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Evaluate \(\langle a, b, a\rangle \times\langle b, a, b\rangle .\) For what nonzero values of \(a\) and \(b\) are the vectors \(\langle a, b, a\rangle\) and \(\langle b, a, b\rangle\) parallel?

Short Answer

Expert verified
Answer: The vectors ⟨a, b, a⟩ and ⟨b, a, b⟩ are parallel when a = b or a = -b for nonzero values of a and b.

Step by step solution

01

Finding the cross product of the two vectors

\(\langle a, b, a\rangle \times \langle b, a, b\rangle\) can be calculated by finding the determinant of the matrix formed by unit direction vectors \(\) and the provided vectors. $$ \begin{bmatrix} i & j & k \\ a & b & a \\ b & a & b \end{bmatrix} $$ Now we can find the determinant by expanding across the first row.
02

Calculate the determinant

Next, calculate the determinant of the matrix: $$ cross\_product = i \cdot \det\begin{bmatrix} b & a \\ a & b \end{bmatrix} - j \cdot \det\begin{bmatrix} a & a \\ b & b \end{bmatrix} + k \cdot \det\begin{bmatrix} a & b \\ b & a \end{bmatrix} $$ Now, calculate the three determinants and simplify the resulting cross product vector: $$ cross\_product = i(b^2 - a^2) - j(0) + k(a^2 - b^2) $$ So the cross product of the two given vectors is: $$ \langle b^2 - a^2, 0, a^2 - b^2\rangle $$
03

Determine when the vectors are parallel

Vectors are parallel if their cross product is a zero vector, which means all components are equal to zero. $$ \langle b^2 - a^2, 0, a^2 - b^2\rangle = \langle 0, 0, 0\rangle $$ For the two given nonzero vectors to be parallel, the following conditions must be satisfied: $$ b^2 - a^2 = 0 $$ $$ a^2 - b^2 = 0 $$ Solving these equations simultaneously gives us: $$ a^2 = b^2 $$ Or $$ a = b \space \mathrm{or} \space a = -b $$ So the vectors \(\langle a, b, a \rangle\) and \(\langle b, a, b \rangle\) are parallel when \(a = b\) or \(a = -b\) for nonzero values of \(a\) and \(b\).

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Most popular questions from this chapter

Let \(\mathbf{r}(t)=\langle f(t), g(t), h(t)\rangle\). a. Assume that \(\lim _{t \rightarrow a} \mathbf{r}(t)=\mathbf{L}=\left\langle L_{1}, L_{2}, L_{3}\right\rangle,\) which means that $$\begin{aligned} &\lim _{t \rightarrow a}|\mathbf{r}(t)-\mathbf{L}|=0 . \text { Prove that }\\\ &\lim _{t \rightarrow a} f(t)=L_{1}, \quad \lim _{t \rightarrow a} g(t)=L_{2}, \text { and } \lim _{t \rightarrow a} h(t)=L_{3}. \end{aligned}$$ $$\begin{aligned} &\text { b. Assume that } \lim _{t \rightarrow a} f(t)=L_{1}, \lim _{t \rightarrow a} g(t)=L_{2}, \text { and }\\\ &\lim _{t \rightarrow a} h(t)=L_{3} . \text { Prove that } \lim _{t \rightarrow a} \mathbf{r}(t)=\mathbf{L}=\left\langle L_{1}, L_{2}, L_{3},\right\rangle\\\ &\text { which means that } \lim _{t \rightarrow a}|\mathbf{r}(t)-\mathbf{L}|=0. \end{aligned}$$

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