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Evaluate the following limits. $$\lim _{(x, y) \rightarrow(1,-3)}(3 x+4 y-2)$$

Short Answer

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Question: Evaluate the limit as (x, y) approaches (1, -3) for the function f(x, y) = 3x + 4y - 2. Answer: The limit as (x, y) approaches (1, -3) for the function f(x, y) = 3x + 4y - 2 is -11.

Step by step solution

01

Identify the function and the point of interest

We are given the function \(f(x, y) = 3x + 4y - 2\) and we want to find the limit as \((x, y) \rightarrow (1, -3)\).
02

Substitute the point of interest into the function

Substitute \((1, -3)\) into the function \(f(x, y)\): $$f(1, -3) = 3(1) + 4(-3) - 2$$
03

Simplify the expression

Simplify the expression by performing the arithmetic operations: $$f(1, -3) = 3 - 12 - 2$$ $$f(1, -3) = -11$$
04

Evaluate the limit

Because the function \(f(x, y)\) is continuous in its domain and it is defined at \((1, -3)\), evaluating the limit is the same as substituting these values into the function. So, the limit is: $$\lim _{(x, y) \rightarrow(1,-3)}(3 x+4 y-2) = f(1, -3) = -11$$

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