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A rectangle initially has dimensions \(2 \mathrm{cm}\) by \(4 \mathrm{cm} .\) All sides begin increasing in length at a rate of \(1 \mathrm{cm} / \mathrm{s}\). At what rate is the area of the rectangle increasing after \(20 \mathrm{s} ?\)

Short Answer

Expert verified
Answer: The rate at which the area is increasing after 20 seconds is 46 cm²/s.

Step by step solution

01

Write down the given values

The initial dimensions of the rectangle are 2 cm and 4 cm. The rate at which all sides are increasing in length is 1 cm/s. After 20 seconds, we need to find the rate at which the rectangle's area is increasing.
02

Determine the dimensions after 20 seconds

Since both sides increase at a rate of 1 cm/s, after 20 seconds, the length and width will increase by 20 cm. Thus, the new dimensions will be: Length: \(2+20=22 \mathrm{cm}\) Width: \(4+20=24 \mathrm{cm}\)
03

Write the area formula

The formula for the area of a rectangle is given by: \(A = \text{Length} \times \text{Width}\)
04

Write the length and width functions with respect to time

After \(t\) seconds have passed, the length will be \((2+t) \mathrm{cm}\) and the width will be \((4+t) \mathrm{cm}\).
05

Write the area function with respect to time

Substituting the length and width functions into the area formula, we get: \(A(t) = (2+t)(4+t)\)
06

Differentiate the area function with respect to time

Differentiate \(A(t)\) with respect to \(t\) using the product rule and chain rule: \(\frac{dA}{dt} = (2+t) \frac{d(4+t)}{dt} + (4+t) \frac{d(2+t)}{dt} \\ = (2+t)(1) + (4+t)(1) = (2+t) + (4+t)\)
07

Find the rate at which the area is increasing after 20 seconds

Substitute \(t=20\) into the \(\frac{dA}{dt}\) formula to find the rate at which the area is increasing after 20 seconds: \(\frac{dA}{dt}(20) = (2+20) + (4+20) = 22 + 24 = 46 \mathrm{cm^2/s}\) The area of the rectangle is increasing at a rate of 46 \(\mathrm{cm^2/s}\) after 20 seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental concept in calculus that helps us understand how functions change over time. It involves calculating the derivative, which represents a function's rate of change. In this problem, we're interested in how the area of a rectangle changes as its dimensions grow over time. By finding the derivative of the area function, we can determine this rate of change—a crucial step to solving related rates problems.

When we differentiate the area function with respect to time, we use slopes to measure how fast the area is expanding. The derivative indicates how the area grows for a tiny change in time; it essentially tells you how one quantity affects another. In our rectangle problem, differentiation allows us to capture how fast the area increases as each side lengthens over time.

This process involves breaking down complex relationships into smaller, manageable components, making it easier to analyze dynamic systems like this expanding rectangle. It’s a key tool in mathematics to study changes and to find solutions to problems, like determining how quickly an area increases when dimensions change.
Product Rule
The product rule is an essential technique used in differentiation when you're dealing with functions that are multiplied together. When calculating the derivative of a product of two functions, you can't merely differentiate each function separately. Instead, you use the product rule to account for changes in both parts of the product.

In mathematical terms, if you have two differentiable functions, say \(u(t)\) and \(v(t)\), their derivative according to the product rule is given by:
\[\frac{d}{dt}[u(t)v(t)] = u(t)\frac{dv}{dt} + v(t)\frac{du}{dt}\]
In our rectangle problem, the area function \(A(t) = (2+t)(4+t)\) represents a product of the length and width functions. As each side increases over time, we apply the product rule to find how the combined product—here, the area—changes.

This rule makes sure we are accounting for the simultaneous change in both the rectangle's length and width. It ensures accuracy by letting us consider the effect of one function changing while the other remains constant at a given instant, thus providing a clear picture of the changes occurring in the system.
Geometry
Geometry plays a crucial role in understanding the shape, size, and properties of figures like rectangles. When dealing with areas, perimeters, volumes, or any measurable aspect of shapes, geometry provides the necessary formulas and insights.

In this exercise, the formula for the area of a rectangle is fundamental: \(A = ext{Length} \times ext{Width}\). This basic principle allows us to compute the area when the dimensions are known.
  • Length: Describes one side of the rectangle
  • Width: Describes the adjacent side
As both dimensions change, our understanding of geometry helps translate physical changes into mathematical ones. After 20 seconds, each side of the rectangle has increased, affecting the overall area.

Geometry not only gives us static formulas but also helps visualize how those formulas apply in dynamic scenarios. Understanding these principles allows us to interpret the changes that occur when dimensions of geometric figures evolve over time.
Time-dependent Functions
Time-dependent functions are essential in modeling scenarios where variables change as time progresses. These functions often depict real-world phenomena, capturing how aspects like size, speed, or growth vary over time.

In our rectangle problem, both the length and width functions of the rectangle are time-dependent. Initially, the dimensions are static: 2 cm by 4 cm. As time passes, these dimensions increase according to the rate of 1 cm/s. Therefore, the functions for length and width become \(2+t\) and \(4+t\) respectively, where \(t\) represents time in seconds.

This directly affects the area function, making it also time-dependent: \(A(t) = (2+t)(4+t)\). Understanding time-dependent functions is crucial because they allow us to predict how a situation evolves as time goes on, providing insights into rates of change and future outcomes.
  • Length function: Dynamic with time (\(2+t\))
  • Width function: Dynamic with time (\(4+t\))
  • Area function: Changes according to both length and width over time
These relationships highlight how interconnected variables adapt over time, offering a comprehensive view of the situation at hand.

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