/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Find \(d y / d x\) for the follo... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(d y / d x\) for the following functions. $$y=e^{6 x} \sin x$$

Short Answer

Expert verified
Answer: The derivative of the function \(y=e^{6x}\sin x\) with respect to \(x\) is \(\frac{dy}{dx} = 6e^{6x}\sin x + e^{6x}\cos x\).

Step by step solution

01

Find the derivatives of f and g

We need to find the derivatives of \(f(x) = e^{6x}\) and \(g(x) = \sin x\) with respect to \(x\). For \(f(x) = e^{6x}\), use the chain rule, which says that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function. So, taking the derivative with respect to \(x\), we have: $$f'(x) = \frac{d}{dx} (e^{6x}) = e^{6x} \cdot \frac{d(6x)}{dx} = e^{6x} \cdot 6 = 6e^{6x}$$ For \(g(x) = \sin x\), the derivative with respect to \(x\) is simply: $$g'(x) = \frac{d}{dx} (\sin x) = \cos x$$ Now, we can use the product rule to find the derivative of \(y = e^{6x}\sin x\).
02

Apply the product rule

Using the product rule, we get: $$\frac{dy}{dx} = f'(x)g(x) + f(x)g'(x) = 6e^{6x}\sin x + e^{6x}\cos x$$ So, the derivative of \(y=e^{6x}\sin x\) with respect to \(x\) is: $$\frac{dy}{dx} = 6e^{6x}\sin x + e^{6x}\cos x$$

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