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Use the Chain Rule to find the derivative of the following functions. $$y=\left(2 x^{6}-3 x^{3}+3\right)^{25}$$

Short Answer

Expert verified
Question: Find the derivative of the function $$y=(2x^6 - 3x^3 + 3)^{25}$$. Answer: The derivative of the function is $$y' = 25(2x^6 - 3x^3 + 3)^{24} \cdot (12x^5 - 9x^2)$$.

Step by step solution

01

Identify the inner and outer functions

The given function can be written as a composite function $$y=(f(g(x)))^{25}$$ where $$f(u) = u^{25}$$ and $$g(x) = 2x^6 - 3x^3 + 3$$ The outer function is \(f(u) = u^{25}\), and the inner function is \(g(x) = 2x^6 - 3x^3 + 3\). Step 2: Find the derivatives of the inner and outer functions
02

Find the derivatives of the inner and outer functions

First, let's find the derivative of the inner function: $$g'(x) = \frac{d}{dx}\left(2x^6 - 3x^3 + 3\right) = 12x^5 - 9x^2$$ Next, find the derivative of the outer function: $$f'(u) = \frac{d}{dx}\left(u^{25}\right) = 25u^{24}$$ Step 3: Apply the Chain Rule
03

Apply the Chain Rule

Now, we apply the chain rule to find the derivative of the composite function: $$\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}$$ where \(u=g(x)\). Substitute the derivatives found in Step 2: $$\frac{dy}{dx} = f'(g(x)) \cdot g'(x) = 25(2x^6 - 3x^3 + 3)^{24} \cdot (12x^5 - 9x^2)$$ Step 4: Simplify
04

Simplify

Our final answer for the derivative of the function is: $$y' = 25(2x^6 - 3x^3 + 3)^{24} \cdot (12x^5 - 9x^2)$$

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