/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Compute the derivative of the fo... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Compute the derivative of the following functions. $$g(x)=\frac{x}{e^{3 x}}$$

Short Answer

Expert verified
Answer: The derivative of the function is $$g'(x) = \frac{e^{3x}(1 - 3x)}{e^{6x}}$$.

Step by step solution

01

Identify f(x) and g(x)

First, let's identify the functions in the numerator and denominator: $$f(x) = x$$ $$g(x) = e^{3x}$$
02

Calculate the derivatives of f(x) and g(x)

Now let's find the derivatives of both functions f(x) and g(x): $$f'(x) = \frac{d}{dx}(x) = 1$$ $$g'(x) = \frac{d}{dx}(e^{3x}) = 3e^{3x}$$
03

Apply the quotient rule to find the derivative of g(x)

With the derivatives of f(x) and g(x) calculated, we can apply the quotient rule to find the derivative of $$g(x) = \frac{x}{e^{3x}}$$: $$g'(x) = \frac{f'(x)g(x) - f(x)g'(x)}{g^2(x)}$$ $$g'(x) = \frac{(1)(e^{3x}) - (x)(3e^{3x})}{(e^{3x})^2}$$
04

Simplify the expression

Now let's simplify the expression: $$g'(x) = \frac{e^{3x} - 3xe^{3x}}{e^{6x}}$$ $$g'(x) = \frac{e^{3x}(1 - 3x)}{e^{6x}}$$ So, the derivative of the given function is: $$g'(x) = \frac{e^{3x}(1 - 3x)}{e^{6x}}$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose \(y=L(x)=a x+b\) (with \(a \neq 0\) ) is the equation of the line tangent to the graph of a one-to-one function \(f\) at \(\left(x_{0}, y_{0}\right) .\) Also, suppose that \(y=M(x)=c x+d\) is the equation of the line tangent to the graph of \(f^{-1}\) at \(\left(y_{0}, x_{0}\right)\) a. Express \(a\) and \(b\) in terms of \(x_{0}\) and \(y_{0}\) b. Express \(c\) in terms of \(a,\) and \(d\) in terms of \(a, x_{0},\) and \(y_{0}\) c. Prove that \(L^{-1}(x)=M(x)\)

One of the Leibniz Rules One of several Leibniz Rules in calculus deals with higher-order derivatives of products. Let \((f g)^{(n)}\) denote the \(n\) th derivative of the product \(f g,\) for \(n \geq 1\) a. Prove that \((f g)^{(2)}=f^{\prime \prime} g+2 f^{\prime} g^{\prime}+f g^{\prime \prime}\) b. Prove that, in general,$$(f g)^{(n)}=\sum_{k=0}^{n}\left(\begin{array}{l} n \\\k\end{array}\right) f^{(k)} g^{(n-k)}$$ where \(\left(\begin{array}{l}n \\\ k\end{array}\right)=\frac{n !}{k !(n-k) !}\) are the binomial coefficients. c. Compare the result of (b) to the expansion of \((a+b)^{n}\).

Suppose \(f(2)=2\) and \(f^{\prime}(2)=3 .\) Let $$g(x)=x^{2} \cdot f(x) \text { and } h(x)=\frac{f(x)}{x-3}$$ a. Find an equation of the line tangent to \(y=g(x)\) at \(x=2\) b. Find an equation of the line tangent to \(y=h(x)\) at \(x=2\)

Witch of Agnesi Let \(y\left(x^{2}+4\right)=8\) (see figure). a. Use implicit differentiation to find \(\frac{d y}{d x}\) b. Find equations of all lines tangent to the curve \(y\left(x^{2}+4\right)=8\) when \(y=1\) c. Solve the equation \(y\left(x^{2}+4\right)=8\) for \(y\) to find an explicit expression for \(y\) and then calculate \(\frac{d y}{d x}\) d. Verify that the results of parts (a) and (c) are consistent.

Proof of the Quotient Rule Let \(F=f / g\) be the quotient of two functions that are differentiable at \(x\) a. Use the definition of \(F^{\prime}\) to show that \(\frac{d}{d x}\left[\frac{f(x)}{g(x)}\right]=\lim _{h \rightarrow 0} \frac{f(x+h) g(x)-f(x) g(x+h)}{h g(x+h) g(x)}\) b. Now add \(-f(x) g(x)+f(x) g(x)\) (which equals 0) to the numerator in the preceding limit to obtain $$\lim _{h \rightarrow 0} \frac{f(x+h) g(x)-f(x) g(x)+f(x) g(x)-f(x) g(x+h)}{h g(x+h) g(x)}$$ Use this limit to obtain the Quotient Rule. c. Explain why \(F^{\prime}=(f / g)^{\prime}\) exists, whenever \(g(x) \neq 0\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.