/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Let \(f(x)=\sin x .\) What is th... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(f(x)=\sin x .\) What is the value of \(f^{\prime}(\pi) ?\)

Short Answer

Expert verified
Answer: The value of the derivative is \(-1\).

Step by step solution

01

Differentiate the sine function

We have a function \(f(x) = \sin x\). We need to find its derivative, \(f'(x)\). Recall that the derivative of \(\sin x\) is \(\cos x\). So, we have: \(f'(x) = \cos x\)
02

Evaluate the derivative at \(x = \pi\)

Now we need to find the value of the derivative at \(x = \pi\). We do this by substituting \(x\) by \(\pi\) in \(f'(x)\). \(f'(\pi) = \cos \pi\)
03

Calculate the value of \(\cos \pi\)

Recall that \(\cos \pi = -1\). Therefore, \(f'(\pi) = -1\) Hence, the value of \(f'(\pi)\) is \(-1\).

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