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Evaluate the Jacobians \(J(u, v, w)\) for the following transformations. $$u=x-y, v=x-z, w=y+z \quad \text { (Solve for } x, y, \text { and } z \text { first.) }$$

Short Answer

Expert verified
The Jacobian matrix for the given transformation is: $$J(u, v, w) = \begin{bmatrix} \frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ 1 & -1 & 0 \end{bmatrix}$$

Step by step solution

01

Solve the transformation equations for x, y, z

We are given the transformations: $$u=x-y$$ $$v=x-z$$ $$w=y+z$$ Let's solve these equations for \(x, y, z\): From the first two equations, we get: $$x = u+y$$ $$x = v+z$$ By comparing these two expressions for \(x\), we can say $$u+y=v+z$$ Now, we can express \(z\) in terms of \(u,v\) and \(y\) $$z= u+y-v$$ Next, we substitute the value of \(z\) in 3rd equation to get an expression for \(y\) $$w= y+(u+y-v)$$ $$w= y+u+y-v$$ $$w= 2y+u-v$$ Solve for \(y\), we got $$y = \frac{w-u+v}{2}$$ And finally, we substitute the value of \(y\) in expression for \(x\) to find \(x\) $$x = u+\frac{w-u+v}{2}$$ Now we have the expressions for \(x, y, z\): $$x = u+\frac{w-u+v}{2}$$ $$y = \frac{w-u+v}{2}$$ $$z = u+y-v$$
02

Find the partial derivatives

Now we need to compute the partial derivatives \(\frac{\partial x}{\partial u}, \frac{\partial x}{\partial v}, \frac{\partial x}{\partial w}, \frac{\partial y}{\partial u}, \frac{\partial y}{\partial v}, \frac{\partial y}{\partial w}, \frac{\partial z}{\partial u}, \frac{\partial z}{\partial v}, \frac{\partial z}{\partial w}\). We'll do this one by one. For \(x(u,v,w)\), we have $$\frac{\partial x}{\partial u} = 1-\frac{1}{2} = \frac{1}{2}$$ $$\frac{\partial x}{\partial v} = \frac{1}{2}$$ $$\frac{\partial x}{\partial w} = \frac{1}{2}$$ For \(y(u,v,w)\), we have $$\frac{\partial y}{\partial u} = -\frac{1}{2}$$ $$\frac{\partial y}{\partial v} = \frac{1}{2}$$ $$\frac{\partial y}{\partial w} = \frac{1}{2}$$ For \(z(u,v,w)\), we have $$\frac{\partial z}{\partial u} = 1$$ $$\frac{\partial z}{\partial v} = -1$$ $$\frac{\partial z}{\partial w} = 0$$
03

Create the Jacobian matrix \(J(u, v, w)\)

Now we have all the necessary derivatives, so we can construct the \(3 \times 3\) Jacobian matrix: $$J(u, v, w) = \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} & \frac{\partial x}{\partial w} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} & \frac{\partial y}{\partial w} \\ \frac{\partial z}{\partial u} & \frac{\partial z}{\partial v} & \frac{\partial z}{\partial w} \end{bmatrix} = \begin{bmatrix} \frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ 1 & -1 & 0 \end{bmatrix}$$ The Jacobian matrix \(J(u,v,w)\) for the given transformation is: $$J(u, v, w) = \begin{bmatrix} \frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ 1 & -1 & 0 \end{bmatrix}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transformation
In mathematics, a transformation refers to the process of converting one set of variables into another set. This is a fundamental concept across various fields, including geometry, linear algebra, and calculus. Simply put, transformation changes one coordinate system to another. In our exercise, we're looking at transforming the coordinates \(x, y, z\) to new coordinates \(u, v, w\).

Transformations can often simplify complex problems, making them easier to work with. For instance, by using transformations, certain equations or geometrical figures might reveal symmetries or result in simpler expressions. This makes solving systems of equations and analyzing functions more manageable.

Here, the given transformations are:
  • \( u = x - y \)
  • \( v = x - z \)
  • \( w = y + z \)
These equations let us translate or 'transform' the familiar \(x, y, z\) coordinates into a new frame described by \(u, v, w\). Understanding transformations is crucial because they allow us to operate in a new space, which often possesses unique properties that can be leveraged for problem-solving.
Partial Derivatives
In calculus, partial derivatives are a way to show how a multivariable function changes as each individual variable is varied while keeping others constant. Think of them as the slope of the function when you slice through it along one axis.

For the given transformation, partial derivatives help us understand how each of the new coordinates \(u, v, w\) influences the changes in the old coordinates \(x, y, z\). They are represented as \( \frac{\partial x}{\partial u} \), \( \frac{\partial x}{\partial v} \), and similar for the other variables.
  • They guide us in forming the Jacobian matrix, which we will discuss in the next section.
  • Partial derivatives are crucial for finding slopes along specific directions, especially in multi-dimensional spaces.
Using the expressions derived for \(x, y, z\) in terms of \(u, v, w\), we calculated the partial derivatives, such as \( \frac{\partial x}{\partial u} = \frac{1}{2} \) and \( \frac{\partial y}{\partial u} = -\frac{1}{2} \). Recognizing these changes helps to map how inputs influence outputs distinctly along each axis, an essential process when dealing with real-world applications like optimization and in the computations of Jacobians.
Jacobian Matrix
The Jacobian matrix is a powerful tool in calculus, particularly when dealing with multiple variables and their transformations. It's a matrix that contains all the first-order partial derivatives of a vector-valued function. For a function \(f(x, y, z)\), the Jacobian measures how the function changes as the input variables change.

Let's break this down: when you transform variables, you are essentially looking at how a small change in one set of variables (like \(u, v, w\) in our case) affects another set (like \(x, y, z\)). The Jacobian provides a compact way to express these changes using a matrix.

In our exercise, we constructed the Jacobian matrix \(J(u,v,w)\) as follows:
  • \(\begin{bmatrix} \frac{1}{2} & \frac{1}{2} & \frac{1}{2} \end{bmatrix}\) for \(x\)
  • \(\begin{bmatrix} -\frac{1}{2} & \frac{1}{2} & \frac{1}{2} \end{bmatrix}\) for \(y\)
  • \(\begin{bmatrix} 1 & -1 & 0 \end{bmatrix}\) for \(z\)
Matrix \(J(u, v, w)\) simplifies and organizes this multi-variable transformation process. It's essential for analyzing how functions behave around a point and is used in various applications such as optimization, dynamics, and more. Understanding Jacobians can pave the way for advanced study in calculus and differential equations.

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Most popular questions from this chapter

The Jacobian is a magnification (or reduction) factor that relates the area of a small region near the point \((u, v)\) to the area of the image of that region near the point \((x, y)\) a. Suppose \(S\) is a rectangle in the \(u v\) -plane with vertices \(O(0,0)\) \(P(\Delta u, 0),(\Delta u, \Delta v),\) and \(Q(0, \Delta v)\) (see figure). The image of \(S\) under the transformation \(x=g(u, v), y=h(u, v)\) is a region \(R\) in the \(x y\) -plane. Let \(O^{\prime}, P^{\prime},\) and \(Q^{\prime}\) be the images of O, P, and \(Q,\) respectively, in the \(x y\) -plane, where \(O^{\prime}\) \(P^{\prime},\) and \(Q^{\prime}\) do not all lie on the same line. Explain why the coordinates of \(\boldsymbol{O}^{\prime}, \boldsymbol{P}^{\prime}\), and \(Q^{\prime}\) are \((g(0,0), h(0,0))\) \((g(\Delta u, 0), h(\Delta u, 0)),\) and \((g(0, \Delta v), h(0, \Delta v)),\) respectively. b. Use a Taylor series in both variables to show that $$\begin{aligned} &g(\Delta u, 0) \approx g(0,0)+g_{u}(0,0) \Delta u\\\ &g(0, \Delta v) \approx g(0,0)+g_{v}(0,0) \Delta v\\\ &\begin{array}{l} h(\Delta u, 0) \approx h(0,0)+h_{u}(0,0) \Delta u \\ h(0, \Delta v) \approx h(0,0)+h_{v}(0,0) \Delta v \end{array} \end{aligned}$$ where \(g_{u}(0,0)\) is \(\frac{\partial x}{\partial u}\) evaluated at \((0,0),\) with similar meanings for \(g_{v}, h_{u}\) and \(h_{v}\) c. Consider the vectors \(\overrightarrow{O^{\prime} P^{\prime}}\) and \(\overrightarrow{O^{\prime} Q^{\prime}}\) and the parallelogram, two of whose sides are \(\overrightarrow{O^{\prime} P^{\prime}}\) and \(\overrightarrow{O^{\prime} Q^{\prime}}\). Use the cross product to show that the area of the parallelogram is approximately \(|J(u, v)| \Delta u \Delta v\) d. Explain why the ratio of the area of \(R\) to the area of \(S\) is approximately \(|J(u, v)|\)

Let \(R_{1}=\\{(x, y): x \geq 1,1 \leq y \leq 2\\}\) and \(R_{2}=\\{(x, y): 1 \leq x \leq 2, y \geq 1\\} .\) For \(n>1,\) which integral(s) have finite values: \(\iint_{R_{1}} x^{-n} d A\) or \(\iint_{R_{2}} x^{-n} d A ?\)

Use integration to find the volume of the following solids. In each case, choose a convenient coordinate system, find equations for the bounding surfaces, set up a triple integral, and evaluate the integral. Assume that \(a, b, c, r, R,\) and h are positive constants. Find the volume of the cap of a sphere of radius \(R\) with thickness \(h\).

Consider the region \(R\) bounded by three pairs of parallel planes: \(a x+b y=0, a x+b y=1, c x+d z=0\) \(c x+d z=1, e y+f z=0,\) and \(e y+f z=1,\) where \(a, b, c, d, e\) and \(f\) are real numbers. For the purposes of evaluating triple integrals, when do these six planes bound a finite region? Carry out the following steps. a. Find three vectors \(\mathbf{n}_{1}, \mathbf{n}_{2},\) and \(\mathbf{n}_{3}\) each of which is normal to one of the three pairs of planes. b. Show that the three normal vectors lie in a plane if their triple scalar product \(\mathbf{n}_{1} \cdot\left(\mathbf{n}_{2} \times \mathbf{n}_{3}\right)\) is zero. c. Show that the three normal vectors lie in a plane if ade \(+\) bcf \(=0\) d. Assuming \(\mathbf{n}_{1}, \mathbf{n}_{2},\) and \(\mathbf{n}_{3}\) lie in a plane \(P,\) find a vector \(\mathbf{N}\) that is normal to \(P\). Explain why a line in the direction of \(\mathbf{N}\) does not intersect any of the six planes, and thus the six planes do not form a bounded region. e. Consider the change of variables \(u=a x+b y, v=c x+d z\) \(w=e y+f z .\) Show that $$ J(x, y, z)=\frac{\partial(u, v, w)}{\partial(x, y, z)}=-a d e-b c f $$ What is the value of the Jacobian if \(R\) is unbounded?

Evaluate the following integrals using a change of variables of your choice. Sketch the original and new regions of integration, \(R\) and \(S\). \(\iint_{R} x y d A,\) where \(R\) is the region bounded by the hyperbolas \(x y=1\) and \(x y=4,\) and the lines \(y=1\) and \(y=3\)

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