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Arc length of polar curves Find the length of the following polar curves. The complete circle \(r=a \sin \theta,\) where \(a>0\)

Short Answer

Expert verified
Answer: The length of the polar curve \(r = a\sin\theta\) for a complete circle is \(L = a\pi\).

Step by step solution

01

Determine the range of \(\theta\)

Observe that \(r(\theta) = a\sin\theta\). We need to find the interval of \(\theta\) that covers the full circle. Since \(r = a\sin\theta\), the range of values of \(r\) is from \(0\) at \(\theta = 0\) to \(a\) at \(\theta = \frac{\pi}{2}\), because \(\sin(\frac{\pi}{2}) =1\). This means that \(\theta\) covers the positive side of the circle from \(0\) to \(\pi/2\). Now, let's check the negative side. If we set \(\theta'\) as the angle from the other side of the circle, we have \(r(\theta') = a\sin(2\pi - \theta')\). Hence \(-r(\theta') = -a\sin(2\pi-\theta') = a\sin(\theta')\), which means that \(\theta'\) covers the negative side of the circle from \(\pi/2\) to \(\pi\). Thus, we can see that \(\theta\) ranges from \(0\) to \(\pi\) for a complete circle.
02

Find the derivative of \(r(\theta)\)

Now, we need to find the derivative of \(r(\theta)\) with respect to \(\theta\). We know that \(r(\theta) = a\sin\theta\). Taking the derivative with respect to \(\theta\), we get $$\frac{dr}{d\theta} = a\cos\theta.$$
03

Apply the polar arc length formula

We can now apply the arc length formula for polar coordinates: $$L = \int_0^\pi \sqrt{r^2 + \left(\frac{dr}{d\theta}\right)^2}d\theta$$ Substituting \(r = a \sin\theta\) and \(\frac{dr}{d\theta} = a\cos\theta\) into the formula: $$L = \int_0^\pi \sqrt{(a\sin\theta)^2 + (a\cos\theta)^2}d\theta$$ $$L = \int_0^\pi \sqrt{a^2(\sin^2\theta +\cos^2\theta)}d\theta$$ Since we know \(\sin^2\theta+ \cos^2\theta = 1\), we can simplify further: $$L = \int_0^\pi a d\theta$$ Now, integrate with respect to \(\theta\): $$L = a\theta\Big|_0^\pi = a(\pi - 0) = a\pi$$ Thus, the length of the polar curve \(r=a\sin\theta\) is \(L = a\pi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arc Length
In the context of polar curves, finding the arc length involves measuring the distance along the curve defined by a polar equation. An easy way to picture this is like unraveling a piece of string laid along the curve, then measuring how long that string is.
The formula to find the arc length \( L \) of a polar curve given by \( r = f(\theta) \) over a range of \( \theta \) is:
  • \( L = \int_{\alpha}^{\beta} \sqrt{r^2 + \left(\frac{dr}{d\theta}\right)^2} \, d\theta \)
Here, \( \alpha \) and \( \beta \) are the starting and ending angles for \( \theta \). The formula takes into account both the radial distance \( r \) and its rate of change, \( \frac{dr}{d\theta} \).
For our example, we simplified the formula by substituting known trigonometric identities, eventually reducing to \( L = a\pi \), showcasing the elegance of mathematics.
Derivative
Derivatives play a crucial role in analyzing polar curves, primarily to understand how the curve changes as the angle \( \theta \) varies. When you find the derivative of a polar curve given by \( r = a \sin\theta \), you determine how the radius changes as the angle increases.
For a curve \( r = f(\theta) \), the derivative \( \frac{dr}{d\theta} \) is essential for computing the arc length as seen before.In our case, with \( r(\theta) = a\sin\theta \), the derivative is computed as:
  • \( \frac{dr}{d\theta} = a\cos\theta \)
This output gives us the rate at which \( r \) changes, which is important not only for arc length calculations but also for studying curve behavior, like curvature and direction.
Polar Coordinates
Polar coordinates are a way of expressing positions on a plane through an angle and a radius, offering an alternative to the usual Cartesian coordinates \((x, y)\). In polar coordinates, every point is specified by \((r, \theta)\), where \( r \) is the distance from the origin, and \( \theta \) is the angle from the positive x-axis.
This system is particularly helpful in cases involving curves that aren't conveniently expressed with rectangular equations, like spirals or circles.
For example, the polar equation \( r = a \sin \theta \) represents a circle rather than a sine wave, showing a beautiful symmetry achievable only in polar forms. By applying ranges to \( \theta \), like from 0 to \( \pi \), you describe the entire curve, illustrating how polar equations can succinctly capture the essence of curved shapes.
Integration
Integration in the context of polar curves is about accumulating the effect of tiny changes (infinitesimals) across the curve to get a total measure, like length or area.
For arc length, you perform an integration with respect to the angle \( \theta \), considering the changes in distance and direction along the curve. The integration formula is derived from calculus principles but accommodates the polar coordinate system.In our example where \( r = a\sin\theta \), the integral:
  • \( \int_0^\pi a\, d\theta \)
was evaluated to find the total arc length \( L \). The integration simplifies due to the identity \( \sin^2\theta + \cos^2\theta = 1 \), providing a shortcut to the result. This step highlights the power of integration to condense complex shapes into meaningful numerical values, reflecting how calculus serves as a bridge between algebraic expressions and geometric interpretation.

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Most popular questions from this chapter

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