/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Determine the following limits. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine the following limits. $$\lim _{x \rightarrow \infty}\left(3 x^{12}-9 x^{7}\right)$$

Short Answer

Expert verified
Answer: The limit of the given function as x approaches infinity is 3.

Step by step solution

01

Identify the highest power of x in the given function

In the given function, we have two terms: $$3x^{12}$$ and $$-9x^7$$. The highest power of x among these terms is $$x^{12}$$.
02

Divide each term by the highest power of x

To simplify the given function, we will divide each term by $$x^{12}$$. We get: $$\frac{3x^{12}}{x^{12}} - \frac{9x^7}{x^{12}}\text{.}$$
03

Simplify each term

Now, we simplify each term: $$\frac{3x^{12}}{x^{12}} = 3 \quad \text{and} \quad \frac{9x^7}{x^{12}} = \frac{9}{x^5}\text{.}$$ So, the simplified function becomes: $$3 - \frac{9}{x^5}\text{.}$$
04

Determine the limit as x approaches infinity

As x approaches infinity, the term $$\frac{9}{x^5}$$ will approach 0, because the denominator grows faster than the numerator. Thus, we get: $$\lim_{x\to\infty} \left(3 - \frac{9}{x^5}\right) = 3 - 0 = 3\text{.}$$
05

Final Answer

The limit of the given function as x approaches infinity is 3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Limits with a parameter Let \(f(x)=\frac{x^{2}-7 x+12}{x-a}\) a. For what values of \(a,\) if any, does \(\lim _{x \rightarrow a^{+}} f(x)\) equal a finite number? b. For what values of \(a,\) if any, does \(\lim _{x \rightarrow a^{+}} f(x)=\infty ?\) c. For what values of \(a,\) if any, does \(\lim _{x \rightarrow a^{+}} f(x)=-\infty ?\)

The limit at infinity \(\lim _{x \rightarrow \infty} f(x)=L\) means that for any \(\varepsilon>0,\) there exists \(N>0\) such that $$|f(x)-L|<\varepsilon \quad \text { whenever } \quad x>N$$ Use this definition to prove the following statements. $$\lim _{x \rightarrow \infty} \frac{10}{x}=0$$

If a function \(f\) represents a system that varies in time, the existence of \(\lim _{t \rightarrow \infty} f(t)\) means that the system reaches a steady state (or equilibrium). For the following systems, determine if a steady state exists and give the steady-state value. The amount of drug (in milligrams) in the blood after an IV tube is inserted is \(m(t)=200\left(1-2^{-t}\right)\).

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. a. The line \(x=1\) is a vertical asymptote of the function \(f(x)=\frac{x^{2}-7 x+6}{x^{2}-1}.\) b. The line \(x=-1\) is a vertical asymptote of the function \(f(x)=\frac{x^{2}-7 x+6}{x^{2}-1}.\) c. If \(g\) has a vertical asymptote at \(x=1\) and \(\lim _{x \rightarrow 1^{+}} g(x)=\infty\) then \(\lim _{x \rightarrow 1^{-}} g(x)=\infty.\)

Evaluate \(\lim _{x \rightarrow \infty} f(x)\) and \(\lim _{x \rightarrow-\infty} f(x)\). Then state the horizontal asymptote(s) of \(f\). Confirm your findings by plotting \(f\). $$f(x)=\frac{3 e^{x}+e^{-x}}{e^{x}+e^{-x}}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.