/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Let \(b\) represent the base dia... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(b\) represent the base diameter of a conifer tree and let \(h\) represent the height of the tree, where \(b\) is measured in centimeters and \(h\) is measured in meters. Assume the height is related to the base diameter by the function \(h=5.67+0.70 b+0.0067 b^{2}\). a. Graph the height function. b. Plot and interpret the meaning of \(\frac{d h}{d b}\).

Short Answer

Expert verified
#Answer# The derivative of the height function, \(\frac{dh}{db}\) = \(0.70 + 0.0134b\), represents the rate at which the height of the tree increases with respect to the increase in its base diameter. It has a positive value, indicating that the height increases as the base diameter increases, and a positive slope, which means that the height increases at a faster rate as the base diameter grows larger.

Step by step solution

01

Writing the height function

We are given the height function as: $$h = 5.67 + 0.70b + 0.0067b^2$$
02

Graphing the height function

To graph the height function, we can use a graphing tool (such as Desmos, GeoGebra, or a graphing calculator). Simply input the function as given and choose a reasonable domain and range (e.g., positive values for \(b\) since it represents the base diameter). After plotting the function, you should see that it is a quadratic function, with the height increasing as the base diameter increases.
03

Calculating the derivative of the height function with respect to base diameter

To find the derivative of the height function with respect to the base diameter \(b\), we can use the power rule for differentiation. The derivative is denoted as \(\frac{dh}{db}\) and is calculated as follows: $$\frac{dh}{db} = \frac{d(5.67+0.70b+0.0067b^2)}{db} = 0 + 0.70 + 0.0067(2)b = 0.70 + 0.0134b$$
04

Plotting the derivative of the height function

Similar to step 2, plot the function \(\frac{dh}{db}=0.70+0.0134b\) using a graphing tool, with an appropriate domain (positive values for \(b\)). You will see that it is a linear function with a positive slope, indicating that as the base diameter increases, the rate of increase in height also increases.
05

Interpreting the meaning of the derivative

The derivative of the height function, \(\frac{dh}{db}\), represents the rate at which the height of the tree increases with respect to the increase in its base diameter. In this case, it has a positive value, indicating that the height increases as the base diameter increases. Moreover, because the slope is positive, it indicates that the height increases at a faster rate as the base diameter grows larger.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use any method to evaluate the derivative of the following functions. $$h(x)=\left(5 x^{7}+5 x\right)\left(6 x^{3}+3 x^{2}+3\right)$$

Once Kate's kite reaches a height of \(50 \mathrm{ft}\) (above her hands), it rises no higher but drifts due east in a wind blowing \(5 \mathrm{ft} / \mathrm{s} .\) How fast is the string running through Kate's hands at the moment that she has released \(120 \mathrm{ft}\) of string?

Means and tangents Suppose \(f\) is differentiable on an interval containing \(a\) and \(b,\) and let \(P(a, f(a))\) and \(Q(b, f(b))\) be distinct points on the graph of \(f\). Let \(c\) be the \(x\) -coordinate of the point at which the lines tangent to the curve at \(P\) and \(Q\) intersect, assuming that the tangent lines are not parallel (see figure). a. If \(f(x)=x^{2},\) show that \(c=(a+b) / 2,\) the arithmetic mean of \(a\) and \(b\), for real numbers \(a\) and \(b\) b. If \(f(x)=\sqrt{x},\) show that \(c=\sqrt{a b},\) the geometric mean of \(a\) and \(b,\) for \(a>0\) and \(b>0\) c. If \(f(x)=1 / x,\) show that \(c=2 a b /(a+b),\) the harmonic mean of \(a\) and \(b,\) for \(a>0\) and \(b>0\) d. Find an expression for \(c\) in terms of \(a\) and \(b\) for any (differentiable) function \(f\) whenever \(c\) exists.

Find the derivative of the inverse of the following functions at the specified point on the graph of the inverse function. You do not need to find \(f^{-1}\) $$f(x)=x^{2}-2 x-3, \text { for } x \leq 1 ;(12,-3)$$

Orthogonal trajectories Two curves are orthogonal to each other if their tangent lines are perpendicular at each point of intersection (recall that two lines are perpendicular to each other if their slopes are negative reciprocals. . A family of curves forms orthogonal trajectories with another family of curves if each curve in one family is orthogonal to each curve in the other family. For example, the parabolas \(y=c x^{2}\) form orthogonal trajectories with the family of ellipses \(x^{2}+2 y^{2}=k,\) where \(c\) and \(k\) are constants (see figure). Use implicit differentiation if needed to find \(d y / d x\) for each equation of the following pairs. Use the derivatives to explain why the families of curves form orthogonal trajectories. \(x y=a ; x^{2}-y^{2}=b,\) where \(a\) and \(b\) are constants

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.