/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Find the slope of the tangent li... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the slope of the tangent line to the polar curve at the given point. $$r=3 \sin \theta \text { at } \theta=\frac{\pi}{2}$$

Short Answer

Expert verified
The slope of the tangent line to the polar curve at the point \(\theta = \frac{\pi}{2}\) is 0.

Step by step solution

01

Find derivative

Differentiate \(r=3\sin(\theta)\) with respect to \(\theta. Then, r' = 3\cos(\theta)\)
02

Find value of r and r'

Substitute \(\theta = \frac{\pi}{2}\) into \(r\), and into \(r'\). we get r = 3, r' = 0.
03

Calculate slope

Then, we can find the slope of the tangent line by solving the equation \(\tan(\theta + \frac{\pi}{2}) = -\frac{r'}{r}\). Substituting the known values, we get \(\tan(\pi) = -0= 0\). Hence the slope of the line is 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Polar coordinates are a way to describe the position of a point in a plane using the distance from a reference point and the angle from a reference direction. In polar coordinates, we often use the symbols \( (r, \theta) \), where \( r \) is the radial distance from the origin (or pole) and \( \theta \) is the angular parameter measured in radians.
In this exercise, we have a polar curve described by \( r=3\sin \theta \). Here, the value of \( r \) depends on the angle \( \theta \), and it varies as \( \theta \) changes. This particular function traces out a circle when fully plotted.
Polar coordinates are especially useful when dealing with problems exhibiting circular or rotational symmetry, allowing for more straightforward calculations and a clear visual representation in terms of angles and radii.
Derivatives
Derivatives are fundamental tools in calculus allowing us to understand the rate at which things change. In the context of polar coordinates, taking the derivative of a polar function like \( r = 3\sin \theta \) involves differentiating with respect to \( \theta \).
  • The derivative of \( r \) with respect to \( \theta \), noted as \( r' \), tells us how the radius changes as the angle changes.
  • In this exercise, \( r' = 3\cos \theta \) is the derivative.
To find the slope of a tangent line at a particular point, say when \( \theta = \frac{\pi}{2} \), you substitute this value into the derivative to find \( r' \) at that point. Understanding derivatives in polar coordinates helps us find tangents and analyze curves.
Trigonometric Functions
Trigonometric functions, including sine and cosine, are crucial in relating angles to sides of right triangles, and they play a central role in polar coordinates. The function \( \sin \theta \) is periodic and oscillates between -1 and 1, dictating the value of \( r \) when used in polar equations like \( r = 3\sin \theta \).
In this problem, \( \theta = \frac{\pi}{2} \) leads to \( \sin \left( \frac{\pi}{2} \right) = 1 \), resulting in \( r = 3 \). Trigonometric identities and properties are valuable as they help in simplifying the function and making sense of the curve's behavior.
The tangent line at any point on a polar curve can also involve trigonometric functions to express its slope effectively. Here, the relation becomes clear in solutions where the horizontal slope or other characteristics depend on these foundational trigonometric values.

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Most popular questions from this chapter

Show that a celestial object can incorrectly appear to be moving faster than the speed of light. An observer stands at the origin and tracks the horizontal movement of the object in exercises 57 and \(58 .\) As computed in exercise \(58,\) light received at time \(T\) was emitted by the object at time \(t,\) where \(T=t+L(t) .\) Similarly, light received at time \(T+\Delta T\) was emitted at time \(t+d t\) where typically \(d t \neq \Delta T .\) The apparent \(x\) -coordinate of the object at time \(T\) is \(x_{a}(T)=x(t) .\) The apparent horizontal speed of the object at time \(T\) as measured by the observer is \(h(T)=\lim _{\Delta T \rightarrow 0} \frac{x_{a}(T+\Delta T)-x_{a}(T)}{\Delta T} .\) Tracing back to time \(t\) show that \(h(t)=\lim _{d t \rightarrow 0} \frac{x(t+d t)-x(t)}{\Delta T}=\frac{v \sin \theta}{T^{\prime}(t)}=\frac{v \sin \theta}{1+L^{\prime}(t)}\)

If the polar curve \(r=f(\theta), a \leq \theta \leq b,\) has length \(L,\) show that \(r=c f(\theta), a \leq \theta \leq b,\) has length \(|c| L\) for any constant \(c\).

Find parametric equations for the path traced out by a specific point on a circle of radius \(r\) rolling from left to right at a constant speed \(v>r .\) Assume that the point starts at \((r, r)\) at time \(t=0 .\) (Hint: First, find parametric equations for the center of the circle. Then, add on parametric equations for the point going around the center of the circle.) Find the minimum and maximum speeds of the point and the locations where each occurs. Graph the curve for \(v=3\) and \(r=2 .\) This curve is called a cycloid.

In exercises find the slopes of the tangent lines to the given curves at the indicated points. $$\left\\{\begin{array}{l} x=t^{3}-t \\ y=t^{4}-5 t^{2}+4 \end{array} \quad \text { (a) } t=-1, \text { (b) } t=1, \text { (c) }(0,4)\right.$$

If a hyperbolic mirror is in the shape of the left half of \(\frac{x^{2}}{8}-y^{2}=1,\) to which point will light rays following the path \(y=c(x+3)\) reflect?

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