/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Determine convergence or diverge... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine convergence or divergence of the series. $$\sum_{k=1}^{\infty} \frac{e^{1 / k}+1}{k^{3}}$$

Short Answer

Expert verified
Therefore, the original series \( \sum_{k=1}^{\infty} \frac{e^{1 / k}+1}{k^{3}} \) is convergent.

Step by step solution

01

Apply the Limit Comparison Test

Choose a simpler series to compare with, in this case we can choose \( B_k = \frac{1}{k^{3}} \). The next step is to find the limit of the ratio between our original series \( A_k = \frac{e^{1 / k} + 1}{k^{3}} \) and the chosen series \( B_k \) as k approaches infinity.
02

Calculate the limit

This limit is given by \( \lim_{k→∞} \frac{A_k}{B_k} = \lim_{k→∞} \frac{\frac{e^{1 / k}+1}{k^{3}}}{\frac{1}{k^{3}}} = \lim_{k→∞} e^{1 / k} + 1 \). As \( k \) approaches infinity, \( 1/k \) approaches 0, hence \( e^{1 / k} + 1 \) approaches \( e^{0} + 1 = 2 \).
03

Evaluate the limit

Since the limit \( 2 \) is finite and positive, by the rule of the Limit Comparison Test, \( ∑A_k \) and \( ∑B_k \) have same behavior. Therefore the given series \( ∑A_k = ∑ \frac{e^{1 / k}+1}{k^{3}} \) will converge if \( ∑B_k = ∑ \frac{1}{k^{3}} \) converges.
04

Compare with p-series

The series \( ∑ \frac{1}{k^{3}} \) is a p-series where \( p=3 \) and since \( p>1 \), such a p-series will always converge.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Comparison Test
When we are given two series and need to determine if they converge or diverge, the limit comparison test can be very useful. This test entails selecting a known simpler series that we assume behaves similarly to our target series. In our example exercise, the series we want to check is \(\sum \frac{e^{1/k} + 1}{k^{3}}\). We compared it with \(\sum \frac{1}{k^{3}}\), a well-known series for which the nature is established.To apply the limit comparison test, we calculate the limit \(\lim_{k\to\infty} \frac{A_k}{B_k}\). If this limit exists as a positive and finite number, it tells us that both series \(\sum A_k\) and \(\sum B_k\) will either converge or diverge together. This method is advantageous because it provides a straightforward mechanism to assess convergence by referencing the behavior of known series.
P-Series
A p-series is defined as the series \(\sum \frac{1}{k^p}\), where \(p\) is a constant. It is a fundamental type of series in calculus because it easily helps us understand whether certain types of series converge.
  • If \(p > 1\), the p-series converges.
  • If \(p \leq 1\), the p-series diverges.
In the example solution, we noted that \(\sum \frac{1}{k^{3}}\) is a p-series with \(p = 3\). Here, \(p > 1\), indicating convergence. This property makes p-series a crucial benchmark when employing the limit comparison test, as they offer a clear criterion for convergence or divergence.
Convergence Criteria
Convergence criteria refer to the rules and tests utilized to determine whether an infinite series converges to a finite value. The convergence of a series means that as we add more terms indefinitely, the total approaches a specific number. Several tests are available besides the limit comparison test, each suited to different situations:
  • Ratio Test: Often applied when the series terms have factorials or exponential elements.
  • Root Test: Utilized when the terms are raised to the power affecting convergence.
  • Integral Test: Applied when the series terms are continuous, positive, and decreasing.
For our exercise, the limit comparison test was chosen because it provides a direct way to compare with the well-known p-series. Establishing the behavior of a series using recognized convergence criteria aids in avoiding complex calculations.
Infinite Series
An infinite series is the sum of an infinite sequence of terms. Understanding whether it converges or diverges is pivotal in calculus.
  • Convergent Series: These series sum up to a finite value. As you keep adding the terms, you will get closer to a specific number.
  • Divergent Series: These series do not sum up to a finite number. Adding terms will continuously increase the sum without it approaching any defined limit.
The challenge with infinite series is grasping their behavior as more terms are included. We solve this by using tests like the limit comparison test to simplify the analysis. Through such tests, we can categorize a diverse range of series, aiding us in recognizing whether they will converge to a specific value or not.

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