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Why is it not possible to evaluate \(\lim _{x \rightarrow 0} \frac{\sin x}{x}\) by direct substitution?

Short Answer

Expert verified
Answer: Direct substitution cannot be used to evaluate this limit because it results in an indeterminate form, specifically \(\frac{0}{0}\). This means that we need to use another method, such as L'Hôpital's Rule or geometric interpretation, to accurately evaluate the limit.

Step by step solution

01

Attempt Direct Substitution

Attempt to substitute \(x=0\) into the function: $$\lim_{x \rightarrow 0} \frac{\sin x}{x} = \frac{\sin(0)}{0} = \frac{0}{0}$$
02

Identify Indeterminate Form

The attempt to use direct substitution resulted in the indeterminate form \(\frac{0}{0}\). This means that the function cannot be evaluated at \(x=0\) using direct substitution, and we need to use another method.
03

Use of L'Hôpital's Rule or other methods

Since direct substitution results in an indeterminate form, other methods like L'Hôpital's Rule or geometric interpretation can be used to evaluate the limit. In fact, the limit \(\lim_{x \rightarrow 0} \frac{\sin x}{x}\) is a well-known result in calculus, with a limit of \(1\). However, this exercise focuses on why direct substitution is not possible, and we have shown that through encountering the indeterminate form \(\frac{0}{0}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indeterminate Forms
When evaluating limits, sometimes you end up with something called an indeterminate form. This happens when both the numerator and the denominator go to zero, which is often seen as \(\frac{0}{0}\). It's a bit like a math puzzle, where simple arithmetic can't provide the answer. You might also see forms like \(\frac{\infty}{\infty}\), \(\infty - \infty\), or even \(0 \cdot \infty\). These forms tell us that direct calculation won't work, because division by zero isn't defined and infinity isn't a specific number. In our example of \(\lim_{x \rightarrow 0} \frac{\sin x}{x}\), putting zero straight into the equation leads to the \(\frac{0}{0}\) form. This signals that we need to use a different method to find the limit. Fortunately, this "math puzzle" often has a straightforward solution using other techniques.
Direct Substitution
Direct substitution is the go-to method when you first start evaluating limits. It's super simple: just plug the approaching value into the function. If you get a proper number, great! That's your limit. But if you hit an indeterminate form like \(\frac{0}{0}\), direct substitution falls short. In such cases, we have to turn to other methods to find the solution. So, although direct substitution is quick, it's not always the right tool for the job, especially when functions behave unexpectedly around certain points. It’s like trying to fit a square peg in a round hole—sometimes you need a different approach.
L'Hôpital's Rule
L'Hôpital's Rule is a lifesaver for limits involving indeterminate forms. When faced with \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\), it's time for L'Hôpital to step in. This rule says you can take the derivative of the top and the bottom of the fraction separately, then try the limit again. For example, with \(\lim_{x \rightarrow 0} \frac{\sin x}{x}\), direct substitution gives \(\frac{0}{0}\). Applying L'Hôpital's Rule means finding the derivatives of \(\sin x\) and \(x\), which are \(\cos x\) and \(1\) respectively. After applying the rule, the limit becomes \(\lim_{x \rightarrow 0} \frac{\cos x}{1}\), which quickly solves to \(1\). The rule offers a helpful way to solve limits that initially seem unsolvable through basic methods—turning chaos into clarity.
Trigonometric Limits
Trigonometric limits, especially when involving small angles like \(x \rightarrow 0\), often come with special rules or shortcuts. If you've zoomed in on a trigonometric function, the behavior can be surprising due to their oscillatory nature. A classic example is \(\lim_{x \rightarrow 0} \frac{\sin x}{x} = 1\). This isn't just a random fact—it's a fundamental limit in calculus. Visualizing the graph of \(\sin x\) around zero helps you see that the function closely hugs the line \(y=x\), leading naturally to the conclusion of its limit being \(1\). By knowing and understanding a few trigonometric limits, you can easily tackle problems without resorting to more complex algebra or calculus tools.

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