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Solve the following pairs of equations for the vectors \(\mathbf{u}\) and \(\mathbf{v} .\) Assume \(\mathbf{i}=\langle 1,0\rangle\) and \(\mathbf{j}=\langle 0,1\rangle\) $$2 \mathbf{u}+3 \mathbf{v}=\mathbf{i}, \mathbf{u}-\mathbf{v}=\mathbf{j}$$

Short Answer

Expert verified
The unknown vectors \(\mathbf{u}\) and \(\mathbf{v}\) are \(\mathbf{u} = \langle\frac{1}{5}, \frac{3}{5}\rangle\) and \(\mathbf{v} = \langle\frac{1}{5}, -\frac{2}{5}\rangle\).

Step by step solution

01

Rewrite the equation in coordinate form

Since \(\mathbf{i}=\langle 1,0\rangle\) and \(\mathbf{j}=\langle 0,1\rangle\), we can rewrite the given equations as: $$2 \mathbf{u} + 3 \mathbf{v} = \langle 1, 0\rangle \quad \text{and} \quad \mathbf{u} - \mathbf{v} = \langle 0, 1\rangle$$
02

Solve the first equation for \(\mathbf{u}\)

From the second equation, we can express \(\mathbf{u}\) in terms of \(\mathbf{v}\): $$\mathbf{u} = \mathbf{v} + \langle 0, 1\rangle$$
03

Substitute the expression for \(\mathbf{u}\) in the first equation

Now, we can substitute the expression for \(\mathbf{u}\) from step 2 in the first equation: $$2(\mathbf{v} + \langle 0, 1\rangle) + 3 \mathbf{v} = \langle 1, 0\rangle$$
04

Solve for \(\mathbf{v}\)

We can now solve this equation for \(\mathbf{v}\) by simplifying: $$2\mathbf{v} + \langle 0, 2\rangle + 3\mathbf{v} = \langle 1, 0\rangle$$ $$5\mathbf{v} + \langle 0, 2\rangle = \langle 1, 0\rangle$$ $$5\mathbf{v} = \langle 1, -2\rangle$$ $$\mathbf{v} = \frac{1}{5}\langle 1, -2\rangle = \langle \frac{1}{5}, -\frac{2}{5}\rangle$$
05

Solve for \(\mathbf{u}\)

Now, we can substitute the value of \(\mathbf{v}\) in the expression for \(\mathbf{u}\) from step 2: $$\mathbf{u} = \langle\frac{1}{5}, -\frac{2}{5}\rangle + \langle 0, 1\rangle = \langle\frac{1}{5}, \frac{3}{5}\rangle$$
06

Give the final solution

Finally, we have found the values of \(\mathbf{u}\) and \(\mathbf{v}\) that satisfy the given equations: $$\mathbf{u} = \langle\frac{1}{5}, \frac{3}{5}\rangle \quad \text{and} \quad \mathbf{v} = \langle\frac{1}{5}, -\frac{2}{5}\rangle$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Equations
Understanding vector equations is crucial because they allow us to express relationships between vectors just like regular algebraic equations do with scalars. In vector equations, vectors are often represented in bold, such as \( \mathbf{u} \) and \( \mathbf{v} \) in our exercise.

A vector equation can involve operations like addition, subtraction, or scalar multiplication of vectors, resulting in another vector. For example, in the exercise, we have the equation:

\[ 2 \mathbf{u} + 3 \mathbf{v} = \mathbf{i} \]

Here, the equation describes a linear combination of vectors \( \mathbf{u} \) and \( \mathbf{v} \) that equals vector \( \mathbf{i} \). Solving vector equations often involves breaking the vectors into components, and treating each component individually. This will transform the vector equation into a pair of algebraic equations, which are much easier to solve.
Coordinate Vectors
When dealing with vectors, it can be useful to express them in terms of their components, referred to as coordinate vectors. This involves specifying each vector in a list of numbers, corresponding to different dimensions or axes, such as \( \langle x, y \rangle \) for 2D vectors.

In our exercise, the vectors \( \mathbf{i} \) and \( \mathbf{j} \) serve as the basis vectors:

  • \( \mathbf{i} = \langle 1, 0 \rangle \)
  • \( \mathbf{j} = \langle 0, 1 \rangle \)

These are unit vectors, pointing along the x and y axes, respectively. A vector \( \mathbf{a} \) can be expressed using these as \( \mathbf{a} = a_1 \mathbf{i} + a_2 \mathbf{j} \), where \( a_1 \) and \( a_2 \) are scalars.

By assigning coordinates to vectors, it becomes straightforward to perform operations like addition and subtraction, as in the step-by-step solution where the equations are rewritten in coordinate form. This method simplifies solving equations by translating them into problems involving numbers that can be managed via linear algebraic manipulations.
Linear Combinations
A linear combination involves creating a new vector by adding together a set of vectors multiplied by specific scalars. In the context of our exercise, the equation \( 2 \mathbf{u} + 3 \mathbf{v} = \mathbf{i} \) is a linear combination of the vectors \( \mathbf{u} \) and \( \mathbf{v} \).

  • The number '2' is the scalar multiplying vector \( \mathbf{u} \).
  • The number '3' scales vector \( \mathbf{v} \).

Finding solutions for such linear combinations usually requires expressing one vector in terms of the others, as shown in the step-by-step solution where \( \mathbf{u} \) was expressed in terms of \( \mathbf{v} \).

Linear combinations are foundational in vector spaces, where they help determine vectors' dependencies and span. By understanding how vectors can combine, we gain insights into their interactions, enabling us to solve complex equations and understand geometric interpretations.

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Most popular questions from this chapter

Given a fixed vector \(\mathbf{v},\) there is an infinite set of vectors \(\mathbf{u}\) with the same value of proj\(_{\mathbf{v}} \mathbf{u}\). Let \(\mathbf{v}=\langle 0,0,1\rangle .\) Give a description of all position vectors \(\mathbf{u}\) such that \(\operatorname{proj}_{\mathbf{v}} \mathbf{u}=\operatorname{proj}_{\mathbf{v}}\langle 1,2,3\rangle\).

An object on an inclined plane does not slide provided the component of the object's weight parallel to the plane \(\left|\mathbf{W}_{\text {par }}\right|\) is less than or equal to the magnitude of the opposing frictional force \(\left|\mathbf{F}_{\mathrm{f}}\right|\). The magnitude of the frictional force, in turn, is proportional to the component of the object's weight perpendicular to the plane \(\left|\mathbf{W}_{\text {perp }}\right|\) (see figure). The constant of proportionality is the coefficient of static friction, \(\mu\) a. Suppose a 100 -lb block rests on a plane that is tilted at an angle of \(\theta=20^{\circ}\) to the horizontal. Find \(\left|\mathbf{W}_{\text {parl }}\right|\) and \(\left|\mathbf{W}_{\text {perp }}\right|\) b. The condition for the block not sliding is \(\left|\mathbf{W}_{\mathrm{par}}\right| \leq \mu\left|\mathbf{W}_{\text {perp }}\right| .\) If \(\mu=0.65,\) does the block slide? c. What is the critical angle above which the block slides with \(\mu=0.65 ?\)

For the following vectors u and \(\mathbf{v}\) express u as the sum \(\mathbf{u}=\mathbf{p}+\mathbf{n},\) where \(\mathbf{p}\) is parallel to \(\mathbf{v}\) and \(\mathbf{n}\) is orthogonal to \(\mathbf{v}\). \(\mathbf{u}=\langle-1,2,3\rangle, \mathbf{v}=\langle 2,1,1\rangle\)

Evaluate the following limits. $$\lim _{t \rightarrow 2}\left(\frac{t}{t^{2}+1} \mathbf{i}-4 e^{-t} \sin \pi t \mathbf{j}+\frac{1}{\sqrt{4 t+1}} \mathbf{k}\right)$$

Find the points (if they exist) at which the following planes and curves intersect. $$y=1 ; \mathbf{r}(t)=\langle 10 \cos t, 2 \sin t, 1\rangle, \text { for } 0 \leq t \leq 2 \pi$$

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