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Recall that \(f\) is even if \(f(-x)=f(x),\) for all \(x\) in the domain of \(f,\) and \(f\) is odd if \(f(-x)=-f(x),\) for all \(x\) in the domain of \(f\) a. If \(f\) is a differentiable, even function on its domain, determine whether \(f^{\prime}\) is even, odd, or neither. b. If \(f\) is a differentiable, odd function on its domain, determine whether \(f^{\prime}\) is even, odd, or neither.

Short Answer

Expert verified
Answer: If f is a differentiable, even function, its derivative f′ is an odd function. If f is a differentiable, odd function, its derivative f′ is an even function.

Step by step solution

01

Recall the definition of an even function

An even function is defined as \(f(-x) = f(x)\) for all \(x\) in its domain.
02

Apply the definition of a differentiable function

A differentiable function has a derivative at every point in its domain. For our even function \(f\), let's consider its derivative \(f^{\prime}(x)\).
03

Investigate the derivative of the even function

We want to determine if \(f^{\prime}(-x) = f^{\prime}(x)\) (even) or \(f^{\prime}(-x) = -f^{\prime}(x)\) (odd) by analyzing the even function, \(f(-x) = f(x)\), and taking its derivative. Differentiate both sides with respect to \(x\): \(\frac{d}{dx}(f(-x)) = \frac{d}{dx}(f(x))\) Using the chain rule, the left side becomes: \(-f^{\prime}(-x) = f^{\prime}(x)\) Since \(-f^{\prime}(-x) = f^{\prime}(x)\), we can conclude that \(f^{\prime}(x)\) is an odd function. #b. If f is a differentiable, odd function on its domain, determine whether f′ is even, odd, or neither.#
04

Recall the definition of an odd function

An odd function is defined as \(f(-x) = -f(x)\) for all \(x\) in its domain.
05

Apply the definition of a differentiable function

A differentiable function has a derivative at every point in its domain. For our odd function \(f\), let's consider its derivative \(f^{\prime}(x)\).
06

Investigate the derivative of the odd function

We want to determine if \(f^{\prime}(-x) = f^{\prime}(x)\) (even) or \(f^{\prime}(-x) = -f^{\prime}(x)\) (odd) by analyzing the odd function, \(f(-x) = -f(x)\), and taking its derivative. Differentiate both sides with respect to \(x\): \(\frac{d}{dx}(f(-x)) = \frac{d}{dx}(-f(x))\) Using the chain rule, the left side becomes: \(-f^{\prime}(-x) = -f^{\prime}(x)\) Since \(-f^{\prime}(-x) = -f^{\prime}(x)\), we can conclude that \(f^{\prime}(x)\) is an even function.

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