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Consider the following position functions. a. Find the velocity and speed of the object. b. Find the acceleration of the object. $$\mathbf{r}(t)=\left\langle t^{2}+3, t^{2}+10, \frac{1}{2} t^{2}\right\rangle, \text { for } t \geq 0$$

Short Answer

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Question: Given the position function for an object, \(\mathbf{r}(t)=\left\langle t^{2}+3, t^{2}+10, \frac{1}{2}t^{2}\right\rangle\), find: a. The velocity and speed of the object. b. The acceleration of the object. Answer: a. Velocity: \(\mathbf{v}(t)=\left\langle 2t, 2t, t\right\rangle\), speed: \(| \mathbf{v}(t) |=3t \text{ for } t \geq 0\) b. Acceleration: \(\mathbf{a}(t)=\left\langle 2, 2, 1\right\rangle\)

Step by step solution

01

Calculate the velocity vector

First, we need to find the velocity vector, which is the derivative of the position vector with respect to time. The position vector is given by \(\mathbf{r}(t)=\left\langle t^{2}+3, t^{2}+10, \frac{1}{2}t^{2}\right\rangle\). Taking the derivative of each component with respect to time gives us the velocity vector: $$\mathbf{v}(t)=\frac{d\mathbf{r}}{dt}=\left\langle \frac{d(t^2 + 3)}{dt}, \frac{d(t^2 + 10)}{dt}, \frac{d(\frac{1}{2}t^2)}{dt} \right\rangle$$ $$\mathbf{v}(t)=\left\langle 2t, 2t, t\right\rangle$$
02

Calculate the speed

Next, we need to find the speed, which is the magnitude of the velocity vector. The magnitude of a vector \(\mathbf{v}=\left\langle a, b, c \right\rangle\) is given by \(|\mathbf{v}|=\sqrt{a^2+b^2+c^2}\). So, the speed of the object is: $$|\mathbf{v}|=\sqrt{(2t)^2+(2t)^2+(t)^2}=\sqrt{4t^2+4t^2+t^2}=\sqrt{9t^2}=3t \text{ for } t \geq 0$$
03

Calculate the acceleration vector

Now, we need to find the acceleration vector, which is the derivative of the velocity vector with respect to time. The velocity vector is \(\mathbf{v}(t)=\left\langle 2t, 2t, t\right\rangle\). Taking the derivative of each component with respect to time gives us the acceleration vector: $$\mathbf{a}(t)=\frac{d\mathbf{v}}{dt}=\left\langle \frac{d(2t)}{dt}, \frac{d(2t)}{dt}, \frac{d(t)}{dt} \right\rangle$$ $$\mathbf{a}(t)=\left\langle 2, 2, 1\right\rangle$$ So, the velocity and speed of the object are given by: a. Velocity: \(\mathbf{v}(t)=\left\langle 2t, 2t, t\right\rangle\), speed: \(| \mathbf{v}(t) |=3t \text{ for } t \geq 0\) b. Acceleration: \(\mathbf{a}(t)=\left\langle 2, 2, 1\right\rangle\)

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Most popular questions from this chapter

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