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For each point \(P(x, y, z)\) given below. let \(A(x, y, 0), B(x, 0, z),\) and \(C(0, y, z)\) be points in the \(x y-x z^{-},\) and yz-planes, respectively. Plot and label the points \(A, B, C,\) and \(P\) in \(R^{3}\). a. \(P(-3,2,4)\) b. \(P(4,-2,-3) \) c. \(P(-2,-4,-3)\)

Short Answer

Expert verified
Answer: A(-3, 2, 0), B(-3, 0, 4), C(0, 2, 4) 2. What are the coordinates of points A, B, and C for the given point P(4, -2, -3)? Answer: A(4, -2, 0), B(4, 0, -3), C(0, -2, -3) 3. What are the coordinates of points A, B, and C for the given point P(-2, -4, -3)? Answer: A(-2, -4, 0), B(-2, 0, -3), C(0, -4, -3)

Step by step solution

01

a. Point A

For point A(x, y, 0), we substitute the given coordinates of P(-3,2,4) into A. A(-3, 2, 0)
02

a. Point B

For point B(x, 0, z), we substitute the given coordinates of P(-3,2,4) into B. B(-3, 0, 4)
03

a. Point C

For point C(0, y, z), we substitute the given coordinates of P(-3,2,4) into C. C(0, 2, 4)
04

b. Point A

For point A(x, y, 0), we substitute the given coordinates of P(4, -2, -3) into A. A(4, -2, 0)
05

b. Point B

For point B(x, 0, z), we substitute the given coordinates of P(4, -2, -3) into B. B(4, 0, -3)
06

b. Point C

For point C(0, y, z), we substitute the given coordinates of P(4, -2, -3) into C. C(0, -2, -3)
07

c. Point A

For point A(x, y, 0), we substitute the given coordinates of P(-2, -4, -3) into A. A(-2, -4, 0)
08

c. Point B

For point B(x, 0, z), we substitute the given coordinates of P(-2, -4, -3) into B. B(-2, 0, -3)
09

c. Point C

For point C(0, y, z), we substitute the given coordinates of P(-2, -4, -3) into C. C(0, -4, -3) To plot these points in R^3, utilize a 3-dimensional graphing tool or graphing software. Plot each set of coordinates on the respective x, y, and z axes, and label points A, B, and C accordingly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Plotting Points in 3D
Plotting points in 3D space can seem daunting at first, but with a clear understanding of the axes and coordinate systems, it becomes much more straightforward. In a 3D coordinate system, we have three axes: the x-axis, y-axis, and z-axis.
Each point is defined by a triplet \(x, y, z\), where 'x' is the position along the x-axis, 'y' is along the y-axis, and 'z' is along the z-axis.
To accurately plot a point, you will need to move along these axes from the origin, which is \(0,0,0\).
  • Consider the point \(P(-3,2,4)\). To plot it, you start at the origin (0,0,0).
  • From there, move -3 units along the x-axis, then 2 units parallel to the y-axis, and finally 4 units parallel to the z-axis.
  • Mark the point and label it 'P'.
Visualizing these points requires imagining or using a graphing software to see how points align across these three dimensions. For practice, try mapping these in various software tools to solidify your understanding.
3D Planes
Three-dimensional planes are subsets of space defined by the combination of axes. These are critical when we deal with points like A(x, y, 0), B(x, 0, z), and C(0, y, z) based on a given point P(x, y, z).
Each of these points lies on a specific plane:
  • Point A is on the xy-plane because the z-coordinate is zero.
  • Point B is on the xz-plane as the y-coordinate is zero.
  • Point C is on the yz-plane since the x-coordinate is zero.
The characteristic equation of a plane provides a geometric interpretation of these points. Remember that a plane is simply a flat, two-dimensional surface extended infinitely within three-dimensional space. Explore how changing coordinates affect the position of these points on their respective planes to gain a deeper understanding of 3D geometry.
Transformations in 3D
Transformations in 3D geometry involve adjusting the position or dimensions of objects in a three-dimensional space. Some common transformations include translations, rotations, and scaling.
When transforming points:
  • Translations change a point's location but maintain its orientation and size.
  • Rotations pivot the point or object around a specific axis, altering its orientation.
  • Scaling adjusts the size of the object relative to a center point, changing its dimensions without impacting its angles.
Understanding transformations is crucial in various fields such as computer graphics, engineering, and physics. For instance, if you have a point P(x, y, z) and you want to translate it by (a, b, c), the new point would be (x+a, y+b, z+c). Practice these transformations with different coordinates to see the effects vividly in the 3D space.
Graphing Software for Mathematics
Using graphing software can greatly enhance your understanding of 3D coordinate geometry. These tools provide visual insights into how points, lines, and planes relate to each other in three-dimensional space.
Software like GeoGebra, Desmos, or MATLAB offers user-friendly interfaces for experimenting with 3D graphs:
  • Input coordinates to see precise placement of points in space with tools like GeoGebra.
  • With Desmos, explore dynamic transformations directly in a web browser.
  • MATLAB offers robust capabilities for complex mathematical modeling and 3D visualizations.
These resources not only assist in visualizing mathematical concepts but also provide a platform to test and verify calculations. Spend time with these tools to elevate your comprehension of 3D geometry, allowing you to solve problems more efficiently.

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Most popular questions from this chapter

Let \(D\) be a solid heat-conducting cube formed by the planes \(x=0, x=1, y=0, y=1, z=0,\) and \(z=1 .\) The heat flow at every point of \(D\) is given by the constant vector \(\mathbf{Q}=\langle 0,2,1\rangle\) a. Through which faces of \(D\) does \(Q\) point into \(D ?\) b. Through which faces of \(D\) does \(\mathbf{Q}\) point out of \(D ?\) c. On which faces of \(D\) is \(Q\) tangential to \(D\) (pointing neither in nor out of \(D\) )? d. Find the scalar component of \(\mathbf{Q}\) normal to the face \(x=0\). e. Find the scalar component of \(\mathbf{Q}\) normal to the face \(z=1\). f. Find the scalar component of \(\mathbf{Q}\) normal to the face \(y=0\).

Assume that \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{w}\) are vectors in \(\mathrm{R}^{3}\) that form the sides of a triangle (see figure). Use the following steps to prove that the medians intersect at a point that divides each median in a 2: 1 ratio. The proof does not use a coordinate system. a. Show that \(\mathbf{u}+\mathbf{v}+\mathbf{w}=\mathbf{0}\) b. Let \(\mathbf{M}_{1}\) be the median vector from the midpoint of \(\mathbf{u}\) to the opposite vertex. Define \(\mathbf{M}_{2}\) and \(\mathbf{M}_{3}\) similarly. Using the geometry of vector addition show that \(\mathbf{M}_{1}=\mathbf{u} / 2+\mathbf{v} .\) Find analogous expressions for \(\mathbf{M}_{2}\) and \(\mathbf{M}_{3}\) c. Let \(a, b,\) and \(c\) be the vectors from \(O\) to the points one-third of the way along \(\mathbf{M}_{1}, \mathbf{M}_{2},\) and \(\mathbf{M}_{3},\) respectively. Show that \(\mathbf{a}=\mathbf{b}=\mathbf{c}=(\mathbf{u}-\mathbf{w}) / 3\) d. Conclude that the medians intersect at a point that divides each median in a 2: 1 ratio.

A 500-kg load hangs from three cables of equal length that are anchored at the points \((-2,0,0),(1, \sqrt{3}, 0),\) and \((1,-\sqrt{3}, 0) .\) The load is located at \((0,0,-2 \sqrt{3}) .\) Find the vectors describing the forces on the cables due to the load.

An object moves along an ellipse given by the function \(\mathbf{r}(t)=\langle a \cos t, b \sin t\rangle,\) for \(0 \leq t \leq 2 \pi,\) where \(a > 0\) and \(b > 0\) a. Find the velocity and speed of the object in terms of \(a\) and \(b\) for \(0 \leq t \leq 2 \pi\) b. With \(a=1\) and \(b=6,\) graph the speed function, for \(0 \leq t \leq 2 \pi .\) Mark the points on the trajectory at which the speed is a minimum and a maximum. c. Is it true that the object speeds up along the flattest (straightest) parts of the trajectory and slows down where the curves are sharpest? d. For general \(a\) and \(b\), find the ratio of the maximum speed to the minimum speed on the ellipse (in terms of \(a\) and \(b\) ).

\(\mathbb{R}^{2}\) Consider the vectors \(\mathbf{I}=\langle 1 / \sqrt{2}, 1 / \sqrt{2}\rangle\) and \(\mathbf{J}=\langle-1 / \sqrt{2}, 1 / \sqrt{2}\rangle\). Show that \(\mathbf{I}\) and \(\mathbf{J}\) are orthogonal unit vectors.

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