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Find equations of the following lines. The line through (0,0,1) parallel to the \(x\) -axis

Short Answer

Expert verified
Answer: The parametric equation of the line is \(x=t, \ y=0, \ z=1\).

Step by step solution

01

Find the direction vector

Since the line is parallel to the x-axis, its direction vector will have the same direction as the x-axis. The x-axis has the direction vector (1,0,0).
02

Use the point-slope form of the equation of a line

The point-slope form of the equation of a line in 3D space is: $$ \frac{x - x_0}{a} = \frac{y - y_0}{b} = \frac{z - z_0}{c} $$ Where (x0, y0, z0) is the point through which the line passes, and (a, b, c) is the direction vector.
03

Plug in the values and write the equation of the line

Given the point (0,0,1) and the direction vector (1,0,0), the point-slope form of the equation becomes: $$ \frac{x - 0}{1} = \frac{y - 0}{0} = \frac{z - 1}{0} $$
04

Finalize the equation of the line

It's clear from the equation above that the second and third parts, $$\frac{y-0}{0}$$ and $$\frac{z-1}{0}$$, is undefined. But we can represent the line using parametric form, where x, y, and z are written as functions of a parameter t. So, the equation of the line can be written as: $$ x = 1t = t, \: y = 0, \: z = 1 $$ The parametric equation of the line through (0,0,1) parallel to the x-axis is: \(x=t, \ y=0, \ z=1\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equations
Parametric equations are a way to define a curve or line by expressing the coordinates of points on the curve as functions of a parameter, typically denoted as \( t \). This approach provides a flexible means to describe the motion of objects through space and can be particularly useful in three-dimensional (3D) coordinate systems.

In the context of 3D space, a parametric equation of a line is formulated by:
  • Representing the \( x \)-coordinate as a function of \( t \) (i.e., \( x = x_0 + at \))
  • Representing the \( y \)-coordinate as a function of \( t \) (i.e., \( y = y_0 + bt \))
  • Representing the \( z \)-coordinate as a function of \( t \) (i.e., \( z = z_0 + ct \))
Here, \( (x_0, y_0, z_0) \) is a point on the line, and \( (a, b, c) \) is the direction vector. This technique is helpful for visualizing lines as paths traced out by points that move through 3D space. The parameter \( t \) can be varied to explore different points on the path, which makes it ideal for animations and simulations.
Direction Vector
A direction vector is a crucial component of the parametric equations. It defines the "direction" in which a line extends through 3D space. Direction vectors are essential because they determine the slope or the rate at which the line ascends, descends, or maintains its level.

The direction vector is often represented as \( \langle a, b, c \rangle \), where each component corresponds to the vector's influence along the x, y, and z axes, respectively.

For instance, if a line is described as parallel to the x-axis, its direction vector would be \( (1, 0, 0) \). This suggests that the line progresses positively along the x-axis, while maintaining static positions along the y and z axes.

Understanding how to determine and utilize direction vectors empowers you to describe lines in 3D spaces accurately, paving the way for realistic modeling and analysis of physical phenomena.
Point-Slope Form
The point-slope form of a line is a useful equation for describing lines in 3D systems. It allows us to build on known information, such as a point on the line and its direction, to derive the equation comprehensively.

The standard form is expressed as:\[\frac{x - x_0}{a} = \frac{y - y_0}{b} = \frac{z - z_0}{c}\] where \( (x_0, y_0, z_0) \) is a known point on the line, and \( (a, b, c) \) constitutes the direction vector.

This form equates fractional changes in \( x, y, \) and \( z \) coordinates to maintain the line's direction. However, if any component of the direction vector is zero, it represents a special case, typically requiring reinterpretation as a horizontal or vertical trajectory.

By setting real values into this form, you can precisely define or reconfigure any line in a 3D environment, making it a valuable tool for illustrating geometric problems.

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Most popular questions from this chapter

For the following vectors u and \(\mathbf{v}\) express u as the sum \(\mathbf{u}=\mathbf{p}+\mathbf{n},\) where \(\mathbf{p}\) is parallel to \(\mathbf{v}\) and \(\mathbf{n}\) is orthogonal to \(\mathbf{v}\). \(\mathbf{u}=\langle 4,3,0\rangle, \mathbf{v}=\langle 1,1,1\rangle\)

Assume that \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{w}\) are vectors in \(\mathrm{R}^{3}\) that form the sides of a triangle (see figure). Use the following steps to prove that the medians intersect at a point that divides each median in a 2: 1 ratio. The proof does not use a coordinate system. a. Show that \(\mathbf{u}+\mathbf{v}+\mathbf{w}=\mathbf{0}\) b. Let \(\mathbf{M}_{1}\) be the median vector from the midpoint of \(\mathbf{u}\) to the opposite vertex. Define \(\mathbf{M}_{2}\) and \(\mathbf{M}_{3}\) similarly. Using the geometry of vector addition show that \(\mathbf{M}_{1}=\mathbf{u} / 2+\mathbf{v} .\) Find analogous expressions for \(\mathbf{M}_{2}\) and \(\mathbf{M}_{3}\) c. Let \(a, b,\) and \(c\) be the vectors from \(O\) to the points one-third of the way along \(\mathbf{M}_{1}, \mathbf{M}_{2},\) and \(\mathbf{M}_{3},\) respectively. Show that \(\mathbf{a}=\mathbf{b}=\mathbf{c}=(\mathbf{u}-\mathbf{w}) / 3\) d. Conclude that the medians intersect at a point that divides each median in a 2: 1 ratio.

Evaluate the following limits. $$\lim _{t \rightarrow 0}\left(\frac{\sin t}{t} \mathbf{i}-\frac{e^{t}-t-1}{t} \mathbf{j}+\frac{\cos t+t^{2} / 2-1}{t^{2}} \mathbf{k}\right)$$

An object moves along an ellipse given by the function \(\mathbf{r}(t)=\langle a \cos t, b \sin t\rangle,\) for \(0 \leq t \leq 2 \pi,\) where \(a > 0\) and \(b > 0\) a. Find the velocity and speed of the object in terms of \(a\) and \(b\) for \(0 \leq t \leq 2 \pi\) b. With \(a=1\) and \(b=6,\) graph the speed function, for \(0 \leq t \leq 2 \pi .\) Mark the points on the trajectory at which the speed is a minimum and a maximum. c. Is it true that the object speeds up along the flattest (straightest) parts of the trajectory and slows down where the curves are sharpest? d. For general \(a\) and \(b\), find the ratio of the maximum speed to the minimum speed on the ellipse (in terms of \(a\) and \(b\) ).

The definition \(\mathbf{u} \cdot \mathbf{v}=|\mathbf{u}||\mathbf{v}| \cos \theta\) implies that \(|\mathbf{u} \cdot \mathbf{v}| \leq|\mathbf{u}||\mathbf{v}|(\text {because}|\cos \theta| \leq 1) .\) This inequality, known as the Cauchy-Schwarz Inequality, holds in any number of dimensions and has many consequences. Verify that the Cauchy-Schwarz Inequality holds for \(\mathbf{u}=\langle 3,-5,6\rangle\) and \(\mathbf{v}=\langle-8,3,1\rangle\).

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