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Graph of a linear function Find and graph the linear function that passes through the points (2,-3) and (5,0)

Short Answer

Expert verified
Answer: The equation of the line passing through the points (2, -3) and (5, 0) is y = 1x - 5. Its graph is a straight line going through the points (2, -3) and (5, 0).

Step by step solution

01

Find the slope (m)

Use the slope formula: m = (y2 - y1) / (x2 - x1) Let (x1, y1) = (2, -3) and (x2, y2) = (5, 0) m = (0 - (-3)) / (5 - 2) m = 3/3 m = 1
02

Substitute the slope (m) and one of the points (x, y) into the equation y = mx + b

Let's use the point (2, -3) -3 = 1 * 2 + b
03

Solve for b

We have -3 = 1 * 2 + b b = -3 - 2 b = -5
04

Write the linear equation using the values of m and b

We know that m = 1 and b = -5. Plugging these values into the equation y = mx + b, we have y = 1x - 5
05

Graph the linear function y = 1x - 5

To graph the function, we'll need to plot at least two points. Since we are given two points already, (2, -3) and (5, 0), we don't need to find any more points. Plot the points (2, -3) and (5, 0) on the graph and draw a straight line passing through those points. The graph of the linear function y = 1x - 5 will be a straight line going through these points.

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