$ .$$h'(x) = \frac{d(1+\cos x)}{dx} = -\sin x$$ Now that we have the derivatives of \(g(x)\) and \(h(x)\), we can plug these into the quotient rule formula that we identified in step 1.
03

Apply the quotient rule

Using the quotient rule with \(g'(x) = \cos x\), \(h'(x) = -\sin x\), \(g(x) = \sin x\), and \(h(x) = 1+\cos x\), we get: .$$y' = \frac{(\cos x)(1+\cos x) - (\sin x)(-\sin x)}{(1+\cos x)^2}$$
04

Simplify the expression

Now, we will simplify the obtained expression for the derivative: .$$y' = \frac{\cos x + \cos^2 x + \sin^2 x}{(1+\cos x)^2}$$ Recall the trigonometric identity \(\sin^2x + \cos^2x = 1\). Using this identity, we can further simplify the expression: .$$y' = \frac{1 + \cos x}{(1+\cos x)^2}$$
05

Express the final answer

The derivative of the given function, \(y = \frac{\sin x}{1+\cos x}\) is: .$$y' = \boxed{\frac{1 + \cos x}{(1+\cos x)^2}}$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
The Quotient Rule is a fundamental method used in calculus to find the derivative of a function that is the ratio of two differentiable functions. When you have a function in the form of \(y = \frac{g(x)}{h(x)}\), using the Quotient Rule becomes necessary for finding its derivative accurately. Here's the simple formula:
  • \[ y' = \frac{g'(x)h(x) - g(x)h'(x)}{[h(x)]^2} \]
This formula tells us the derivative of \(y\) by applying specific steps:
1. Differentiate the numerator \(g(x)\) to get \(g'(x)\).
2. Differentiate the denominator \(h(x)\) to get \(h'(x)\).
3. Substitute \(g'(x), h(x), g(x)\), and \(h'(x)\) back into the formula.
4. Simplify everything to find \(y'\), the derivative. The importance of the Quotient Rule lies in its ability to handle complex fractions where both the numerator and the denominator are functions of \(x\). It's crucial when just directly differentiating the top and bottom can cause errors. So, remember, when you see a fraction, consider using this powerful rule!
Trigonometric Identities
In calculus, trigonometric identities play a vital role in simplifying expressions and solving problems. These identities include fundamental relationships between trigonometric functions, like sine, cosine, and tangent. One of the most basic and helpful identities is:
  • \( \sin^2 x + \cos^2 x = 1 \)
This identity allows us to replace expressions involving \( \sin^2 x \) or \( \cos^2 x \) to simplify derivatives or integrals.
For instance, in the problem given, simplifying \( \sin^2 x + \cos^2 x \) directly turned it into \( 1 \). This type of simplification is crucial for making expressions manageable and less complicated.
Other common identities include:
  • \( \tan x = \frac{\sin x}{\cos x} \)
  • \( \sec^2 x = 1 + \tan^2 x \)
Using these identities can turn a seemingly complex calculus problem into one that's more approachable by reducing the steps needed to simplify the equation. So, keep these identities in mind whenever you deal with trigonometric functions in calculus!
Differentiation Techniques
Differentiation is a key concept in calculus that involves finding the derivative of a function. Different techniques are suitable for different types of functions. Here, we focus on some essential techniques:**1. Basic Derivatives:**
  • The derivative of \( \sin x \) is \( \cos x \).
  • The derivative of \( \cos x \) is \(-\sin x \).
Knowing these basic derivatives is the first step in tackling more complex problems.
**2. Applying the Quotient Rule:**When you have a fraction, like in this exercise \( y = \frac{\sin x}{1+\cos x} \), employing the Quotient Rule, as discussed previously, is the go-to technique.
**3. Simplification Using Trigonometric Identities:**In combination with basic differentiation and the Quotient Rule, simplifying derivatives using trigonometric identities further polishes the derivative to its simplest form.
These techniques, together, provide a robust toolkit for breaking down and solving differentiable functions efficiently. Practicing these methods ensures a smoother process when faced with complex calculus tasks.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Means and tangents Suppose \(f\) is differentiable on an interval containing \(a\) and \(b,\) and let \(P(a, f(a))\) and \(Q(b, f(b))\) be distinct points on the graph of \(f\). Let \(c\) be the \(x\) -coordinate of the point at which the lines tangent to the curve at \(P\) and \(Q\) intersect, assuming that the tangent lines are not parallel (see figure). a. If \(f(x)=x^{2},\) show that \(c=(a+b) / 2,\) the arithmetic mean of \(a\) and \(b\), for real numbers \(a\) and \(b\) b. If \(f(x)=\sqrt{x},\) show that \(c=\sqrt{a b},\) the geometric mean of \(a\) and \(b,\) for \(a>0\) and \(b>0\) c. If \(f(x)=1 / x,\) show that \(c=2 a b /(a+b),\) the harmonic mean of \(a\) and \(b,\) for \(a>0\) and \(b>0\) d. Find an expression for \(c\) in terms of \(a\) and \(b\) for any (differentiable) function \(f\) whenever \(c\) exists.

Visualizing tangent and normal lines a. Determine an equation of the tangent line and normal line at the given point \(\left(x_{0}, y_{0}\right)\) on the following curves. (See instructions for Exercises \(63-68 .)\) b. Graph the tangent and normal lines on the given graph. $$\begin{aligned}&3 x^{3}+7 y^{3}=10 y\\\&\left(x_{0}, y_{0}\right)=(1,1)\end{aligned}$$

The bottom of a large theater screen is \(3 \mathrm{ft}\) above your eye level and the top of the screen is \(10 \mathrm{ft}\) above your eye level. Assume you walk away from the screen (perpendicular to the screen) at a rate of \(3 \mathrm{ft} / \mathrm{s}\) while looking at the screen. What is the rate of change of the viewing angle \(\theta\) when you are \(30 \mathrm{ft}\) from the wall on which the screen hangs, assuming the floor is horizontal (see figure)?

Find the derivative of the inverse of the following functions at the specified point on the graph of the inverse function. You do not need to find \(f^{-1}\) $$f(x)=x^{2}+1, \text { for } x \geq 0 ;(5,2)$$

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. a. The derivative \(\frac{d}{d x}\left(e^{5}\right)\) equals \(5 \cdot e^{4}\) b. The Quotient Rule must be used to evaluate \(\frac{d}{d x}\left(\frac{x^{2}+3 x+2}{x}\right)\) c. \(\frac{d}{d x}\left(\frac{1}{x^{5}}\right)=\frac{1}{5 x^{4}}\) d. \(\frac{d^{n}}{d x^{n}}\left(e^{3 x}\right)=3^{n} \cdot e^{3 x},\) for any integer \(n \geq 1\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.