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Give two alternative representations of the points in polar coordinates. $$\left(2, \frac{7 \pi}{4}\right)$$

Short Answer

Expert verified
Answer: The two alternative representations of the polar coordinates \((2, \frac{7 \pi}{4})\) are \(\left(2, \frac{15 \pi}{4}\right)\) and \(\left(2, -\frac{1 \pi}{4}\right)\).

Step by step solution

01

Identify the given polar coordinates

The given polar coordinates are \((r, \theta) = \left(2, \frac{7 \pi}{4}\right)\).
02

Add or subtract multiples of \(2\pi\) to the angle

We can represent the same point in polar coordinates by either adding or subtracting multiples of \(2\pi\) to the angle. So first, let's add \(2\pi\) to the angle: $$\frac{7 \pi}{4} + 2\pi = \frac{7 \pi}{4} + \frac{8 \pi}{4} = \frac{15 \pi}{4}$$ Now, let's subtract \(2\pi\) from the angle: $$\frac{7 \pi}{4} - 2\pi = \frac{7 \pi}{4} - \frac{8 \pi}{4} = -\frac{1 \pi}{4}$$
03

Write the alternative polar coordinates

Based on our calculations in Step 2, we have two alternative representations of the given polar coordinates: 1. \((r, \theta) = \left(2, \frac{15 \pi}{4}\right)\) 2. \((r, \theta) = \left(2, -\frac{1 \pi}{4}\right)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alternative Representations
Polar coordinates help us localize a point on a plane by considering its distance from a reference point and an angle from a reference direction. They are denoted as \((r, \theta)\), where \(r\) is the radial distance from the origin and \(\theta\) represents the angle.

The beauty of polar coordinates lies in their flexibility. A single point on a plane can have multiple polar representations. By altering the angle \(\theta\) while maintaining the radial distance \(r\), one can find "alternative representations" of a point.

For instance, the polar coordinates \(\left(2, \frac{7 \pi}{4}\right)\) can also be expressed as \(\left(2, \frac{15 \pi}{4}\right)\) and \(\left(2, -\frac{1 \pi}{4}\right)\). These alternative representations are crucial when dealing with problems in trigonometry and calculus, as they offer flexibility in calculations and interpretations.
Angle Adjustment
One fundamental concept when working with polar coordinates is adjusting the angle \(\theta\). This involves adding or subtracting full rotations, which amount to \(2\pi\), to simplify or change the angle without altering the point's location. It's like traversing around a circle. A complete trip around equals adding or subtracting \(2\pi\) radians, but you still end up at the same spot. This flexibility allows us to express a point in multiple ways by modifying \(\theta\). For example:
  • Adding \(2\pi\) to \(\frac{7\pi}{4}\):
    \(\frac{7\pi}{4} + 2\pi = \frac{7\pi}{4} + \frac{8\pi}{4} = \frac{15\pi}{4}\)

  • Subtracting \(2\pi\) from \(\frac{7\pi}{4}\):
    \(\frac{7\pi}{4} - 2\pi = \frac{7\pi}{4} - \frac{8\pi}{4} = -\frac{1\pi}{4}\)
Here, adjustments are carried out to find other equivalent angles representing the same polar point.
Trigonometry
Trigonometry plays a significant role in polar coordinates. It bridges the gap between polar and Cartesian coordinates and helps in finding angles and distances.

In polar coordinates, the angle \(\theta\) is pivotal as it defines the direction of the point from the origin, while trigonometric functions help calculate corresponding points in Cartesian coordinates. For any point \((r, \theta)\):
  • The x-coordinate is found using: \(x = r \cos(\theta)\)
  • The y-coordinate is found using: \(y = r \sin(\theta)\)

Understanding these conversions is vital when switching between systems or solving problems involving rotations, where different representations might simplify calculations.

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Most popular questions from this chapter

Water flows in a shallow semicircular channel with inner and outer radii of \(1 \mathrm{m}\) and \(2 \mathrm{m}\) (see figure). At a point \(P(r, \theta)\) in the channel, the flow is in the tangential direction (counterclockwise along circles), and it depends only on \(r\), the distance from the center of the semicircles. a. Express the region formed by the channel as a set in polar coordinates. b. Express the inflow and outflow regions of the channel as sets in polar coordinates. c. Suppose the tangential velocity of the water in \(\mathrm{m} / \mathrm{s}\) is given by \(v(r)=10 r,\) for \(1 \leq r \leq 2 .\) Is the velocity greater at \(\left(1.5, \frac{\pi}{4}\right)\) or \(\left(1.2, \frac{3 \pi}{4}\right) ?\) Explain. d. Suppose the tangential velocity of the water is given by \(v(r)=\frac{20}{r},\) for \(1 \leq r \leq 2 .\) Is the velocity greater at \(\left(1.8, \frac{\pi}{6}\right)\) or \(\left(1.3, \frac{2 \pi}{3}\right) ?\) Explain. e. The total amount of water that flows through the channel (across a cross section of the channel \(\theta=\theta_{0}\) ) is proportional to \(\int_{1}^{2} v(r) d r .\) Is the total flow through the channel greater for the flow in part (c) or (d)?

The region bounded by the parabola \(y=a x^{2}\) and the horizontal line \(y=h\) is revolved about the \(y\) -axis to generate a solid bounded by a surface called a paraboloid (where \(a > 0\) and \(h > 0\) ). Show that the volume of the solid is \(\frac{3}{2}\) the volume of the cone with the same base and vertex.

Use a graphing utility to graph the hyperbolas \(r=\frac{e}{1+e \cos \theta},\) for \(e=1.1,1.3,1.5,1.7\) and 2 on the same set of axes. Explain how the shapes of the curves vary as \(e\) changes.

Suppose that two hyperbolas with eccentricities \(e\) and \(E\) have perpendicular major axes and share a set of asymptotes. Show that \(e^{-2}+E^{-2}=1\)

Sketch the graph of the following parabolas. Specify the location of the focus and the equation of the directrix. Use a graphing utility to check your work. $$x^{2}=12 y$$

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