/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Why are both the \(x\) -coordina... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Why are both the \(x\) -coordinate and the \(y\) -coordinate generally needed to find the slope of the tangent line at a point for an implicitly defined function?

Short Answer

Expert verified
Answer: Both x and y coordinates are needed to find the slope of the tangent line at a point for an implicitly defined function because they impact the values of the partial derivatives when evaluating the expression for dy/dx. The slope of the tangent line is determined by evaluating the expression at a specific point (x, y), which requires both the x and y coordinates to accurately compute the slope.

Step by step solution

01

Differentiate both sides with respect to x

Start by differentiating both sides of the implicitly defined function F(x, y) = 0 concerning x. Remember to use the chain rule while differentiating with respect to y. \[\frac{dF}{dx} = \frac{\partial F}{\partial x} + \frac{\partial F}{\partial y}\frac{dy}{dx}\] In this step, we implicitly differentiate the function; however, the values of x and y are not needed yet.
02

Rearrange the equation to find dy/dx

Next, rearrange the equation to find the explicit expression for dy/dx, the slope of the tangent line. \[\frac{dy}{dx} = -\frac{\frac{\partial F}{\partial x}}{\frac{\partial F}{\partial y}}\] In this step, we have found the expression for the slope. However, we still need to evaluate this expression at a specific point (x, y) to find the slope of the tangent line.
03

Evaluate the expression at the point (x, y)

Now, evaluate the expression for dy/dx at the point (x, y) to get the slope of the tangent line at that specific point. \[\left.\frac{dy}{dx}\right|_{(x,y)} = -\frac{\frac{\partial F}{\partial x}(x,y)}{\frac{\partial F}{\partial y}(x,y)}\] In this final step, we needed both the x and y coordinates to compute the slope of the tangent line at the point (x, y). This step is crucial as both the \(x\)-coordinate and the \(y\)-coordinate impact the values of the partial derivatives, leading to the tangent line's slope.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Visualizing tangent and normal lines a. Determine an equation of the tangent line and normal line at the given point \(\left(x_{0}, y_{0}\right)\) on the following curves. (See instructions for Exercises \(63-68 .)\) b. Graph the tangent and normal lines on the given graph. \(\left(x^{2}+y^{2}\right)^{2}=\frac{25}{3}\left(x^{2}-y^{2}\right);\) \(\left(x_{0}, y_{0}\right)=(2,-1)\) (lemniscate of Bernoulli)

Use any method to evaluate the derivative of the following functions. $$h(x)=\left(5 x^{7}+5 x\right)\left(6 x^{3}+3 x^{2}+3\right)$$

Proof of the Quotient Rule Let \(F=f / g\) be the quotient of two functions that are differentiable at \(x\) a. Use the definition of \(F^{\prime}\) to show that \(\frac{d}{d x}\left[\frac{f(x)}{g(x)}\right]=\lim _{h \rightarrow 0} \frac{f(x+h) g(x)-f(x) g(x+h)}{h g(x+h) g(x)}\) b. Now add \(-f(x) g(x)+f(x) g(x)\) (which equals 0) to the numerator in the preceding limit to obtain $$\lim _{h \rightarrow 0} \frac{f(x+h) g(x)-f(x) g(x)+f(x) g(x)-f(x) g(x+h)}{h g(x+h) g(x)}$$ Use this limit to obtain the Quotient Rule. c. Explain why \(F^{\prime}=(f / g)^{\prime}\) exists, whenever \(g(x) \neq 0\)

Once Kate's kite reaches a height of \(50 \mathrm{ft}\) (above her hands), it rises no higher but drifts due east in a wind blowing \(5 \mathrm{ft} / \mathrm{s} .\) How fast is the string running through Kate's hands at the moment that she has released \(120 \mathrm{ft}\) of string?

A particle travels clockwise on a circular path of diameter \(R,\) monitored by a sensor on the circle at point \(P ;\) the other endpoint of the diameter on which the sensor lies is \(Q\) (see figure). Let \(\theta\) be the angle between the diameter \(P Q\) and the line from the sensor to the particle. Let \(c\) be the length of the chord from the particle's position to \(Q\) a. Calculate \(d \theta / d c\) b. Evaluate \(\left.\frac{d \theta}{d c}\right|_{c=0}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.