Chapter 3: Problem 30
a. For the following functions and points, find \(f^{\prime}(a)\) b. Determine an equation of the line tangent to the graph of \(f\) at \((a, f(a))\) for the given value of \(a\). $$f(x)=2 x^{3} ; a=10$$
Short Answer
Expert verified
The equation of the line tangent to the graph at \(a=10\) is:
\(y - 2000 = 600(x - 10)\)
Step by step solution
01
Find the derivative of the function \(f(x)\)
To determine the derivative of the function \(f(x) = 2x^3\), we will use the power rule. The power rule states that if \(f(x) = x^n\), where \(n\) is a constant, then \(f'(x) = nx^{n-1}\). Applying the power rule to our function, we get:
$$f^{\prime}(x) = 3 \cdot 2x^{3-1} = 6x^2$$
02
Evaluate the derivative at \(a = 10\)
To find the slope of the tangent line at \(a = 10\), we will substitute the value of \(a\) into the derivative:
$$f^{\prime}(a) = 6a^2 = 6(10)^2 = 600$$
So, the slope of the tangent line at \(a = 10\) is 600.
03
Find the point \((a, f(a))\)
Now we will find the coordinates of the point on the graph of \(f(x)\) where the tangent line touches it. Since \(a = 10\), we will evaluate \(f(a)\):
$$f(a) = 2a^3 = 2(10)^3 = 2000$$
Therefore, the point \((a, f(a))\) is \((10, 2000)\).
04
Determine the equation of the tangent line
Finally, we will use the point-slope form of a linear equation to find the equation of the tangent line. The point-slope form is given by \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) are the coordinates of the point on the line and \(m\) is the slope. In our case, \((x_1, y_1) = (10, 2000)\) and \(m = 600\). Plugging in these values, we get:
$$y - 2000 = 600(x - 10)$$
And that is the equation of the line tangent to the graph of \(f(x)=2x^3\) at \(a = 10\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
The power rule is a fundamental concept in calculus, used to find the derivative of functions that are expressed as powers. Essentially, it makes taking derivatives simple for polynomial expressions. Whether you’re dealing with a term like \(x^3\) or any variable raised to a power, the power rule states that if you have a function \(f(x) = x^n\), its derivative \(f'(x)\) would be \(nx^{n-1}\). This involves:
- Multiplying the power 'n' by the coefficient of the term.
- Reducing the power by one to form the new exponent.
Tangent Line
A tangent line is a straight line that touches a curve at a single point, matching the curve's slope at that point. Understanding tangent lines is important in many fields, both mathematical and applied, from analyzing graphs to modeling real-world data. When you have a function like \(f(x) = 2x^3\), the tangent line at any point \((a, f(a))\) gives you an approximation of the curve near that point. The slope of this tangent line is given by the derivative, \(f'(a)\).
- First, find the derivative of the function to obtain the slope.
- Then, evaluate this derivative at the desired point to get the specific slope at that point.
- Use this slope in conjunction with the point to determine the equation of the tangent line.
Point-Slope Form
The point-slope form is a formula used to find the equation of a line when you know the slope and a point on the line. It’s especially useful when dealing with tangent lines in calculus, as it makes finding linear equations straightforward. The formula is:\[ y - y_1 = m(x - x_1) \]where \((x_1, y_1)\) are the coordinates of the point and \(m\) is the slope. To use this form:
- First, determine the slope of the line using the derivative of the function.
- Identify the specific point on the curve that intersects with the tangent line.
- Substitute both the point and the slope into the point-slope formula to get the tangent line's equation.