/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Given an acceleration vector, in... [FREE SOLUTION] | 91Ó°ÊÓ

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Given an acceleration vector, initial velocity $\left\langle u_{0}, v_{0}\right\rangle,\( and initial position \)\left\langle x_{0}, y_{0}\right\rangle,\( find the velocity and position vectors, for \)t \geq 0$. $$\mathbf{a}(t)=\langle\cos t, 2 \sin t\rangle,\left\langle u_{0}, v_{0}\right\rangle=\langle 0,1\rangle,\left\langle x_{0}, y_{0}\right\rangle=\langle 1,0\rangle$$

Short Answer

Expert verified
The velocity vector is given by \(\mathbf{v}(t) = \left\langle \sin t, -2\cos t +1 \right\rangle\) and the position vector is given by \(\mathbf{r}(t) = \left\langle -\cos t + 1, -2\sin t + t \right\rangle\) for \(t \geq 0\).

Step by step solution

01

To find the velocity vector, we need to integrate the given acceleration vector with respect to time. We have $$\mathbf{a}(t) = \left\langle \cos t, 2\sin t\right\rangle$$ To find the velocity vector \(\mathbf{v}(t)\), we need to integrate components of the acceleration vector separately: $$\mathbf{v}(t) = \left\langle \int \cos t \, dt, \int 2\sin t \, dt\right\rangle$$ #Step 2: Determine the constants of integration for the velocity vector#

We found the expression for the velocity vector without the constants of integration. Now, we need to use the initial velocity vector to determine the constants of integration. The initial velocity vector is ´\(\langle 0, 1 \rangle\). When \(t=0\): $$\mathbf{v}(0) = \left\langle \int_0^0 \cos t \, dt + C_1, \int_0^0 2\sin t \, dt + C_2\right\rangle = \langle 0,1\rangle$$ From this, we can determine \(C_1\) and \(C_2\), which are both 0. #Step 3: Express the complete velocity vector as a function of time#
02

Considering that both constants of integration are 0, our velocity vector becomes: $$\mathbf{v}(t) = \left\langle \int \cos t \, dt, \int 2\sin t \, dt\right\rangle = \left\langle \sin t, -2\cos t + 1\right\rangle$$ #Step 4: Integrate the velocity vector to find the position vector#

Now that we have the velocity vector, we need to integrate it to find the position vector \(\mathbf{r}(t)\). We can integrate components of the velocity vector separately: $$\mathbf{r}(t) = \left\langle \int \sin t \, dt, \int (-2\cos t + 1) \, dt\right\rangle$$ #Step 5: Determine the constants of integration for the position vector#
03

Similarly, as we did for the velocity vector, we need to determine the constants of integration for the position vector. The initial position vector is \(\langle 1, 0 \rangle\). When \(t=0\): $$\mathbf{r}(0) = \left\langle \int_0^0 \sin t \, dt + D_1, \int_0^0 (-2\cos t + 1) \, dt + D_2\right\rangle = \langle 1, 0\rangle$$ From this, we can determine \(D_1 = 1\) and \(D_2 = 0\). #Step 6: Express the complete position vector as a function of time#

Considering the values for the constants of integration, our position vector becomes: $$\mathbf{r}(t) = \left\langle \int \sin t \, dt + 1, \int (-2\cos t + 1)\,dt\right\rangle = \left\langle -\cos t+1, -2\sin t+t\right\rangle$$ Therefore, the velocity vector is given by \(\mathbf{v}(t) = \left\langle \sin t, -2\cos t +1 \right\rangle\) and the position vector is given by \(\mathbf{r}(t) = \left\langle -\cos t + 1, -2\sin t + t \right\rangle\) for \(t \geq 0\).

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